Stoichiometry Unit 8 Lesson 1.

Slides:



Advertisements
Similar presentations
Stoichiometry! The math of chemistry .
Advertisements

Limiting Reactant.  Determine which reactant is left over in a reaction.  Identify the limiting reactant and calculate the mass of the product.  Calculate.
MOLE RATIOS IN CHEMICAL EQUATIONS
MOLE RATIOS IN CHEMICAL EQUATIONS STOICHIOMETRY ‘ the study of the quantitative relationships that exist in chemical formulas and reactions ’ The study.
Chapter 12 Stoichiometry The study of the quantitative, or measurable, relationships that exist in chemical formulas and chemical reactions.Stoichiometry.
Chapter 3 - Stoichiometry It is important to be able to quantify the amount of reagent(s) that will be needed to produce a given amount of product(s).
Stoichiometry “In solving a problem of this sort, the grand thing is to be able to reason backward. This is a very useful accomplishment, and a very easy.
Chapter 9 Stoichiometry
Chapter 11 Stoichiometry.
Stoichiometry II. Solve stoichiometric problems involving moles, mass, and volume, given a balanced chemical reaction. Include: heat of reaction Additional.
Things you must KNOW and what to expect  Things you must KNOW  You must KNOW your polyatomics  You must KNOW how to write a balanced formula  You have.
Sec. 11.2: Stoichiometric Calculations
Stoichiometry Section 12.1.
Stoichiometry. What Is It? Branch of chemistry that shows the relationships among reactants and products in a chemical reaction Equations must be balanced.
Mass-Gas Stoichiometry Using a balanced chemical equation, it is possible to determine the volume of a gas if the mass of a reactant or product Is given.
2Mg (s) + O 2 → 2MgO INTERPRETING A CHEMICAL EQUATION Quantitative Interpretation of Chemical Reactions Stoichiometry is one of the most important topic.
The Mathematics of Chemical Reactions Chemical Stoichiometry Quantitative Relationships between the reactants and products in a chemical reaction.
Bell Work: Mole Ratios 2 C 4 H 10 + ___ O 2 → ___ CO 2 + ___ H 2 O 1. Finish balancing the equation. How many moles of oxygen will react? 3. water.
Stoichiometry Chapter Stoichiometry Stoichiometry is the study of quantitative relationships between the amounts of reactants used and amounts.
Chap. 9: Stoichiometry Identify the mole ratio of any two species in a chemical reaction. Calculate theoretical yields from chemical equations.
Chapter 11: Stoichiometry
Stoichiometry Introduction to Stoichiometry. Stoichiometry  Objectives  Define stoichiometry  Describe the importance of the mole ratio in stoichiometric.
What is Stoichiometry? Objectives: 6.0 Solve stoichiometric problems involving relationships among the number of particles, moles, and masses of reactants.
Learning Objectives Perform stoichiometric calculations to determine – Mass relationships between products and reactants Stoichiometric Calculations.
01 StoichiometryChapter 12. What conversion factors would you need if you were going to move from grams to liters? Solve the following problems. –How.
When gases react, the coefficients in the balanced chemical equation represent both molar amounts and relative volumes. Section 3: Gas Stoichiometry K.
Stoichiometry GPS 13. Stoichiometry Example: 2H 2 + O 2 → 2H 2 O Equivalencies: 2 mol H 2 for every 1 mol O 2 2 mol H 2 for every 2 mol H 2 O 1 mol O.
Chapter 12: Stoichiometry
Stoichiometry Introduction to Chemistry. Stoichiometry Example: 2H 2 + O 2 → 2H 2 O Equivalencies: 2 mol H 2 for every 1 mol O 2 2 mol H 2 for every 2.
The Mathematics of Chemical Equations
Stoichiometry Introduction.
Stoichiometry II.
Stoichiometry.
Stoichiometry Stoichiometry: is the study of the calculations of amounts of substances involved in chemical equations.
Melinda Cottrell Integrated Science Grade 10 Unit Conversions (Part 2)
Moles to Moles Stoichiometry Calculation Notes
Law of Conservation of Matter
Lecture 60 Defining Stoichiometry Ozgur Unal
Chapter 9 Stoichiometry.
Calculations with Equations
Chapter 12 Stoichiometry
Chemical Reactions Unit
Reaction Stoichiometry
Stoichiometry.
11.1 Defining Stoichiometry Ashley Lardizabal Discovery School
Stoichiometry Review.
Stoichiometry Chapter 11.
Chapter 11 Stoichiometry
Stoichiometric Calculations
Stoichiometry – Mr. Mole.
Things to memorize Solubility rules Strong bases Strong acids
Stoichiometry Unit 8 Lesson 1.
Chapter 7 Reactions.
Chemical Calculations
5.2 Stoichiometry. 5.2 Stoichiometry Moles 6.022×1023 Particles 1mol = STP 1mol = Molar Mass The mass of 1 mole of a substance in grams (also.
Chemical Calculations
Warm-Up How many molecules are in 5.78 mol of ammonium nitrate?
Warm-Up *Don’t turn in your lab just yet
4/27/16 Today I will define stoichiometry and calculate mole-mole stoichiometry problems Warm Up Write a balanced equation for the reaction of magnesium.
9.1 NOTES Stoichiometry.
Stoichiometry Section 12.1.
Stoichiometry.
and cooking with chemicals
Stoichiometry Problems
Stoichiometry of Gases
Stoichiometry.
Mole ratios Mole to mole conversions
Stoichiometry Unit 8 Lesson 1.
Stoichiometry Unit 7 Lesson 1.
STOICHIOMETRY.
Presentation transcript:

