3.5 – Introduction to Functions

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Presentation transcript:

3.5 – Introduction to Functions Defn: A relation is a set of ordered pairs. Domain: The values of the 1st component of the ordered pair. Range: The values of the 2nd component of the ordered pair.

3.5 – Introduction to Functions State the domain and range of each relation. x y 1 3 2 5 -4 6 4 x y 4 2 -3 8 6 1 -1 9 5 x y 2 3 5 7 8 -2 -5

3.5 – Introduction to Functions Defn: A function is a relation where every x value has one and only one value of y assigned to it. State whether or not the following relations could be a function or not. x y 4 2 -3 8 6 1 -1 9 5 x y 1 3 2 5 -4 6 4 x y 2 3 5 7 8 -2 -5 function not a function function

3.5 – Introduction to Functions Functions and Equations. State whether or not the following equations are functions or not. x y -3 5 7 -2 -7 4 3 x y 2 4 -2 -4 16 3 9 -3 x y 1 -1 4 2 -2 function function not a function

3.5 – Introduction to Functions Graphs can be used to determine if a relation is a function. Vertical Line Test If a vertical line can be drawn so that it intersects a graph of an equation more than once, then the equation is not a function.

3.5 – Introduction to Functions The Vertical Line Test y function x y -3 5 7 -2 -7 4 3 x

3.5 – Introduction to Functions The Vertical Line Test y function x y 2 4 -2 -4 16 3 9 -3 x

3.5 – Introduction to Functions The Vertical Line Test y not a function x y 1 -1 4 2 -2 x

3.5 – Introduction to Functions Domain and Range from Graphs x y Find the domain and range of the function graphed to the right. Use interval notation. Domain Range Domain: [–3, 4] Range: [–4, 2]

3.5 – Introduction to Functions Domain and Range from Graphs x y Find the domain and range of the function graphed to the right. Use interval notation. Range Domain: (– , ) Range: [– 2, ) Domain

3.6 – Function Notation Function Notation Shorthand for stating that an equation is a function. Defines the independent variable (usually x) and the dependent variable (usually y).

3.6 – Function Notation Function notation also defines the value of x that is to be use to calculate the corresponding value of y. f(x) = 4x – 1 find f(2). g(x) = x2 – 2x find g(–3). find f(3). f(2) = 4(2) – 1 g(–3) = (-3)2 – 2(-3) f(2) = 8 – 1 g(–3) = 9 + 6 f(2) = 7 g(–3) = 15 (2, 7) (–3, 15)

3.6 – Function Notation f(5) = 7 f(4) = 3 f(5) = 1 f(6) = Given the graph of the following function, find each function value by inspecting the graph. x y ● f(x) ● f(5) = 7 f(4) = 3 ● f(5) = 1 f(6) = 6 ●

3.6 – Function Notation