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Topological Structures in the Julia Sets of Rational Maps Dynamics of the family of complex maps Paul Blanchard Mark Morabito Toni Garijo Monica Moreno.

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Presentation on theme: "Topological Structures in the Julia Sets of Rational Maps Dynamics of the family of complex maps Paul Blanchard Mark Morabito Toni Garijo Monica Moreno."— Presentation transcript:

1 Topological Structures in the Julia Sets of Rational Maps Dynamics of the family of complex maps Paul Blanchard Mark Morabito Toni Garijo Monica Moreno Rocha Matt HolzerKevin Pilgrim U. Hoomiforgot Elizabeth Russell Dan LookYakov Shapiro Sebastian MarottaDavid Uminsky with:

2 Three different types of topological objects: 1. Cantor Necklaces A Cantor necklace is a planar set that is homeomorphic to the Cantor middle thirds set with open disks replacing removed intervals.

3 Three different types of topological objects: 1. Cantor Necklaces dynamical plane n = 2

4 Three different types of topological objects: 1. Cantor Necklaces dynamical plane n = 2

5 Three different types of topological objects: 1. Cantor Necklaces dynamical plane n = 2

6 Three different types of topological objects: 1. Cantor Necklaces dynamical plane parameter plane n = 2

7 Three different types of topological objects: 2. Mandelpinski Necklaces Infinitely many simple closed curves in the parameter plane that pass alternately through centers of “Sierpinski holes” and centers of baby Mandelbrot sets.

8 Three different types of topological objects: 2. Mandelpinski Necklaces parameter planezoom in n = 3

9 Three different types of topological objects: 3. CanManPinski Trees A tree of Cantor necklaces with Mandelbrot sets interspersed between each branch

10 Three different types of topological objects: 3. CanManPinski Trees parameter plane n = 2

11 Three different types of topological objects: 3. CanManPinski Trees parameter plane n = 2

12 Dynamics of complex and The Julia set is: The closure of the set of repelling periodic points; The boundary of the escaping orbits; The chaotic set. The Fatou set is the complement of.

13 When, the Julia set is the unit circle

14 When, the Julia set is the unit circle

15 When, the Julia set is the unit circle

16 When, the Julia set is the unit circle

17 When, the Julia set is the unit circle

18 When, the Julia set is the unit circle

19 When, the Julia set is the unit circle

20 When, the Julia set is the unit circle

21 When, the Julia set is the unit circle

22 When, the Julia set is the unit circle

23 When, the Julia set is the unit circle

24 When, the Julia set is the unit circle

25 When, the Julia set is the unit circle

26 When, the Julia set is the unit circle

27 When, the Julia set is the unit circle

28 When, the Julia set is the unit circle

29 When, the Julia set is the unit circle

30 When, the Julia set is the unit circle

31 When, the Julia set is the unit circle

32 When, the Julia set is the unit circle

33 When, the Julia set is the unit circle

34 When, the Julia set is the unit circle

35 When, the Julia set is the unit circle

36 When, the Julia set is the unit circle

37 When, the Julia set is the unit circle

38 When, the Julia set is the unit circle

39 When, the Julia set is the unit circle

40 When, the Julia set is the unit circle

41 When, the Julia set is the unit circle

42 When, the Julia set is the unit circle

43 When, the Julia set is the unit circle

44 When, the Julia set is the unit circle

45 When, the Julia set is the unit circle

46 When, the Julia set is the unit circle

47 When, the Julia set is the unit circle

48 When, the Julia set is the unit circle

49 When, the Julia set is the unit circle

50 When, the Julia set is the unit circle

51 When, the Julia set is the unit circle

52 When, the Julia set is the unit circle

53 When, the Julia set is the unit circle

54 When, the Julia set is the unit circle

55 When, the Julia set is the unit circle

56 When, the Julia set is the unit circle

57 When, the Julia set is the unit circle

58 When, the Julia set is the unit circle

59 When, the Julia set is the unit circle

60 But when, the Julia set explodes When, the Julia set is the unit circle

61 But when, the Julia set explodes A Sierpinski curve When, the Julia set is the unit circle

62 But when, the Julia set explodes Another Sierpinski curve When, the Julia set is the unit circle

63 But when, the Julia set explodes Also a Sierpinski curve When, the Julia set is the unit circle

64 A Sierpinski curve is any planar set that is homeomorphic to the Sierpinski carpet fractal. The Sierpinski Carpet Sierpinski Curve

