Section 8.1 Day 4.

Slides:



Advertisements
Similar presentations
1 Copyright © 2010, 2007, 2004 Pearson Education, Inc. All Rights Reserved. Section 7.2 Estimating a Population Proportion Objective Find the confidence.
Advertisements

CONFIDENCE INTERVALS Feb. 18 th, A STATS PROFESSOR ASKED HER STUDENTS WHETHER OR NOT THEY WERE REGISTERED TO VOTE. IN A SAMPLE OF 50 OF HER STUDENTS.
Copyright © 2010, 2007, 2004 Pearson Education, Inc. Chapter 7 Estimates and Sample Sizes 7-1 Review and Preview 7-2 Estimating a Population Proportion.
Highlighting Standards for Mathematical Practice in an Intro Stats Course by Fides Ushe Springfield College, MA.
Confidence Intervals for Proportions
STA291 Statistical Methods Lecture 17. Bias versus Efficiency 2 AB CD.
Suppose we wanted to estimate the proportion of registered voters who are more enthusiastic about voting in this election compared to other years? Suppose.
Sampling distributions rule of thumb…. Some important points about sample distributions… If we obtain a sample that meets the rules of thumb, then…
Section Estimating a Proportion with Confidence Objectives: 1.To find a confidence interval graphically 2.Understand a confidence interval as consisting.
SECTION 7.2 Estimating a Population Proportion. Practice  Pg  #6-8 (Finding Critical Values)  #9-11 (Expressing/Interpreting CI)  #17-20.
CHAPTER 8 ESTIMATING WITH CONFIDENCE 8.2 Estimating a Population Proportion Outcome: I will state and check all necessary conditions for constructing a.
CHAPTER 8 (4 TH EDITION) ESTIMATING WITH CONFIDENCE Section 8.2.
Section 8.5 Day 3.
Solution: D. Solution: D Confidence Intervals for Proportions Chapter 18 Confidence Intervals for Proportions Copyright © 2010 Pearson Education, Inc.
Confidence Intervals for Proportions
CHAPTER 8 Estimating with Confidence
Confidence Intervals for Proportions
CHAPTER 8 Estimating with Confidence
CHAPTER 8 Estimating with Confidence
CHAPTER 8 Estimating with Confidence
CHAPTER 8 Estimating with Confidence
CHAPTER 8 Estimating with Confidence
Confidence Intervals with proportions a. k. a
Section 8.1 Day 2.
Significance Test for the Difference of Two Proportions
MATH 2311 Section 7.1.
Section 8.4 Day 2.
Confidence Interval for the Difference of Two Proportions
Inferences Based on a Single Sample
CHAPTER 8 Estimating with Confidence
Inference for Proportions
Advanced Placement Statistics
Inferences about Single Sample Proportions
Objectives Estimate population means and proportions and develop margin of error from simulations involving random sampling. Analyze surveys, experiments,
Confidence Intervals Review of Chapter 8.
Section 6-3 –Confidence Intervals for Population Proportions
EVEN Homework ANSWERS p. 483 – 484 # 17, 19-24; p. 496 #27, 31, 32, 33
8.3 Estimating Population Proportions
CHAPTER 8 Estimating with Confidence
CHAPTER 8 Estimating with Confidence
Confidence Intervals: The Basics
8.3 Estimating Population Proportions
Estimating a Population Proportion
Chapter 8: Estimating with Confidence
CHAPTER 8 Estimating with Confidence
Confidence Intervals with Proportions
CHAPTER 8 Estimating with Confidence
Comparing Two Proportions
Unit 6 - Comparing Two Populations or Groups
Pull 2 samples of 10 pennies and record both averages (2 dots).
Chapter 8: Estimating with Confidence
CHAPTER 8 Estimating with Confidence
Comparing Two Proportions
Chapter 8: Estimating with Confidence
2/3/ Estimating a Population Proportion.
8.2 Estimating a Population Proportion
Lecture Slides Elementary Statistics Twelfth Edition
Chapter 10: Comparing Two Populations or Groups
Chapter 6 and 8 review By Henry Mesa Portland Community College.
Chapter 8: Estimating with Confidence
Comparing Two Proportions
Introduction to Confidence Intervals
CHAPTER 8 Estimating with Confidence
Chapter 8: Estimating with Confidence
DG 24 (LAST ONE) minutes Day 57 Agenda: DG 24 (LAST ONE) minutes.
Comparing Two Proportions
Chapter 8: Confidence Intervals
Warm Up A Gallup poll asked 1600 adults in the U.S. “Did you attend church in the past 7 days?” 715 people said yes. Assume the survey used a simple.
Chapter 8: Estimating with Confidence
CHAPTER 8 Estimating with Confidence
Presentation transcript:

