Section 9.3—Analysis of a Chemical Formula How can we determine a chemical formula?

Slides:



Advertisements
Similar presentations
It’s a beauty mark… It’s a small furry garden pest… No, wait… its how we count ATOMS!
Advertisements

Empirical and Molecular Formulas
Section Percent Composition and Chemical Formulas
Stoichiometry © 2009, Prentice-Hall, Inc. Unit 10: Stoichiometry 1 Calculations with Chemical Formulas.
Empirical and Molecular Formulas. Formaldehyde CH 2 O Acetic acid C 2 H 4 O 2 Gylceradehyde C 3 H 6 O 3 40% C; 6.7% H; 53.3% O.
Chapter 8 Chemical Composition Chemistry B2A. Atomic mass unit (amu) = × g Atomic Weight Atoms are so tiny. We use a new unit of mass:
Determining Chemical Formulas Experimentally % composition, empirical and molecular formula.
Percentage Composition
Empirical and Molecular Formulas
Chapter 3 Percent Compositions and Empirical Formulas
Mass Conservation in Chemical Reactions Mass and atoms are conserved in every chemical reaction. Molecules, formula units, moles and volumes are not always.
Empirical Formula The empirical formula indicates the ratio of the atoms of an element in a compound.
4.6 MOLECULAR FORMULAS. 1. Determine the percent composition of all elements. 2. Convert this information into an empirical formula 3. Find the true number.
The Mole: A measurement of Matter
1 Empirical Formulas Honors Chemistry. 2 Formulas The empirical formula for C 3 H 15 N 3 is CH 5 N. The empirical formula for C 3 H 15 N 3 is CH 5 N.
The Mole and Chemical Composition
Empirical and Molecular Formulas
The Mole and Chemical Composition
The Mole Chapter 11 Chemistry RiverDell High School Ms. C. Militano
Percent Comp. Percentage composition Indicates the relative amount of each element present in a compound.
Section 9.3—Analysis of a Chemical Formula
Percent Composition (Section 11.4) Helps determine identity of unknown compound –Think CSI—they use a mass spectrometer Percent by mass of each element.
Empirical Formula The simplest formula that represents the whole number ratio between the elements in a compound.
Empirical and Molecular formulas. Empirical – lowest whole number ratio of elements in a compound Molecular – some multiple of the empirical formula Examples:
Chapter 10 review.
Tis the season to be thankful so lets thank Avogadro for math in Chemistry.
1 Percent Composition: Identifies the elements present in a compound as a mass percent of the total compound mass. The mass percent is obtained by dividing.
Percent Composition Like all percents: Part x 100 % whole Find the mass of each component, divide by the total mass.
1 Chapter 10 “Chemical Quantities” Yes, you will need a calculator for this chapter!
It’s time to learn about.... Stoichiometry: Percent Composition At the conclusion of our time together, you should be able to: 1. Determine the percent.
Unit 6: Chemical Quantities
Percent Composition and Molecular Formulas.  Determining the percent composition of each element in a compound  H 2 O 1. Find the molar mass of the.
Empirical & Molecular Formulas
Unit Empirical and Molecular Formulas. Empirical Formulas Consists of the symbols for the elements combined in a compound, with subscripts showing.
Empirical Formula vs. Molecular Formula Empirical formula: the formula for a compound with the smallest whole-number mole ratio of the elements Molecular.
IIIIII Formula Calculations The Mole. A. Percentage Composition n the percentage by mass of each element in a compound.
Ch. 11 The Mole The Mol House The Mol House Atoms in a molecule molecules molgrams Molar Mass Avogadro’s number Chemical formula.
Empirical & Molecular Formulas. Percent Composition Def – the percent by mass of each element in a compound Percent by mass = mass of element x 100 mass.
Chapter 7 “Chemical Formulas and Chemical Compounds” Yes, you will need a calculator for this chapter!
Empirical & Molecular Formulas. Percent Composition Determine the elements present in a compound and their percent by mass. A 100g sample of a new compound.
(4.6/4.7) Empirical and Molecular Formulas SCH 3U.
Calculating Empirical Formula Using percentage or mass to find the Empirical Formula.
CHEMISTRY CHAPTER 7 SECTIONS 3-4 SECTION 3. USING CHEMICAL FORMULAS Introduction A chemical formula indicates: the elements present in a compound the relative.
Molecular Weight, Percent Composition, Empirical Formula.
Calculating Empirical Formulas
Percent Composition, Empirical Formula and Molecular Formula.
Percentage Composition Sec 7.3. Percentage Composition Review –What does the formula H 2 O tell us? –What does % mean? –You get 7 out of 10 on a test.
Empirical and Molecular Formulas Topic #20. Empirical and Molecular Formulas Empirical --The lowest whole number ratio of elements in a compound. Molecular.
IIIIII II. % Composition and Formula Calculations Ch. 3 – The Mole.
Percent Composition, Empirical and Molecular Formulas.
THE MOLE CHAPTER 10 Chemistry Class Mrs. Gonsalves.
Chapter 7 “Chemical Formulas and Chemical Compounds”
Section 9.3—Analysis of a Chemical Formula
Empirical Formula.
EMPIRICAL FORMULA VS. MOLECULAR FORMULA .
% Composition & Empirical Formulas
Empirical and Molecular Formulas
DO NOW Pick up notes. Get out your periodic table and calculator.
Section 9.3—Analysis of a Chemical Formula
Percent Composition Empirical Formula Molecular Formula
Empirical and Molecular Formulas
FORMULA NUMBER OF MOLES GIVEN WEIGHT MOLAR MASS = GW MM n =
Section 9.3—Analysis of a Chemical Formula
TYPES OF FORMULA.
Emperical Formula.
Chemical Composition Mole (mol) – The number equal to the number of carbon atoms in grams of carbon. Avogadro’s number – The number of atoms in exactly.
Empirical & Molecular Formulas
Empirical and Molecular Formulas
Chapter 7- Sec. 3 and 4 “Chemical Formulas and Chemical Compounds”
Molecular Formula.
Presentation transcript:

Section 9.3—Analysis of a Chemical Formula How can we determine a chemical formula?

Percent Composition

What is Percent Composition?

Example #1 Example: A 8.5 g sample is composed of carbon and hydrogen. If 5.5 g of the sample is found to be carbon, what is the percent composition by mass of the sample?

Example #1 If total = 8.5 g and C = 5.5 g then H =3.0 g - Example: A 8.5 g sample is composed of carbon and hydrogen. If 5.5 g of the sample is found to be carbon, what is the percent composition by mass of the sample?

Let’s Practice #1 A sample is 57.0% by mass chlorine, how many grams of chlorine are present in a 27.5 g sample?

Let’s Practice #1  27.5 g27.5 g  100 A sample is 57.0% by mass chlorine, how many grams of chlorine are present in a 27.5 g sample?

Example #2 Percent composition can also be determined from a chemical formula Example: Find the percent composition, by mass, of CaCl 2

Example #2 Percent composition can also be determined from a chemical formula total = g Ca = g Cl =70.90 g Ca Cl g/mole g/mole  = g/mole = g/mole g/mole  So for 1 mole: Example: Find the percent composition, by mass, of CaCl 2

Let’s Practice #2 Find the percent composition, by mass, of NaNO 3

Let’s Practice #2 Find the percent composition, by mass, of NaNO 3 Na N g/mole g/mole  = g/mole = g/mole g/mole  O g/mole  = g/mole

Empirical Formulas

What’s an Empirical Formula? Empirical – from data Empirical Formula – Chemical formula determined from lab data. Lowest possible ratio of atoms CH 2 is the lowest ratio (and empirical formula) of the molecule C 3 H 6

Ratio of Atoms in a Molecule Subscripts in a chemical formula show the ratio of atoms (or ions) in a molecule a sample of CaCl 2 has 1 calcium ion : 2 chlorine ions We can use the unit “mole” to count things Atoms and ions can be counted by “moles” If the subscripts give the ratio of atoms, then they also give the ratio of moles of atoms a sample of CaCl 2 has 1 mole of calcium ions : 2 moles of chlorine ions

Using Mole Ratio of Atoms in a Molecule Therefore, if the ratio of moles of each atom is found… then the subscripts of the chemical formula are known 1 mole C 2 mole H CH 2