65 Easy computations: 2n free critical points

66 Easy computations: 2n free critical points

67 Easy computations: 2n free critical points Only 2 critical values

68 Easy computations: 2n free critical points Only 2 critical values

69 Easy computations: 2n free critical points Only 2 critical values

70 Easy computations: 2n free critical points Only 2 critical values But really only 1 free critical orbit since the map has 2n-fold symmetry

71 Easy computations: is superattracting, so have immediate basin B mapped n-to-1 to itself. B

72 Easy computations: is superattracting, so have immediate basin B mapped n-to-1 to itself. B T 0 is a pole, so have trap door T mapped n-to-1 to B.

73 Easy computations: is superattracting, so have immediate basin B mapped n-to-1 to itself. B 0 is a pole, so have trap door T mapped n-to-1 to B. T So any orbit that eventually enters B must do so by passing through T.

74 The Escape Trichotomy B is a Cantor set T is a Cantor set of simple closed curves T is a Sierpinski curve There are three distinct ways the critical orbit can enter B: (this case does not occur if n = 2) (with Dan Look & David Uminsky)

75 B is a Cantor set parameter plane when n = 3 Case 1:

76 B is a Cantor set parameter plane when n = 3 J is a Cantor set

77 B is a Cantor set parameter plane when n = 3 J is a Cantor set

78 B is a Cantor set parameter plane when n = 3 J is a Cantor set

79 B is a Cantor set parameter plane when n = 3 J is a Cantor set

80 B is a Cantor set parameter plane when n = 3 J is a Cantor set

81 B is a Cantor set parameter plane when n = 3 J is a Cantor set

82 B is a Cantor set parameter plane when n = 3 J is a Cantor set

83 B is a Cantor set parameter plane when n = 3 J is a Cantor set

84 B is a Cantor set parameter plane when n = 3 J is a Cantor set

85 B is a Cantor set parameter plane when n = 3 J is a Cantor set

86 B is a Cantor set parameter plane when n = 3 J is a Cantor set

87 B is a Cantor set parameter plane when n = 3 J is a Cantor set

88 parameter plane when n = 3 Case 2: the critical values lie in T, not B

89 T parameter plane when n = 3 lies in the McMullen domain

90 T parameter plane when n = 3 J is a Cantor set of simple closed curves lies in the McMullen domain Remark: There is no McMullen domain in the case n = 2.

91 T parameter plane when n = 3 J is a Cantor set of simple closed curves lies in the McMullen domain

92 T parameter plane when n = 3 J is a Cantor set of simple closed curves lies in the McMullen domain

93 T parameter plane when n = 3 J is a Cantor set of simple closed curves lies in the McMullen domain

94 T parameter plane when n = 3 J is a Cantor set of simple closed curves lies in the McMullen domain

95 T parameter plane when n = 3 J is a Cantor set of simple closed curves lies in the McMullen domain

96 T parameter plane when n = 3 J is a Cantor set of simple closed curves lies in the McMullen domain

97 T parameter plane when n = 3 lies in a Sierpinski hole Case 3: the critical orbit eventually lands in the trap door.

98 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

99 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

100 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

101 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

102 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

103 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

104 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

105 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

106 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

107 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

108 T parameter plane when n = 3 J is a Sierpinski curve lies in a Sierpinski hole

109 1.Cantor necklaces in the dynamical and parameter plane The Cantor necklace is homeomorphic to the Cantor middle thirds set with open disks replacing removed intervals.

