 # Equations – Success if you can do these 3x = 64x + 2 = 3x + 7 x/4 = 25x – 3 = 7 + 3x x + 3 = 173(x + 2) = 12 x – 4 = 134(x + 5) = 32 3x + 4 = 253(2x –

## Presentation on theme: "Equations – Success if you can do these 3x = 64x + 2 = 3x + 7 x/4 = 25x – 3 = 7 + 3x x + 3 = 173(x + 2) = 12 x – 4 = 134(x + 5) = 32 3x + 4 = 253(2x –"— Presentation transcript:

Equations – Success if you can do these 3x = 64x + 2 = 3x + 7 x/4 = 25x – 3 = 7 + 3x x + 3 = 173(x + 2) = 12 x – 4 = 134(x + 5) = 32 3x + 4 = 253(2x – 2) = 2(x + 6) 4x – 3 = 174(3x + 5) = 2(x + 15)

How to solve the 4(x + 3) = 40 type of equation The 4, 3 and 40 could be any numbers

Get rid of the brackets 4(x + 3) = 40

Get rid of the brackets 4(x + 3) = 40 X x + 3 4 4x + 12 4x + 12 = 40

Get rid of the brackets 4(x + 3) = 40 X x + 3 4 4x + 12 4x + 12 = 40 Subtract 12 from both sides

Get rid of the brackets 4(x + 3) = 40 X x + 3 4 4x + 12 4x + 12 = 40 4x + 12 – 12 = 40 – 12 Subtract 12 from both sides

Get rid of the brackets 4(x + 3) = 40 X x + 3 4 4x + 12 4x + 12 = 40 4x + 12 – 12 = 40 – 12 4x =28 Subtract 12 from both sides

Get rid of the brackets 4(x + 3) = 40 X x + 3 4 4x + 12 4x + 12 = 40 4x + 12 – 12 = 40 – 12 4x =28 Subtract 12 from both sides Divide both sides by 4

Get rid of the brackets 4(x + 3) = 40 X x + 3 4 4x + 12 4x + 12 = 40 4x + 12 – 12 = 40 – 12 4x =28 4x/4 = 28/4 Subtract 12 from both sides Divide both sides by 4

Get rid of the brackets 4(x + 3) = 40 X x + 3 4 4x + 12 4x + 12 = 40 4x + 12 – 12 = 40 – 12 4x =28 4x/4 = 28/4 = 7 Subtract 12 from both sides Divide both sides by 4

Solve this equation 5(x + 2) = 3(x + 10)

Get rid of the brackets

5(x + 2) = 3(x + 10) 5x + 10 = 3x + 30 Get rid of the brackets

5(x + 2) = 3(x + 10) 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 Get rid of the brackets Subtract 10 from both sides

5(x + 2) = 3(x + 10) 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 Get rid of the brackets Subtract 10 from both sides

5(x + 2) = 3(x + 10) 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 Get rid of the brackets Subtract 10 from both sides Subtract 3x from both sides

5(x + 2) = 3(x + 10) 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 5x – 3x = 3x + 20 –3x 2x = 20 Get rid of the brackets Subtract 10 from both sides Subtract 3x from both sides

5(x + 2) = 3(x + 10) 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 5x – 3x = 3x + 20 –3x 2x = 20 Get rid of the brackets Subtract 10 from both sides Subtract 3x from both sides Divide both sides by 2

5(x + 2) = 3(x + 10) 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 5x – 3x = 3x + 20 –3x 2x = 20 2x/2 = 20/2 x = 10 Get rid of the brackets Subtract 10 from both sides Subtract 3x from both sides Divide both sides by 2

Remember, always do the same thing to both sides. Felix is checking that you do this properly. 5x + 3 = 43 + 3x 5x + 3 – 3 = 43 – 3 5x = 40 + 3x 5x – 3x = 40 + 3x – 3x 2x = 40 x = 20

Download ppt "Equations – Success if you can do these 3x = 64x + 2 = 3x + 7 x/4 = 25x – 3 = 7 + 3x x + 3 = 173(x + 2) = 12 x – 4 = 134(x + 5) = 32 3x + 4 = 253(2x –"

Similar presentations