Section 8.1 Day 4

What sample size should you use for a survey if you want the margin of error to be at most 2% with 90% confidence?

What sample size should you use for a survey if you want the margin of error to be at most 2% with 90% confidence?

What sample size should you use for a survey if you want the margin of error to be at most 2% with 90% confidence? Because no estimate of p, use p = 0.5

What sample size should you use for a survey if you want the margin of error to be at most 2% with 90% confidence? Because no estimate of p, use p = 0.5 n = (1.645)2●(0.5)(1 – 0.5)/(0.02)2

What sample size should you use for a survey if you want the margin of error to be at most 2% with 90% confidence? Because no estimate of p, use p = 0.5 n = (1.645)2●(0.5)(1 – 0.5)/(0.02)2 n = 1691.266

What sample size should you use for a survey if you want the margin of error to be at most 2% with 90% confidence? Because no estimate of p, use p = 0.5 n = (1.645)2●(0.5)(1 – 0.5)/(0.02)2 n = 1691.266 n = 1692

Page 487, E7 A sample of 549 randomly selected teenagers ages 13 – 17 were asked whether it is appropriate for parents to install a computer program limiting what teens can access on the Internet. Fifty-two percent responded that, yes, this was an appropriate measure. Check the conditions and then construct a 90% confidence interval of the proportion of teenagers nationwide who would think this is an appropriate measure.

Check Conditions

Check Conditions a) (1) Problem states this is a random sample.

Check Conditions a) (1) Problem states this is a random sample. (2) Both np = 549(0.52) = 285.48 and n(1-p) = 549(0.48) = 263.52 are more than 10.

Check Conditions a) (1) Problem states this is a random sample. (2) Both np = 549(0.52) = 285.48 and n(1-p) = 549(0.48) = 263.52 are more than 10. (3) There are more than 10(549) = 5,490 teenagers aged 13 to 17 in the United States.

90% Confidence Interval

90% Confidence Interval A sample of 549 randomly selected teenagers ages 13 – 17 were asked whether it is appropriate for parents to install a computer program limiting what teens can access on the Internet. Fifty-two percent responded that, yes, this was an appropriate measure. Check the conditions and then construct a 90% confidence interval of the proportion of teenagers nationwide who would think this is an appropriate measure.

Remember, x must be a whole number 90% Confidence Interval 1-PropZInt x = 286 x = 52% of 549 = 285.48 n = 549 C-level: .90 Remember, x must be a whole number

90% Confidence Interval 1-PropZInt x = 286 x = 52% of 549 n = 549 C-level: .90 (.48588, .55602)

(c) What is it that you are 90% sure is in the confidence interval?

Page 487, E7 A sample of 549 randomly selected teenagers ages 13 – 17 were asked whether it is appropriate for parents to install a computer program limiting what teens can access on the Internet. Fifty-two percent responded that, yes, this was an appropriate measure. Check the conditions and then construct a 90% confidence interval of the proportion of teenagers nationwide who would think this is an appropriate measure.

(c) What is it that you are 90% sure is in the confidence interval? Construct a 90% confidence interval of the proportion of teenagers nationwide who would think this is an appropriate measure.

(c) What is it that you are 90% sure is in the confidence interval? the proportion of teenagers nationwide who would think it is appropriate for parents to install a computer program limiting what teens can access on the Internet

(d) Interpret this confidence interval (in context).