110 1.Cantor necklaces in the dynamical and parameter plane Julia set n = 2 = -0.23 The Cantor necklace is homeomorphic to the Cantor middle thirds set with open disks replacing removed intervals.

111 1.Cantor necklaces in the dynamical and parameter plane parameter plane n = 4 The Cantor necklace is homeomorphic to the Cantor middle thirds set with open disks replacing removed intervals.

112 Dynamical plane: n = 2 Suppose B and T are disjoint. B T

113 Dynamical plane: n = 2 Four critical points 1/4

114 Dynamical plane: n = 2 And two critical values that do not lie in T 2 1/2

115 Dynamical plane: n = 2 The critical lines...

116 Dynamical plane: n = 2 are mapped two-to-one to one of two critical value rays

117 So the sectors S 0 and S 1 are mapped one-to-one to C - {critical value rays) S1S1 S0S0

118 And the regions I 0 - T and I 1 - T are mapped one-to-one to C - B - {critical value rays) Dynamical plane: n = 2 I1I1 I0I0

119 And the regions I 0 - T and I 1 - T are mapped one-to-one to C - B - {critical value rays) Dynamical plane: n = 2

120 I1I1 I0I0 So consider the bow-tie I 0  T  I 1 T

121 Dynamical plane: n = 2 I1I1 I0I0 Both I 0 and I 1 are mapped one-to-one over the entire bow-tie I 0  T  I 1 T

122 Dynamical plane: n = 2 So we have a preimage of the bow-tie inside each of I 0 and I 1 T

123 Dynamical plane: n = 2 Then a second preimage, etc., etc. T

124 Dynamical plane: n = 2 The points whose orbits stay in I 0  I 1 form a Cantor set, and the preimages of T give the adjoined disks. T

125 Dynamical plane: n = 2 The points whose orbits stay in I 0  I 1 form a Cantor set, and the preimages of T give the adjoined disks.

126 Cantor Necklaces in the Parameter Plane c = 1/4 v = 2 1/2 F (v ) = 1/4 + 4 D = { | | | < 1, Re( ) < 0} D

127 For each  D, have a Cantor set of points inside I 1 I1I1 I0I0 T........:...

128 I1I1 I0I0 T For each  D, have a Cantor set of points inside I 1........:... Let z s ( ) be the point in the Cantor set with itinerary s z s ( )

129 I1I1 I0I0 T For each  D, have a Cantor set of points inside I 1........:... Let z s ( ) be the point in the Cantor set with itinerary s z s ( ) z s ( ) depends analytically on and continuously on s

130 I1I1 I0I0 T For each  D, have a Cantor set of points inside I 1........:... Let z s ( ) be the point in the Cantor set with itinerary s z s ( ) and z s ( ) lies in the half-disk H given by |z| < 2, Re(z) < 0 H z s ( ) depends analytically on and continuously on s

131 So have an analytic map  z s ( ) that takes D into H z s ( ) D H

132 So have an analytic map  z s ( ) that takes D into H z s ( ) D H Have another map  G( ) = F (v ) = 1/4 + 4 which maps D over a larger half disk containing H G( )

133 So have an analytic map  z s ( ) that takes D into H z s ( ) D H Have another map  G( ) = F (v ) = 1/4 + 4 which maps D over a larger half disk containing H G -1 But G is invertible.

134 So have an analytic map  z s ( ) that takes D into H z s ( ) D H Have another map  G( ) = F (v ) = 1/4 + 4 which maps D over a larger half disk containing H G -1 But G is invertible. So G -1 (z s ( )) maps D strictly inside itself.

135 z s ( ) D H G -1 By the Schwarz Lemma, for each itinerary s there is a unique fixed point s for the map G -1 (z s ( )). s

136 z s ( ) D H This is a parameter for which G( s ) = z s ( s ), i.e., the second iterate of the critical points lands on a point in the Cantor set portion of the Cantor necklace. G -1 By the Schwarz Lemma, for each itinerary s there is a unique fixed point s for the map G -1 (z s ( )). s z s ( s )

137 z s ( ) D H G -1 So the points s for each s give a Cantor set of points in the parameter plane. s z s ( s )

138 z s ( ) D H G -1 So the points s for each s give a Cantor set of points in the parameter plane. s Similar arguments involving Böttcher coordinates on and itineraries of preimages of the trap door then append the Sierpinski holes to the necklace. z s ( s )

139 This necklace lies along the negative real axis. parameter plane n = 2

140 parameter plane n = 2 There are lots of other Cantor necklaces in the parameter planes.

