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A. Phase Changes Sublimation solid  gas

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Presentation on theme: "A. Phase Changes Sublimation solid  gas"— Presentation transcript:

1 A. Phase Changes Sublimation solid  gas
v.p. of solid equals external pressure EX: dry ice, mothballs, solid air fresheners

2 B. Phase Diagrams Show the phases of a substance at different temps and pressures

3 Water vs. Carbon Dioxide
B. Phase Diagrams Water vs. Carbon Dioxide

4 C. Heating Curves Gas - KE  Boiling - PE  Liquid - KE 
Melting - PE  Solid - KE 

5 C. Heating Curves Temperature Change change in KE (molecular motion)
Phase Change change in PE (molecular arrangement) temp remains constant

6 C. Heating Curves Heat of Fusion (Hfus)
energy required to melt or freeze 1 mole of a substance at its m.p./f.p. Hfus of ice = kJ/mol To freeze (or melt) one mole of ice, you need to remove or put in kJ of energy (heat)

7 C. Heating Curves Heat of Vaporization (Hvap)
energy required to boil or condense 1 mole of a substance at its b.p./c.p. Hvap for water = kJ/mol usually larger than Hfus…why? EX: sweating, steam burns

8 D. Properties of Water Hfus of ice = 6.009 kJ/mol
Hvap for water = kJ/mol To calculate the amount of heat energy required to melt or freeze a substance: convert grams to moles multiply by molar heat of fusion or vaporization

9 D. Properties of Water How much heat energy is required to melt 25 grams of ice at 0oC to liquid water at a temperature of 0oC? ice 6.009 kJ 1 mol H2O 25 g H2O 1 mol H2O 18.02 g H2O = 8.3 kJ

10 D. Properties of Water How much heat energy is required to change grams of liquid water at 100oC to steam at 100oC? steam 40.79 kJ 1 mol H2O 500.0 g H2O 1 mol H2O 18.02 g H2O = 1132 kJ


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