Multipole Moments Section 41. Expand potential  in powers of 1/R 0.

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Presentation transcript:

Multipole Moments Section 41

Expand potential  in powers of 1/R 0.

The exact potential is Taylor expansion

Quadrupole potential We can set r = 0 before taking the derivative r = 0

The quadrupole potential has two factors The factor  a x  x  is a symmetric tensor. It is given by the coordinates of all of the charges. A symmetric tensor has 6 independent quantities. The rest of  (2) depends only on the field point R 0. ARE THERE REALLY 6?

The potential of a point charge satisfies Laplace’s equation and so We can add this zero to  (2) without changing it. And we can multiply it first by and then add it.

The factor that characterizes the charge distribution is now a different symmetric tensor:

The advantage of the new tensor is that it has zero trace. Trace Therefore D  has only 5 independent quantities. is an equation that allows one of the 6 quantities to be expressed as a combination of the other 5.

Depends on 5 quantities that characterize the charge distribution. Unit vector in the direction of the field point.

Every 3-D symmetric tensor can be diagonalized by finding principal axes. Since D  = 0, only two principle axes are independent.

Suppose charges are symmetric about z Then z is a principle axis. Other two axes lie in the x-y plane. Their location is arbitrary. D xx = D yy = -D zz /2 Let D zz be defined as “D”. Now we can express  (2) as product of D and P 2 (cos  ), a Legendre polynomial.

Legendre Polynomial

From theory of spherical harmonics x Law of cosines Field point Addition theorem Associated Legendre polynomials

Spherical functions Note typos in book

2 l -pole moment in spherical coordinates 2l + 1 independent quantities Characterizes the charge distribution __________ Monopole Dipole Quadrupole

Relations between Cartesian and spherical expressions for dipole and quadrupole moments Note typo in the book