Warm Up # 4 When the temperature for 45.0 grams of water decreases from 90.5oC to 7.0oC, how much energy is lost, in kilojoules? The specific heat of.

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Warm Up # 4 When the temperature for 45.0 grams of water decreases from 90.5oC to 7.0oC, how much energy is lost, in kilojoules? The specific heat of water is 4.18J/oC•g. What does ΔH mean? Give two examples of phase change in which the ΔH will be positive. Explain why they are positive. Draw a diagram for an endothermic reaction. Use these specific numbers. The reactants are originally at 50 J of energy, the peak of the energy is at150 J of energy. The products are at 110 J of energy. With these numbers in mind answer the following questions: How much activation energy is required for the reaction to occur. What is the ΔH in this reaction? Is it a positive or negative number?

Amount of Energy with Phase Changes Chapter 17.3-17.4 Amount of Energy with Phase Changes

Given information for H2O: You have 78.0 grams of ice at -5.00oC. Calculate how much energy will be generated, in kilojoules (kJ), when you increase the temperature to 125oC, producing water vapor. Given information for H2O: ΔHfus = 6.01 kJ/mol Melting Point: 0.00oC ΔHvap = 40.7 kJ/mol Boiling Point: 100oC C = 4.18 J/oC•g

Measuring Heat Energy A, C and E = temp increases/decreases within a phase: q = (m) (c) (ΔT) B = solid/liquid phase change: ΔHfus or ΔHsolid D = liquid/gas phase change: ΔHvap or ΔHcond

Step 1: Solid State -5.00oC  0.00oC (melting point) How? q = m • c • ΔT q = (78.0g) (4.18 J/oC•g) (0.00oC-[-5.00oC]) q = ____________ CONVERT TO KILOJOULES

Step 2: Melting 0oC = melting How? Use ΔHfus (6.01 kJ/mol) Since Δ H is in kJ/mol, convert 78.0g H2O into mol 6.01 kJ/mol = ( x kJ/ 4.33 mol ) x = ____________

Step 3: Liquid State 0oC  100oC How? q = m • c • ΔT q = (78.0g) (4.18J/oC•g) (100oC – 0oC) q = ______________ CONVERT TO KILOJOULES

Step 4: Boiling 100oC = boiling How? ΔHvap (40.7 kJ/mol) Since ΔH in kJ/mol, convert 78.0 g of H2O to mol 40.7 kJ/mol = (x kJ / 4.33 mol) x = _____________

Step 5: In Gaseous State 100oC  125oC How? q = m • c • ΔT q = (78.0g) (4.18 J/oC • g) (125oC – 100oC) q = ________________ CONVERT TO KILOJOULES

Review: Calculate Heat WITHIN a phase: q = m • c • ΔT Calculate Heat DURING a phase change: ΔHvap/fus Convert everything to kilojoules (kJ)

Warm Up #