(d) Interpret this confidence interval (in context). I am 90% confident that the proportion of all teenagers nationwide who would think it is appropriate for parents to install a computer program limiting what teens can access on the Internet is between 48.6% and 55.6%.

(e) Explain the meaning of 90% confidence.

(e) Explain the meaning of 90% confidence. Suppose we could take 100 random samples from this population and construct the 100 resulting confidence intervals. We’d expect that the true proportion of all teenagers nationwide who would think it is appropriate for parents to install a computer program limiting what teens can access on the Internet would be in 90 of these intervals.

Use only the chart of reasonably likely outcomes to answer parts a and b for this question. Do not use a formula or calculator.

According to a recent report, about 70% of adults plan to vote in the next election. How many voters is it reasonably likely to get in a sample of 40 randomly selected adults?

According to a recent report, about 70% of adults plan to vote in the next election. How many voters is it reasonably likely to get in a sample of 40 randomly selected adults? 22 to 34 adults

Suppose that in a random sample of 40 students, 32 studied for a test Suppose that in a random sample of 40 students, 32 studied for a test. Find the 95% CI for the proportion of students who study for tests.

Suppose that in a random sample of 40 students, 32 studied for a test Suppose that in a random sample of 40 students, 32 studied for a test. Find the 95% CI for the proportion of students who study for tests. (0.65, 0.90)

Page 484, P11(a) In a survey consisting of a randomly selected national sample of 600 teens ages 13-17, 4% of the 600 students responding gave their school a D rating (on a scale of A, B, C, D, F). (a) Check to see if the three conditions for computing a confidence interval are met in this case. (Need to be specific, not just general here)

Page 484, P11(a) The problem states that the sample was In a survey consisting of a randomly selected national sample of 600 teens ages 13-17, 4% of the 600 students responding gave their school a D rating (on a scale of A, B, C, D, F). The problem states that the sample was selected randomly from all U.S. teens ages 13 to 17.

Page 484, P11(a) In a survey consisting of a randomly selected national sample of 600 teens ages 13-17, 4% of the 600 students responding gave their school a D rating (on a scale of A, B, C, D, F).

All three conditions are met. Page 484, P11 In a survey consisting of a randomly selected national sample of 600 teens ages 13-17, 4% of the 600 students responding gave their school a D rating (on a scale of A, B, C, D, F). There are well over 600(10) = 6000 teens ages 13 to 17 in the United States. All three conditions are met.

Page 484, P11(b) In a survey consisting of a randomly selected national sample of 600 teens ages 13-17, 4% of the 600 students responding gave their school a D rating (on a scale of A, B, C, D, F). (b) Find a 95% confidence interval for the percentage of all teenagers in the United States who would give their school a D rating.

Page 484, P11(b) In a survey consisting of a randomly selected national sample of 600 teens ages 13-17, 4% of the 600 students responding gave their school a D rating (on a scale of A, B, C, D, F). (b) Find a 95% confidence interval for the percentage of all teenagers in the United States who would give their school a D rating.

Page 487, E8 Conditions met?

Page 487, E8 (1) There is no indication of how the sample was selected, so the random sample condition may not have been met

Page 487, E8 (1) There is no indication of how the sample was selected, so the random sample condition may not have been met (2) np = 885(0.40) = 354 and n(1 – p) = 885(0.6) = 531 are both at least 10

Page 487, E8 (1) There is no indication of how the sample was selected, so the random sample condition may not have been met (2) np = 885(0.40) = 354 and n(1 – p) = 885(0.6) = 531 are both at least 10 (3) There are more than 885(10) = 8850 adults nationwide So, two of the three conditions are met

Page 487, E8 90% confidence interval is?

Page 487, E8 90% confidence interval 1-PropZInt x: 354 n: 885 C-Level: .90

Page 487, E8 (.37291, .42709) Of course, you can have confidence in this interval only if the sampling was done randomly.

Questions?