141 parameter plane n = 2 There are lots of other Cantor necklaces in the parameter planes.

142 parameter plane n = 2 There are lots of other Cantor necklaces in the parameter planes.

143 parameter plane n = 2 There are lots of other Cantor necklaces in the parameter planes.

144 When n > 2, get more complicated Cantor webs case n = 3:

145 When n > 2, get more complicated Cantor webs case n = 3:

146 When n > 2, get more complicated Cantor webs case n = 3:

147 When n > 2, get more complicated Cantor webs case n = 3:

148 When n > 2, get more complicated Cantor webs case n = 3: Continue in this way and then adjoin Cantor sets

149 Parameter plane n = 3 Dynamical plane

150 Parameter plane n = 3 Dynamical plane

151 Parameter plane n = 3 Dynamical plane

152 Parameter plane n = 3 Dynamical plane

153 Parameter plane n = 3 Dynamical plane

154 Parameter plane n = 3 Cantor webs in the parameter plane

155 Parameter plane n = 3 Cantor webs in the parameter plane

156 Parameter plane n = 3 Cantor webs in the parameter plane Parameter plane

157 Parameter plane n = 3 Cantor webs in the parameter plane Parameter plane

158 Parameter plane n = 3 Cantor webs in the parameter plane Parameter plane

159 Parameter plane n = 4 Different Cantor webs when n = 4 Dynamical plane

160 Part 2: Mandelpinski Necklaces

161 Parameter plane for n = 3 A “Mandelpinski necklace” is a simple closed curve in the parameter plane that passes alternately through k centers of baby Mandelbrot sets and k centers of Sierpinski holes.

162 Parameter plane for n = 3 A “Mandelpinski necklace” is a simple closed curve in the parameter plane that passes alternately through k centers of baby Mandelbrot sets and k centers of Sierpinski holes. C 1 passes through the centers of 2 M-sets and 2 S-holes Easy check: C 1 is the circle r = 2 -2n/n-1

163 Parameter plane for n = 3 A “Mandelpinski necklace” is a simple closed curve in the parameter plane that passes alternately through k centers of baby Mandelbrot sets and k centers of Sierpinski holes.

164 Parameter plane for n = 3 A “Mandelpinski necklace” is a simple closed curve in the parameter plane that passes alternately through k centers of baby Mandelbrot sets and k centers of Sierpinski holes. C 2 passes through the centers of 4 M-sets and 4 S-holes * * only exception: 2 centers of period 2 bulbs, not M-sets

165 A “Mandelpinski necklace” is a simple closed curve in the parameter plane that passes alternately through k centers of baby Mandelbrot sets and k centers of Sierpinski holes. Parameter plane for n = 3 C 3 passes through the centers of 10 M-sets and 10 S-holes

166 A “Mandelpinski necklace” is a simple closed curve in the parameter plane that passes alternately through k centers of baby Mandelbrot sets and k centers of Sierpinski holes. Parameter plane for n = 3 C 4 passes through the centers of 28 M-sets and 28 S-holes

167 A “Mandelpinski necklace” is a simple closed curve in the parameter plane that passes alternately through k centers of baby Mandelbrot sets and k centers of Sierpinski holes. Parameter plane for n = 3 C 5 passes through the centers of 82 M-sets and 82 S-holes

168 Theorem: There exist closed curves C j, surrounding the McMullen domain. Each C j passes alternately through (n-2)n j-1 +1 centers of baby Mandelbrot sets and centers of Sierpinski holes.

