Newton’s Laws of Motion

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Presentation transcript:

Newton’s Laws of Motion Motion & Forces Newton’s Laws of Motion “If I have seen far, it is because I have stood on the shoulders of giants.” - Sir Isaac Newton (referring to Galileo)

Force Force a push or pull that one body exerts on another What forces are being exerted on the football? Fkick Fgrav

Newton’s Laws of Motion

Newton’s First Law Newton’s First Law of Motion “Law of Inertia” tendency of an object to resist any change in its motion increases as mass increases

Newton’s First Law Newton’s First Law of Motion An object at rest will remain at rest and an object in motion will continue moving at a constant velocity unless acted upon by a net force.

Newton’s First Law Balanced Forces forces acting on an object that are opposite in direction and equal in size no change in velocity

What if the forces aren’t balanced? Net Force unbalanced forces that are not opposite and equal velocity changes (object accelerates) Fnet Ffriction Fpull N W

F = ma Newton’s Second Law Newton’s Second Law of Motion The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. F = ma

F = ma F m a F m Newton’s Second Law F: force (N) m: mass (kg) a: accel (m/s2) 1 N = 1 kg ·m/s2

a F m Calculations F = ? F = ma m = 40 kg F = (40 kg)(4 m/s2) What force would be required to accelerate a 40 kg mass by 4 m/s2? GIVEN: F = ? m = 40 kg a = 4 m/s2 WORK: F = ma F = (40 kg)(4 m/s2) F = 160 N m F a

a F m Calculations m = 4.0 kg a = F ÷ m F = 30 N a = (30 N) ÷ (4.0 kg) A 4.0 kg shotput is thrown with 30 N of force. What is its acceleration? GIVEN: m = 4.0 kg F = 30 N a = ? WORK: a = F ÷ m a = (30 N) ÷ (4.0 kg) a = 7.5 m/s2 m F a

Newton’s Third Law Newton’s Third Law of Motion When one object exerts a force on a second object, the second object exerts an equal but opposite force on the first.

Newton’s Third Law Problem: How can a horse pull a cart if the cart is pulling back on the horse with an equal but opposite force? Aren’t these “balanced forces” resulting in no acceleration? NO!!!

Newton’s Third Law Explanation: forces are equal and opposite but act on different objects they are not “balanced forces” the movement of the horse depends only on the forces acting on the horse

Newton’s Third Law Action-Reaction Pairs The hammer exerts a force on the nail to the right. The nail exerts an equal but opposite force on the hammer to the left.

Newton’s Third Law Action-Reaction Pairs The rocket exerts a downward force on the exhaust gases. The gases exert an equal but opposite upward force on the rocket. FG FR

Newton’s Third Law F m Action-Reaction Pairs Both objects accelerate. The amount of acceleration depends on the mass of the object. F m Small mass  more acceleration Large mass  less acceleration

Types of Different Forces

Gravity Gravity force of attraction between any two objects in the universe increases as... mass increases distance decreases

Gravity Who experiences more gravity - the astronaut or the politician? Which exerts more gravity - the Earth or the moon? more mass less distance

Gravity Would you weigh more on Earth or Jupiter? Jupiter because... greater mass greater gravity greater weight

W = mg Gravity Weight the force of gravity on an object This follows Newton’s Second Law! W = mg W: weight (Newtons) m: mass (kg) g: acceleration due to gravity (m/s2)

Gravity Mass vs. Weight Mass – always the same! (kg) Weight – Depends on gravity (N) Would you weigh more on Earth or Jupiter? Jupiter – it’s gravity and stronger than Earth’s. Your MASS would be the same on Jupiter.

Animation from “Multimedia Physics Studios.” * 07/16/96 Gravity Accel. due to gravity (g) Without air resistance, all falling objects have the same acceleration! On Earth: g = 9.8 m/s2 elephant feather Ended 7th 9/27 Animation from “Multimedia Physics Studios.” *

g F m Calculations F(W) = 557 N m = F ÷ g m = ? * 07/16/96 Calculations Mrs. J. weighs 557 N. What is her mass? GIVEN: F(W) = 557 N m = ? g = 9.8 m/s2 WORK: m = F ÷ g m = (557 N) ÷ (9.8 m/s2) m = 56.8 kg Ended 8th 9/27 m F g *

Concept Test Is the following statement true or false? An astronaut has less mass on the moon since the moon exerts a weaker gravitational force. False! Mass does not depend on gravity, weight does. The astronaut has less weight on the moon.

Friction Friction force that opposes motion between 2 surfaces depends on the: types of surfaces force between the surfaces

Friction Friction is greater... between rough surfaces when there’s a greater force between the surfaces (e.g. more weight)

Friction Static Friction Prevents two surfaces from sliding past each other No motion!

Friction Kinetic (sliding) Friction Opposes the motion of two surfaces sliding past each other Requires motion!

Friction Rolling Friction Frictional force between a rolling object and the surface it rolls on

Air Resistance Air Resistance a.k.a. “fluid friction” or “drag” force that air exerts on a moving object to oppose its motion depends on: speed surface area shape density of fluid

Air Resistance Fair Fgrav Terminal Velocity maximum velocity reached by a falling object reached when… Fgrav = Fair Fair no net force  no acceleration  constant velocity Fgrav

Animation from “Multimedia Physics Studios.” Air Resistance Falling with air resistance heavier objects fall faster because they accelerate to higher speeds before reaching terminal velocity Fgrav = Fair larger Fgrav  need larger Fair  need higher speed Animation from “Multimedia Physics Studios.”

Momentum

p = mv v p m Momentum Momentum quantity that describes the motion p: momentum (kg ·m/s) m: mass (kg) v: velocity (m/s)

v p m Momentum p = ? p = mv m = 280 kg p = (280 kg)(3.2 m/s) Find the momentum of a bumper car if it has a total mass of 280 kg and a velocity of 3.2 m/s. GIVEN: p = ? m = 280 kg v = 3.2 m/s WORK: p = mv p = (280 kg)(3.2 m/s) p = 896 kg·m/s m p v

v p m Momentum p = 675 kg·m/s v = p ÷ m m = 300 kg The momentum of a second bumper car is 675 kg·m/s. What is its velocity if its total mass is 300 kg? GIVEN: p = 675 kg·m/s m = 300 kg v = ? WORK: v = p ÷ m v = (675 kg·m/s)÷(300 kg) v = 2.25 m/s m p v

Conservation of Momentum Law of Conservation of Momentum The total momentum in a group of objects doesn’t change unless outside forces act on the objects. pbefore = pafter

Conservation of Momentum Newton’s 3rd Law Revisited Example: Two people push off each other. Newton’s 3rd Law says the forces are opposite. Result: one positive, one negative velocity. Total momentum is conserved!

Conservation of Momentum A 5-kg cart traveling at 4.2 m/s strikes a stationary 2-kg cart and they connect. Find their speed after the collision. BEFORE Cart 1: m = 5 kg v = 4.2 m/s Cart 2 : m = 2 kg v = 0 m/s AFTER Cart 1 + 2: m = 7 kg v = ? p = 21 kg·m/s m p v p = 0 v = p ÷ m v = (21 kg·m/s) ÷ (7 kg) v = 3 m/s pbefore = 21 kg·m/s pafter = 21 kg·m/s

Impulse Impulse is the product of average force and time. Impulse = FΔt Impulse is equal to change in momentum. Recall: F=ma, or F=mΔv/Δt This means FΔt = mΔv

Impulse A larger change in momentum can be caused by: Larger force Longer contact time of force

Impulse OR, for the same change in momentum: Larger contact time = smaller force Shorter contact time = larger force Examples: