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TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

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Presentation on theme: "TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand."— Presentation transcript:

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2 TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You will then be taken to the post-quiz. CLICK TO CONTINUE

3 One mole of an element, such as solid sulfur, contains 6.022 x 10 23 sulfur atoms. One mole of the liquid diatomic element bromine contains 6.022 x 10 23 bromine molecules. One mole of a gaseous compound like carbon dioxide contains 6.022 x 10 23 carbon dioxide molecules. CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

4 One mole of sulfur has a mass of 32.066 grams. One mole of bromine has a mass of 159.808 grams. One mole of carbon dioxide has a mass of 44.010 grams. CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

5 At room temperature and pressure: one mole of solid sulfur has a volume of approximately sixteen cubic centimeters; one mole of bromine has a volume of fifty one cubic centimeters; one mole of carbon dioxide has a volume of twenty thousand cubic centimeter. CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

6 the formula of sulfur atoms is S, the atomic weight of sulfur is 32.066, and so one mole of sulfur atoms has a mass of 32.066 grams; LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

7 the formula of bromine molecules is Br 2, the molecular weight of bromine is twice the atomic weight of bromine, that is, two times 79.904 which is 159.808, and so one mole of bromine has a mass of 159.808 grams;

8 the formula of carbon dioxide molecules is CO 2, the molecular weight of carbon dioxide is the atomic weight of carbon plus twice the atomic weight of oxygen, that is, 12.011 plus two times 15.9994 which is 44.010, and so one mole of carbon dioxide has a mass of 44.010 grams. CLICK TO CONTINUE

9 1.Convert 30 g carbon to moles. The formula of carbon is C and its atomic weight is 12.011, therefore one mole of carbon has a mass of 12.011 grams. CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

10 mass (g) carbon  moles carbon CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 30 g C to mol.)

11 30 g C 1 12.011 x _________ mole C g C 30 mole C 12.011 = 2.5 mol C CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 30 g C to mol.)

12 2. Convert 3.5 liters of ammonia at S.T.P. to moles.

13 At S.T.P., one mole of gaseous ammonia, NH 3, has a volume of 22.414 liters. volume (L) ammonia  moles ammonia CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 3.5 L NH 3 at S.T.P. to mol.)

14 3.5 L NH 3 x 3.5 mol NH 3 22.414 = 0.16 mol NH 3 ___________ mol NH 3 L NH 3 1 22.414 CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 3.5 L NH 3 at S.T.P. to mol.)

15 3. How many moles of glucose are in 10 mL of a 0.5 molar aqueous solution? The unit molar, M, is defined as the number of moles of solute dissolved in one liter of solution. This solution contains 0.5 moles glucose per one liter of solution.

16 volume (mL) solution  volume (L) solution  moles solvent CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?)

17 10 mL solutionx 1 1000 or 10 mL solution x 1 L 10 3 mL or 10 mL solution x 10 -3 L 1 mL ______ L mL CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?)

18 10 mL solution x 1 L 1000 mL 10 mL solution x 1 L 10 3 mL 10 mL solution x 10 -3 L 1 mL or CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY x mol glucose L solution x mol glucose L solution x mol glucose L solution (# mol glucose in 10 mL 0.5 M soln?) 0.5 1 0.5 1 0.5 1

19 10 mL solution x 1 L x 0.5 mol glucose 1000 mL 1 L solution or 10 mL solution x 1 L x 0.5 mol glucose 10 3 mL 1 L solution or 10 mL solution x 10 -3 L x 0.5 mol glucose 1 mL 1 L solution CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?)

20 LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) CLICK TO CONTINUE 10 x 0.5 mol glucose 1000 or 10 x 0.5 mol glucose 10 3 or 10 x 10 -3 x 0.5 mol glucose = 0.005 or 5 x 10 -3 mol glucose

21 4. How many atoms are present in 4.0 moles of phosphine, PH 3 ?

22 Each molecule of phosphine contains four atoms (one phosphorus, three hydrogens.) moles phosphine  molecules phosphine  atoms CLICK TO CONTINUE (# atoms in 4.0 mol PH 3 ?)

23 4.0 mol PH 3 x _____________________ molecules PH 3 mol PH 3 6.02 x 10 23 1 x atoms molecule PH 3 CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY 4141 (# atoms in 4.0 mol PH 3 ?)

24 4.0 mol PH 3 x 6.02 x 10 23 molecules PH 3 1 mol PH 3 x 4 atoms 1 molecules PH 3 4.0 x 6.02 x 10 23 x 4 atoms = 9.6 x 10 24 atoms CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# atoms in 4.0 mol PH 3 ?) ___________________

25 5. How many electrons are lost by ionization of 0.65 moles of calcium?

26 When calcium ionizes each atom loses two electrons and becomes Ca 2+. moles calcium  atoms calcium  electrons CLICK TO CONTINUE (# electrons lost by 0.65 mol Ca?)

27 x electrons atoms Ca 0.65 mol Cax __________________ atoms Ca mol Ca 6.02 x 10 23 1 2121 CLICK TO CONTINUE LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# electrons lost by 0.65 mol Ca?)

28 0.65 mol Ca x 6.02 x 10 23 atoms Ca 1 mol Ca x2 electrons 1 atoms Ca 0.65 x 6.02 x 10 23 x 2 electrons = 7.8 x 10 23 electrons END OF TUTORIAL LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# electrons lost by 0.65 mol Ca?) CLICK TO CONTINUE

29 RETURN TO TUTORIAL GO TO POST-QUIZ OR


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