Equations of Lines.

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Presentation transcript:

Equations of Lines

Equations of Lines Standard form

Standard form of a Line Ax + By = C 5x + 2y = 10 2x - 4y = 8

y = 3x+5 1y = 3x+5 -3x -3x -3x+y = 5 Standard form of a Line Currently in slope intercept form (y = mx + b) Write in Standard Form (Ax + By = C) 1y = 3x+5 -3x -3x -3x+y = 5

y = -2x - 2 1y = -2x - 2 +2x +2x 2x+y = -2 Standard form of a Line Currently in slope intercept form (y = mx + b) Write in Standard Form (Ax + By = C) 1y = -2x - 2 +2x +2x 2x+y = -2

Standard form of a Line Slope Intercept Form Standard Form y = 6x + 4 -6x + y = 4 4x + y = -2 y = -4x - 2 y = -x + 5 x + y = 5 y = -3x + 4 9x + 3y = 12

X and y intercepts Point (0 , 3) Point (-3 , 0) X intercept – where the line crosses the x axis y intercept – where the line crosses the y axis Point (0 , 3) Point (-3 , 0) The x value of the y intercept is 0 The y value of the x intercept is 0

X and y intercepts x + y = 5 x + y = 5 x + y = 5 0 + y = 5 x + 0 = 5 Find the x and y intercepts of the line with the equation of x + y = 5 y intercept – where the line crosses the y axis and x = 0 X intercept – where the line crosses the x axis and y = 0 x + y = 5 x + y = 5 0 + y = 5 x + 0 = 5 x = 5 y = 5 y intercept is (0,5) X-intercept is (5,0)

X and y intercepts 3x + 6y = 12 3x +6y = 12 3x +6y = 12 3(0) +6y = 12 Find the x and y intercepts of the line with the equation of 3x + 6y = 12 y intercept – where the line crosses the y axis and x = 0 X intercept – where the line crosses the x axis and y = 0 3x +6y = 12 3x +6y = 12 3(0) +6y = 12 3x +6(0) = 12 6y = 12 3x = 12 x = 4 y = 2 y intercept is (0,2) X-intercept is (4,0)

X and y intercepts -5x + 2y = -10 -5x +2y = -10 -5x +2y = -10 Find the x and y intercepts of the line with the equation of -5x + 2y = -10 y intercept – where the line crosses the y axis and x = 0 X intercept – where the line crosses the x axis and y = 0 -5x +2y = -10 -5x +2y = -10 -5(0) +2y = -10 -5x +2(0) = -10 2y = -10 -5x = -10 x = 2 y = -5 y intercept is (0,-5) X-intercept is (2,0)