Stoichiometry Unit 8 Lesson 1

Stoichiometry “The study of quantitative relationships between amounts of reactants used and products formed” Stoichiometry is based on the Law of Conservation of Matter Example: 2H2 + O2  2H2O Reads stoichiometrically as “2 moles of hydrogen + 1 mole of oxygen make 2 moles of H2O”

Balanced Equation = Mole Relationship The coefficients in a balanced equation indicate the number of particles (atoms/molecules) of each substance involved. The coefficients also indicate the number of moles of each substance needed or created. N2H4 + 2H2O2  N2 + 4H2O 1 mol N2H4 + 2 mol H2O2 = 1 mol N2 + 4 mol H2O

Mole Relationship = Conversion Factor (using coefficients from balanced equation) N2H4 + 2H2O2  N2 + 4H2O 1 mole N2H4 = 4 moles H2O 2 moles H2O2= 4 moles H2O So 1 mole N2H4 = 2 moles H2O2 1 mole N2H4 = 1 mole N2 2 moles H2O2= 1 mole N2 So 1 mole N2H4 = 2 moles H2O2 (again)

Using the Conversion Factor (coefficients from balanced equation) If 1 mole N2H4 = 2 moles H2O2: How many moles of H2O2 are needed to react completely with 3.5 moles of N2H4? 7.0 moles H2O2

Using the Conversion Factor (coefficients from balanced equation) If 1 mole N2H4 = 4 moles H2O: How many moles of water can be made if we react 3.5 moles of N2H4? 14 moles H2O

Steps for Solving Stoichiometry 1. Write & balance chemical equation 2. Plan conversions using coefficients from balanced equation 3. Write your conversion factors and check units 4. Calculate 5. Adjust for significant figures and include units

Steps for Solving Stoichiometry Example: How many moles of Carbon Dioxide are created from the combustion of 5.0 moles of propane (C3H8)? Step 1: Write & balance equation C3H8 +O2  H2O + CO2 C3H8 +5O2  4H2O + 3CO2 Step 2: Plan conversions 1 mole C3H8 = 3 moles CO2

Steps for Solving Stoichiometry Step 3: Write your equation using coefficients from balanced equation Step 4: Calculate 5.0 X 3 = 15 Step 5: Sig Figs and units 15 moles CO2 3 moles CO2 1 mole C3H8

Mole-Mass Problems 2Na + Cl2  2NaCl Na + Cl2  NaCl Same steps, just need to add a conversion for turning moles into mass Moles A  Moles B Mass B Example: Determine the mass of NaCl produced when 1.25 moles of chlorine gas reacts with sodium metal. Na + Cl2  NaCl 2Na + Cl2  2NaCl

Mass-Mass Problems 4.3 g Al2O3 Adds one more step: Mass A  Moles A Moles B  Mass B Example: In a thermite reaction, powdered aluminum reacts with iron(III) oxide to produce aluminum oxide and molten iron. What mass of aluminum oxide is produced when 2.3 g of aluminum reacts with iron(III) oxide? 2Al + Fe2O3  Al2O3 + 2Fe 4.3 g Al2O3

Volume-Volume Problem What volume of hydrogen gas, along with nitrogen gas, is necessary to produce 16.0 L of ammonia gas (NH3) at STP? N2 + 3H2  2NH3 24.0 L H2

Sample Problem How many moles of bromine (Br2) are produced when fluorine reacts with 347.5 g of potassium bromide? F2 + 2KBr  Br2 + 2KF 1.460 mol Br2

Sample Problem How many liters of oxygen gas are necessary for the combustion of 340. g of ethanol (C2H5OH) gas at 0°C and 1 atm? C2H5OH +3O2  3H2O + 2CO2 496 L O2