SPECIFIC HEAT OF A METAL

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Presentation transcript:

SPECIFIC HEAT OF A METAL

PROCEDURE 1) Fill a 250 mL beaker about 3/4 of the way full with tap water and place it on the hotplate to begin boiling.

PROCEDURE 2) Weigh the piece of metal found at your lab station. Record the mass in the data table. 25.00

PROCEDURE 3) Measure out 100 mL of the cold water from the 600 mL beaker. Do not use any ice cubes. Pour the water into the nested styrofoam cups. This is called a calorimeter.

PROCEDURE 4) Measure the temperature of the water in the calorimeter. Record the temperature in the data table.

PROCEDURE 5) Carefully place the metal into the boiling water. Be careful not to drop the metal into the beaker use the tongs.

PROCEDURE 6) Heat the metal for 5 minutes. Take the temperature of the water in the beaker. Do not touch the bottom or sides of the beaker. Record the temperature in the data table.

PROCEDURE Carefully remove the metal from the boiling water using the tongs and place the metal into the calorimeter. Place the thermometer into the calorimeter. While determining the temperature of the metal and the water do not punch a hole into the calorimeter bottom or you will be starting again.

PROCEDURE 8) Record the temperature every 30 seconds for 5 minutes immediately after you add the metal to the water. Put values on the data table. Determine how much the temperature increased. Record this on the data table.

PROCEDURE Pour the water into the sink and clean-up your lab station. Be sure to unplug the hotplate.

D A T A T A B L E MASS OF METAL SAMPLE (GRAMS) 66.30g MASS OF WATER IN CALORIMETER 100 g TEMP OF BOILING H2O IN BEAKER 100 TEMP OF H20 IN CALORIMETER (START) 2 TEMP OF H2O IN CALORIMETER (END) 7 specific heat capacity of H2O 4.184

CALCULATIONS: HEAT LOST BY METAL = HEAT GAINED BY WATER MASS OF WATER X CHANGE IN TEMPERATURE X SPECIFIC HEAT CAPACITY = HEAT GAINED ___________ x ( Tf - Ti w ) x _____________ = ______________ MASS OF METAL X CHANGE IN TEMPERATURE X SPECIFIC HEAT CAPACITY = HEAT LOST ___________ x ( Ti m - Tf ) x ???????????? = ______________ SOLVE FOR THE SPECIFIC HEAT CAPACITY OF THE METAL. = ______________