Example #3 If given percents, use those percents as grams (as if you assume you have a 100 g sample)—Remember %’s add up to 100! Change grams to moles for each atom Find the lowest possible whole number ratio of the atom (divide all moles by the smallest # of moles) Use the ratio as subscripts for writing the chemical formula Example: Find the empirical formula if a sample contains Ca and Cl and is 36.1% Ca

Example #3 If given percents, use those percents as grams (as if you assume you have a 100 g sample)—Remember %’s add up to 100! Change grams to moles for each atom Find the lowest possible whole number ratio of the atom (divide all moles by the smallest # of moles) Use the ratio as subscripts for writing the chemical formula g Ca = _____ mol Ca g Ca mol Ca g Cl = _____ mol Cl g Cl mol Cl mol Ca = 1 mol Ca mol Cl = 2 mol Cl CaCl 2 Example: Find the empirical formula if a sample contains Ca and Cl and is 36.1% Ca

Let’s Practice # g C = _____ mol C g C mol C g H = _____ mol H g H mol H mol C = 1 mol C mol H = 1.33 mol H 3.41 C3H4O3C3H4O g O = _____ mol O g O mol O mol O = 1 mol O 3.41 Multiply the ratio (1 : 1.33 : 1) by 3 to make a whole number ratio (3 : 4: 3) Find the empirical formula if a sample contains g C, 4.58 g H and 54.5 g O

Molecular Formulas

What’s a Molecular Formula? Empirical Formula – Chemical formula determined from lab data. Lowest possible ratio of atoms Molecular Formula – Actual ratio of atoms in a molecule

Empirical versus Molecular Formula The empirical formula is the lowest possible ratio. A molecule with the empirical formula: Could have one of the following molecular formulas: NO 2 NO 2, N 2 O 4, N 4 O 8 … CH 2 CH 2, C 2 H 4, C 4 H 8 … The molecular formula is the actual ratio

Example #4 Find the empirical formula, if not given Find the molar mass of the empirical formula Find the ratio of the molecular formula’s molar mass (must be given to you) to the empirical formula’s molar mass Multiply the empirical formula’s subscripts by the ratio found in step Example: Empirical formula = C 3 H 4 O 3. The molecular formula’s molar mass = g/mole. Find the molecular formula.

Example #4 Find the empirical formula, if not given Find the molar mass of the empirical formula Find the ratio of the molecular formula’s molar mass (must be given to you) to the empirical formula’s molar mass Multiply the empirical formula’s subscripts by the ratio found in step C3H4O3C3H4O g/mole = g/mole g/mole g/mole   = g/mole = g/mole g/mole g/mole  = 4.04 g/mole C O H  2 C6H8O6C6H8O6 Example: Empirical formula = C 3 H 4 O 3. The molecular formula’s molar mass = g/mole. Find the molecular formula.

Hydrate Formulas

What’s a Hydrate? Hydrate – Molecule that has water physically attached to it It’s not dissolved in water…hydrates can be solid, liquid or gas! BaI 2  2 H 2 O This means there are 2 water molecules attached to each BaI 2 molecules

Hydrate & anhydride Hydrate = molecule with water molecules physically attached anhydride = molecule with water removed  The water can be removed by heating the hydrate Hydrate anhydride + water heat Finding the ratio of anhydride molecules to water molecules gives you the hydrate formula

Example #5 Find the mass of anhydride & water if not given Change mass of anhydride & water to moles Find the ratio of the moles water to moles anhydride Write the hydrate formula Example: 2.46 g MgSO 4 hydrate is heated and 1.20 g MgSO 4 anhydride is left. Find the hydrate formula.

Example #5 Find the mass of anhydride & water if not given Change mass of anhydride & water to moles Find the ratio of the moles water to moles anhydride Write the hydrate formula Example: 2.46 g MgSO 4 hydrate is heated and 1.20 g MgSO 4 anhydride is left. Find the hydrate formula g MgSO 4 = _______ mol MgSO 4 g MgSO 4 mol MgSO g H 2 O = _______ mol H 2 O g H 2 O mol H 2 O mol H 2 O = mole MgSO 4 MgSO 4  7 H 2 O Hydrate = anhydride + water 2.46 g = 1.20 g + water Water = 1.26 g

What did you learn about forensic chemistry?

Forensic Chemistry Analyze a sample Often wants to Solubility & Precipitation Solutions Chromatography Mixtures Compound Empirical & Molecular formulas