Solving Linear Equations

Slides:



Advertisements
Similar presentations
Learn to solve equations that have variables on both sides.
Advertisements

ONE STEP EQUATIONS.
Solving Absolute-Value Equations
Solve two-step equations.
SOLVING EQUATIONS AND EXPANDING BRACKETS
Solve Multi-step Equations
Solve two-step equations.
5Min 5-4 1) Evaluate 3 × (4 + 7) – 5 × 4. 2) Evaluate × 5 3) Evaluate 13 squared. 4) Evaluate 9 cubed. Warm Up.
Inverse Operations Operation Inverse Operation
Daily Quiz - Simplify the expression, then create your own realistic scenario for the final expression.
Algebra Solving Equations October 2006 ©RSH.
One step equations Add Subtract Multiply Divide Addition X + 5 = -9 X = X = X = X = X = 2.
Involving One Operation
Solving Linear Equations Rule 7 ‑ 1: We can perform any mathematical operation on one side of an equation, provided we perform the same operation on the.
REVIEW Inverse Operations
Solving 2-step equations ax + b = c. Keep it balanced Just like when solving a one- step equation keep it balanced. Just like when solving a one- step.
To Start: 10 Points.
ALGEBRAIC EQUATIONS. EQUATIONS AND SOLUTIONS  A correct equation is like a balance scale.  In order to determine if a given value for a variable is.
2-2 Solving Two-Step Equations. Goal: To isolate the variable How do you do this : Use Inverse Operation (Opposite) 1. do all Addition or Subtraction.
 SWBAT solve two-step algebraic equations.  Two-Step Equations are equations that require two- steps to solve.  You will ADD or SUBTRACT and then.
Solving Equations with Brackets or Fractions. Single Bracket Solve 3(x + 4) = 24 3x + 12 = 24 3x + 12 – 12 = x = 12 x = 4 Multiply brackets out.
Solving Equations II Lesson After completing this lesson, you will be able to say: I can solve one-variable equations containing multiplication.
Solving Equations Using Multiplication and Division Algebra 1 Section 3.2a.
Big Ideas 3.4 Solving Equations Using Multiplication and Division
Created by S. Koch Solving One-Step Equations.
Solving Linear Equations with a variable on only one side of the equation.
Equations – Success if you can do these 3x = 64x + 2 = 3x + 7 x/4 = 25x – 3 = 7 + 3x x + 3 = 173(x + 2) = 12 x – 4 = 134(x + 5) = 32 3x + 4 = 253(2x –
One step equations Add Subtract Multiply Divide  When we solve an equation, our goal is to isolate our variable by using our inverse operations.  What.
Solving Equations Inverse operations. INVERSE = Opposite If I am solving an equation using inverses operations, I am solving it using opposite signs.
Equations. Objective: solve linear equations with a variable on one side.
One Step Equations and Inequalities Review
Solving 1-Step Equations 2 An Equation is Like a Balance.
Use Inverse Matrices to Solve Linear Systems Objectives 1.To find the inverse of a square matrix 2.To solve a matrix equation using inverses 3.To solve.
Problem Solving with Two-Step Equations Objective: Learn to use more than one inverse operation to solve an equation.
Solving 2 step equations. Two step equations have addition or subtraction and multiply or divide 3x + 1 = 10 3x + 1 = 10 4y + 2 = 10 4y + 2 = 10 2b +
Lesson 7.4 Solving Multiplication and Division Equations 2/3/10.
SOLVING ONE-STEP EQUATIONS Integrated Math I Objective: Solve one-step linear equations in one variable with strategies involving inverse operations and.
3. 3 Solving Equations Using Addition or Subtraction 3
Students will use inverse operations to solve one-step equations.
Students will use inverse operations to solve one-step equations.
Students will use inverse operations to solve one-step equations.
Solving Two-Step Equations
Equations with Fractions
ONE STEP EQUATIONS.
ONE STEP EQUATIONS.
Solving Literal Equations
Solving Two and Multi Step Equations
Solving One-Step Equations
Solving Inequalities.
Students will use inverse operations to solve one-step equations.
Students will use inverse operations to solve one-step equations.
Lesson 5.1 How do you write fractions as decimals?
In this tutorial you will be able to follow along step by step on how to solve basic operations involving fractions.
Linear Equations Doctor Shildneck.
1.3 Equations with variables on both sides
Solving one- and two-step equations
Subtract the same value on each side
Students will use inverse operations to solve one-step equations.
Equations – Success if you can do these
Learn to solve 2-step equations
Math-7 NOTES What are Two-Step Equations??
Solve Multi-step Equations
5a + 3 = 2a a = 2a a = 2a + 9 5a – 2a = 9 3a = 9 a = 9
Math-7 NOTES 1) 3x = 15 2) 4x = 16 Multiplication equations:
ONE STEP EQUATIONS WHAT?!?!.
Solving Linear Equations
ONE STEP EQUATIONS.
Students will use inverse operations to solve one-step equations.
ONE STEP EQUATIONS.
Multi-Step equations with fractions and decimals
Presentation transcript:

Solving Linear Equations Which level would you like to study? Level 5 Level 6 Level 7 Worksheet

Level 5 Objective: Be able to solve linear equations with an unknown on one side.

4a = 24 a = 24 4 = 6 Low level 5 This means “4 multiplied by a” What is the inverse operation? = 6 Division

b = 3 5 b = 3 x 5 = 15 Low Level 5 This means “b divided by 5” What is the inverse operation? = 15 Multiplication

3a + 8 = 35 3a = 35 - 8 3a = 27 a = 27 3 = 9 High Level 5 Let’s make this question into a low level 5 question. We know how to solve those! 3a = 35 - 8 This is the only bit that is different. We can use inverse operations to get rid of it. This says “add 8” 3a = 27 What is the inverse operation? a = 27 3 Subtract Look! A low level 5 question! = 9

Level 6 Objective: Be able to solve linear equations with an unknown both sides.

5a + 3 = 2a + 12 5a = 2a + 12 - 3 5a = 2a + 9 5a – 2a = 9 3a = 9 a = 9 Low level 6 5a + 3 = 2a + 12 Let’s start by removing this. 5a = 2a + 12 - 3 5a = 2a + 9 Doing this removes the add 3, but remember to subtract 3 from the other side too! 5a – 2a = 9 This says add 3 Now, let’s remove this. 3a = 9 To “get rid of” our 2a, we have to subtract 2a What is the inverse operation? a = 9 A 3 = 3 Subtract 3

5(a - 4) = 3(a + 2) 5a - 20 = 3a + 6 5a = 3a + 6 + 20 5a = 3a + 26 Expanding Brackets Tutorial High Level 6 5(a - 4) = 3(a + 2) 5a - 20 = 3a + 6 5a = 3a + 6 + 20 First expand the brackets (Click the tutorial button above if you cannot remember how to do this) Now we have a low level 6 question which can be solved just as before. 5a = 3a + 26 5a – 3a = 26 2a = 26 a = 13

Level 7 Objective: Be able to solve linear equations with an unknown on one side, including problems where the coefficients are fractional

Level 7