Lateral Area, Surface Area and Volume Honors Geometry Lateral Area, Surface Area and Volume
Prisms - definitions A PRISM is any object with two parallel congruent bases with lateral sides that are parallelograms. In this case, the two pink sides are the bases. In this case, the two blue sides are the bases. In this case, the two yellow sides are the bases. The bases are not always on the top and bottom! In the next figure, the bases are the front and the back, because they are the parallel congruent sides. In this case, the two blue sides are the bases. In this case, the two blue sides are the bases.
Prisms are named by the shape of their bases. Naming Prisms Prisms are named by the shape of their bases. Hexagonal Prism Triangular Prism Rectangular Prism Square Prism
Right and Oblique Prisms A right PRISM has the sides perpendicular to the bases. An oblique PRISM has sides that are NOT perpendicular to the bases. Right Prism Oblique Prism
Cylinders A CYLINDER is a special case of a prism where the two parallel sides (bases) are circles. A cylinder can be thought of as a circular prism. A right cylinder has its side perpendicular to its bases. An oblique cylinder has its side NOT perpendicular to its bases.
Lateral Area of a Prism Lateral Area (LA) is the area of the side(s) of the object not including the bases. x y z z x y In this case, the LA = (x + y + x + y) z, but x + y + x + y = 2x + 2y. This happens to be the perimeter of the base (P). So, the LA of a right prism is given by LA = Ph.
Lateral Area of a Cylinder I like to think of the LA of a cylinder as measuring the area of the label of a soup can. If you cut down the dotted line and peel the label off and lay it out flat, it is a rectangle. The base of the rectangle is the circumference of the base and the height of the rectangle is the height of the cylinder. h r Circumference Height Therefore, LA of a cylinder is given by LA = Ch. Since circumference is to a circle as perimeter is to a polygon, this just a variation of LA = Ph.
Surface (Total) Area of a Prism The Surface area of a Prism is the sum of the area of ALL of the sides. It is also the LA plus the area of the two bases. Since, however the two bases are congruent, the surface area of a right prism (if B is the area of a base) is given by SA = LA + 2B
Example 1 Find the Surface Area LA = Ph; SA = LA + 2B LA = Ph; P = 2(12cm) + 2(10cm) = 44cm; h = 8cm LA = (44cm)(8cm) = 352cm2 B = (12cm)(10cm) = 120cm2; so 2B = 2(120cm2) = 240cm2 SA = LA + 2B = 352cm2 + 240cm2 = 592cm2
Example 2 Find the Surface Area LA = Ph; SA = LA + 2B LA = Ph; P = 15 in. + 12 in. + 9 in. = 36 in.; h = 13 in. LA = (36 in.)(13 in.) = 468 in.2 B = 1/2(12 in.)(9 in.) = 54 in.2; so 2B = 2(54 in.2) = 108 in.2 SA = LA + 2B = 468 in.2 + 108 in.2 = 576 in.2
Surface Area of a Cylinder The Surface Area of a Cylinder is much like that of a Prism. It the LA + the area of the 2 bases or (since the bases are congruent), LA + twice the area of a base (B). SA = Ch + 2B
Example 3 Find the Surface Area LA = Ch; SA = LA + 2B LA = Ch; C = 2π(8 ft.) = 16π ft. = 50.27 ft.; h = 12 ft. LA = (50.27 ft.)(12 ft.) = 603.24 ft.2 B = π(8ft.)2 = 64π ft.2 = 201.06 ft.2; so 2B = 2(201.06 ft.2) = 402.12 ft.2 SA = LA + 2B = 603.24 ft.2 + 402.12 ft.2 = 1005.36 ft.2
Lateral Area and Surface Area Assignment Lateral Area and Surface Area all
Dog - PRISM
Volume of a Prism is merely the area of a base (B) times the height. Unit Cube Volume of a Prism is merely the area of a base (B) times the height. V = Bh Base
Example 4 Find the Volume V = Bh B = (12cm)(10cm) = 120cm2 h = 8cm V = (120cm2)(8cm) = 960cm3
Example 5 Find the Volume V = Bh B = 1/2(12in)(9in) = 54in2 h = 13in. V = (54in2)(13in) = 702in3
Volume of a Cylinder Like a prism, the volume of a Cylinder is the area of a base times its height. V = Bh
Example 6 Find the Volume V = Bh B = π(8ft)2 = 64π ft2 h = 12 ft V = (64π ft2)(12 ft) = 768π ft2 = 2412.74ft2
Assignment Volume - all
For pyramids and cones V = 1/3Bh Triangular Pyramid Square or Rectangular Pyramid Cone For pyramids and cones V = 1/3Bh
Example 7 Find the Volume V = 1/3Bh B = (6mm)2 = 36mm2 V = 1/3 (36mm2) (6mm) = 72mm3
Example 8 Find the Volume V = 1/3Bh B = 1/2(5cm)(8cm) = 20cm2 h = 6cm V = 1/3 (20cm2)(6cm) = 40cm3
Example 9 Find the Volume 15 cm V = 1/3(81π)15 9 cm V = 405π cm3
Pyramids and Cones - all Assignment Pyramids and Cones - all
Spheres r SA = 4πr2 V = 4/3πr3
Example 10 Find the Surface Area SA = 4πr2 SA = 4π(7cm)2 SA = 196πcm2
Example 11 Find the Volume V = 4/3πr3 V = 4/3π(12cm)3 V = 2304πcm3
Assignment Spheres - all