Solving Linear Systems Using Substitution There are two methods of solving a system of equations algebraically: Elimination Substitution - usually used.

Slides:



Advertisements
Similar presentations
Warm Up Solve each equation for x. 1. y = x y = 3x – 4
Advertisements

Solve an equation with variables on both sides
Directions: Solve the linear systems of equations by graphing. Use the graph paper from the table. Tell whether you think the problems have one solution,
EXAMPLE 1 Solve a quadratic equation having two solutions Solve x 2 – 2x = 3 by graphing. STEP 1 Write the equation in standard form. Write original equation.
Solve an absolute value equation EXAMPLE 2 SOLUTION Rewrite the absolute value equation as two equations. Then solve each equation separately. x – 3 =
4.3 Systems of Equations - Elimination Objective: The student will be able to: Solve systems of equations using elimination with addition and subtraction.
Solve an equation using subtraction EXAMPLE 1 Solve x + 7 = 4. x + 7 = 4x + 7 = 4 Write original equation. x + 7 – 7 = 4 – 7 Use subtraction property of.
3-2: Solving Linear Systems
Standardized Test Practice
Lesson 2-4. Many equations contain variables on each side. To solve these equations, FIRST use addition and subtraction to write an equivalent equation.
3-4 Solving Systems of Linear Equations in 3 Variables
Do Now Pass out calculators. Solve the following system by graphing: Graph paper is in the back. 5x + 2y = 9 x + y = -3 Solve the following system by using.
Standardized Test Practice
Standardized Test Practice
3.2 Solving Systems Algebraically
Solving Linear Systems by Substitution Section 3-2:
Solve an equation by combining like terms EXAMPLE 1 8x – 3x – 10 = 20 Write original equation. 5x – 10 = 20 Combine like terms. 5x – =
Solve a two-step inequality EXAMPLE 1 3x – 7 < 8 Write original inequality. 3x < 15 Add 7 to each side. x < 5 Divide each side by 3. ANSWER The solutions.
Do Now (3x + y) – (2x + y) 4(2x + 3y) – (8x – y)
Solve an equation using addition EXAMPLE 2 Solve x – 12 = 3. Horizontal format Vertical format x– 12 = 3 Write original equation. x – 12 = 3 Add 12 to.
Example 1 Solving Two-Step Equations SOLUTION a. 12x2x + 5 = Write original equation. 112x2x + – = 15 – Subtract 1 from each side. (Subtraction property.
Systems of Equations: Substitution
Use the substitution method
Example 2 Multiple Choice Practice
Solve Linear Systems by Substitution January 28, 2014 Pages
Solving Systems of Equations So far, we have solved systems using graphing and substitution. These notes show how to solve the system algebraically using.
Solve Linear Systems by Substitution Students will solve systems of linear equations by substitution. Students will do assigned homework. Students will.
Bell Ringer 2. Systems of Equations 4 A system of equations is a collection of two or more equations with a same set of unknowns A system of linear equations.
Multiply one equation, then add
Solve a two-step equation by combining like terms EXAMPLE 2 Solve 7x – 4x = 21 7x – 4x = 21 Write original equation. 3x = 21 Combine like terms. Divide.
5.4 Elimination Using Multiplication Algebra 1 Objective: Each student will understand if addition and subtraction does not eliminate a variable – how.
6-2 Solving Systems Using Substitution Hubarth Algebra.
Solving Equations with Variables on Both Sides. Review O Suppose you want to solve -4m m = -3 What would you do as your first step? Explain.
3-2: Solving Linear Systems. Solving Linear Systems There are two methods of solving a system of equations algebraically: Elimination Substitution.
Substitution Method: Solve the linear system. Y = 3x + 2 Equation 1 x + 2y=11 Equation 2.
Rewrite a linear equation
Warm Up 2x – 10 9 – 3x 12 9 Solve each equation for x. 1. y = x + 3
Objective I can solve systems of equations using elimination with addition and subtraction.
Example: Solve the equation. Multiply both sides by 5. Simplify both sides. Add –3y to both sides. Simplify both sides. Add –30 to both sides. Simplify.
EXAMPLE 2 Rationalize denominators of fractions Simplify
Solving Multi-Step Equations
The student will be able to:
Solve for variable 3x = 6 7x = -21
Solve an equation by multiplying by a reciprocal
3-2: Solving Linear Systems
6-2 Solving Systems Using Substitution
Example 2 4 m 8 m 5m 12 m x y.
Solving Systems Using Substitution
Solving Multi-Step Equations
Example 2 4 m 8 m 5m 12 m x y.
Solving Multi-Step Equations
Solve an equation by combining like terms
Objectives Solve systems of linear equations in two variables by elimination. Compare and choose an appropriate method for solving systems of linear equations.
Solving Multi-Step Equations
Solving Multi-Step Equations
Solving Systems of Equations
3-2: Solving Linear Systems
12 Systems of Linear Equations and Inequalities.
Solving Multi-Step Equations
The student will be able to:
Section Solving Linear Systems Algebraically
Solving Systems of Equations
Solving Multi-Step Equations
3-2: Solving Linear Systems
Example 2B: Solving Linear Systems by Elimination
6-3 Solving Systems Using Elimination (Combination)
The student will be able to:
3-2: Solving Linear Systems
Warm- Up: Solve by Substitution
EXAMPLE 4 Solve proportions Solve the proportion. ALGEBRA a x 16
Presentation transcript:

Solving Linear Systems Using Substitution There are two methods of solving a system of equations algebraically: Elimination Substitution - usually used when one variable has a coefficient of 1 or -1

Substitution To solve a system of equations by substitution… 1.Solve one equation for one of the variables. (Solve for easiest variable to solve for.) 2.Substitute the value of the variable into the other equation. 3.Simplify and solve the equation. 4.Substitute back into any equation to find the value of the other variable.

Substitution Solve the system: x - 2y = -5 y = x one variable is already solved for (y) Substitute (x + 2) for y in the first equation to solve for x. x - 2y = -5Original Equation x - 2(x + 2) = -5 Substitute x - 2x – 4 = -5Multiply -x - 4 = -5Combine like terms -x = -1Add 4 to both sides x = 1Multiply both sides by -1

Substitution Solve the system: x - 2y = -5 y = x + 2 y = x + 2Equation x = 1 y = 1 + 2Substitute y = 3Solve Solution: (1, 3)

Substitution ● Let’s check the solution. The answer (1, 3) must check in both equations. x - 2y = -5 y = x (3) = -53 = = -5  3 = 3 

Guided Practice Solve the system: 2p + 3q = 2 p - 3q = -17 Check your answer.

Writing and Using a Linear System An AMC movie theater has 345 customers in one day and makes $3555 in ticket sales. Adult tickets are $11 and student tickets are $9. How many adults and students were there? Solution Verbal Model: #Adults + #Students = Total Tickets (#Adults)($Adult) + (#Students)($Student) = Total Cost

Writing and Using a Linear System Solution x = Adults y = Students x + y = 345Substitute 11x + 9y = 3555

Writing and Using a Linear System Solution x + y = x + 9y = 3555 x + y = 345 y = xIsolate Variable 11x + 9(345 - x) = x x = 3555Distributive Property 2x = 3555Combine Like Terms 2x = 450Subtract x = 225Divide

Writing and Using a Linear System Solution x + y = 345 x = y = 345 y = 120 Answer There were 225 adults and 120 students. (225, 120) 11x + 9y = 3555 x + y = 345 *You can also check by graphing.

Independent Practice Solve the linear systems by substitution: 1.x = 4 2x - 3y = x + y = 7 4x + 2y = 16