9-3 Graphing y = ax + bx + c up 1a. y = x - 1 for -3<x<3

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Presentation transcript:

9-3 Graphing y = ax + bx + c up 1a. y = x - 1 for -3<x<3 2 2 up 1a. y = x - 1 for -3<x<3 B. Does it open up or down? C. Identify the axis of symmetry and its vertex. y-axis, (0,-1) y x -3 -2 -1 1 2 3 y 8 3 -1 8 x = 0 x -4 4

Use the equation y = x² + 8x + 13 for x = -7, -6, -5, … 0, to answer questions and make a table of values. a. What is the vertex of the parabola? b. What is its axis of symmetry? c. Find the y-intercept. d. Graph it. e. What are the x-coordinates of the 2 points where y = 13? (-4,-3) x = -4 y 6 1 -2 -3 13 x -7 -6 -5 -4 -3 -2 -1 ? 13 0 & -8

y y 6 1 -2 -3 13 x -7 -6 -5 -4 -3 -2 -1 12 8 4 x -8 -4 -4

To find the x value of the turning point, use this 2 3a. Graph y = .5x - 2x. To find the x value of the turning point, use this formula. , where a is the _____________ and b is the _____________ coefficient of x 2 x = -b 2a coefficient of x x = -(-2) = 2 = 2 2(.5) 1 So, a = .5 and b = -2 Now you can make a table selecting x values that will enable you to graph the parabola over its line or symmetry. x y -1 2.5 0 0 1 -1.5 2 -2 3 -1.5 4 0 5 2.5 b. Does the graph have an axis of symmetry? If so, what is it? c. Name the vertex. d. Identify the y-intercept. Yes, x = 2 (2,-2)

y x y -1 2.5 0 0 1 -1.5 2 -2 3 -1.5 4 0 5 2.5 3 2 1 x 5 -1 -2 -3