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Warm-up #2 Who do you agree with and why?

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Presentation on theme: "Warm-up #2 Who do you agree with and why?"— Presentation transcript:

1 Warm-up #2 Who do you agree with and why?
Noah Lot: “I can make water boil hotter if I add more heat!” Ima Smart: “I can make water boil faster, but at the same temperature, if I add more heat!”

2 Homework Review

3 Molar Enthalpy and Heating Curves

4 Enthalpy H=Heat of substance at a constant pressure ∆H = enthalpy

5 Enthalpy + ∆H = endothermic rxn - ∆H = exothermic rxn

6 Enthalpy of Fusion—heat absorbed when 1 mole melts +ΔHfus (6.01KJ/mol)
(solid to liquid) Enthalpy of Solidification—heat lost when 1 mole freezes –ΔHsolid (-6.01 KJ/mol) ( liquid to solid) +ΔHfus=-ΔHsolid (same quantity; opposite direction)

7 Enthalpy of Vaporization—heat absorbed when 1 mole vaporizes
+ΔHvap (40.79 KJ/mol) (liquid to gas) Enthalpy of Condensation—Heat lost when 1 mole condenses -ΔHcond (gas to liquid) ( KJ/mol) +ΔHvap=-ΔHcond (same quantity, opposite direction)

8 ∆ Hstate change= molar enthalpy of state change
Heats of state change Q = m∆ Hstate change Q= Energy or heat (kJ) m= moles of the sample (mol) ∆ Hstate change= molar enthalpy of state change

9 Sample Problem Calculate the energy needed to vaporize g of water. (convert g into moles then plug in) Q = (m) x (Hvap) 10.0 g H2O x 1 mol H2O = 0.56 moles 18 g H2O Q = (0.56 moles) x (40.7 kJ/mol) Q= kJ

10 Practice How much energy is absorbed by 395 g of water as it vaporizes into steam at 100°C? ΔHvap=40.79 kJ/mol How much energy is released when 645g of water is converted into ice at 0°C? ΔHsolid=-6.01 kJ/mol

11 Heating Curves Diagram representation of the phase changes for a given substance. What do you think it looks like if we plot time vs temperature for water’s heat curve?

12

13 Heating Curve practice- page 3
Then practice problems page 4


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