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Published byDaniel Bernard Eaton Modified over 6 years ago

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**Writing equations given a point and the slope of a line**

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Solve for b 4 = -2 ∙ 3 + b 4 = -6 + b +6 +6 10 = b

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Solve for b -8 = (-2)(-11) + b -8 = 22 + b -22 -22 -30 = b

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**Y = mX + b -3 = (-2)(6) + b -3 = -12 + b +12 +12 9 = b Y = -2X + 9**

Write the equation of the line that goes through point (6, -3) and has a slope of -2 m x y Y = mX + b -3 = (-2)(6) + b -3 = b +12 +12 9 = b Y = -2X + 9

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**Y = mX + b -7 = (⅔)(6) + b -7 = 4+ b -4 -4 -11 = b Y = ⅔X - 11**

Write the equation of the line that goes through point (6, -7) and has a slope of ⅔ m x y Y = mX + b -7 = (⅔)(6) + b -7 = 4+ b -4 -4 -11 = b Y = ⅔X - 11

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**Y = mX + b 9 = (2)(2) + b 9 = 4 + b -4 -4 5 = b Y = 2X + 5 m x y**

Write the equation of the line that goes through point (2, 9) and is parallel to the line Y = 2X + 3 m x y Y = mX + b 9 = (2)(2) + b 9 = b -4 -4 5 = b Y = 2X + 5

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