169 C 14 passes through the centers of 4,782,969 M-sets and S-holes Parameter plane for n = 3 Theorem: There exist closed curves C j, surrounding the McMullen domain. Each C j passes alternately through (n-2)n j-1 +1 centers of baby Mandelbrot sets and centers of Sierpinski holes.

170 Parameter plane for n = 4 C 1 : 3 holes and M-sets Theorem: There exist closed curves C j, surrounding the McMullen domain. Each C j passes alternately through (n-2)n j-1 +1 centers of baby Mandelbrot sets and centers of Sierpinski holes.

171 Parameter plane for n = 4 C 2 : 9 holes and M-sets C 3 : 33 holes and M-sets Theorem: There exist closed curves C j, surrounding the McMullen domain. Each C j passes alternately through (n-2)n j-1 +1 centers of baby Mandelbrot sets and centers of Sierpinski holes. *

172 Easy computations: Critical points: 1/2n Prepoles: (- ) 1/2n

173 Easy computations: All of the critical points and prepoles lie on the “critical circle” : |z| = | | 1/2n

174 All of the critical points and prepoles lie on the “critical circle” : |z| = | | 1/2n which is mapped 2n-to-1 onto the “critical value line” connecting Easy computations:

175 Any other circle around 0 is mapped n-to-1 to an ellipse whose foci are Easy computations:

176 Any other circle around 0 is mapped n-to-1 to an ellipse whose foci are

177 So the exterior of is mapped as an n-to-1 covering of the exterior of the critical value line. Easy computations: Any other circle around 0 is mapped n-to-1 to an ellipse whose foci are

178 So the exterior of is mapped as an n-to-1 covering of the exterior of the critical value line. Same with the interior of. Easy computations: Any other circle around 0 is mapped n-to-1 to an ellipse whose foci are

179 Now assume that lies inside the critical circle: Warning: this is not a real proof....

180 Now assume that lies inside the critical circle: The exterior of is mapped n-to-1 onto the exterior of the critical value ray, so there is a preimage mapped n-to-1 to,

181 Now assume that lies inside the critical circle: The exterior of is mapped n-to-1 onto the exterior of the critical value ray, so there is a preimage mapped n-to-1 to,

182 then is mapped n-to-1 to, Now assume that lies inside the critical circle: The exterior of is mapped n-to-1 onto the exterior of the critical value ray, so there is a preimage mapped n-to-1 to,

183 and on out to Now assume that lies inside the critical circle: then is mapped n-to-1 to, B The exterior of is mapped n-to-1 onto the exterior of the critical value ray, so there is a preimage mapped n-to-1 to,

184 contains 2n critical points and 2n prepoles, so contains 2n 2 pre-critical points and pre-prepoles

185 contains 2n critical points and 2n prepoles, so contains 2n 2 pre-critical points and pre-prepoles B contains 2n k+1 points that map to the critical points and pre-prepoles under

186 contains 2n critical points and 2n prepoles, so contains 2n 2 pre-critical points and pre-prepoles contains 2n k+1 points that map to the critical points and pre-prepoles under n = 3

187 contains 2n critical points and 2n prepoles, so contains 2n 2 pre-critical points and pre-prepoles contains 2n k+1 points that map to the critical points and pre-prepoles under n = 3

188 contains 2n critical points and 2n prepoles, so contains 2n 2 pre-critical points and pre-prepoles contains 2n k+1 points that map to the critical points and pre-prepoles under n = 3

189 As rotates by one turn, these 2n k+1 points on each rotate by 1/2n k+1 of a turn.

190 Since the second iterate of the critical points rotate by 1 - n/2 of a turn As rotates by one turn, these 2n k+1 points on each rotate by 1/2n k+1 of a turn.

191 Since the second iterate of the critical points rotate by 1 - n/2 of a turn, so this point hits exactly preimages of the critical points and prepoles on As rotates by one turn, these 2n k+1 points on each rotate by 1/2n k+1 of a turn.

192 There is a natural parametrization of each The real proof involves the Schwarz Lemma (as before):

193 There is a natural parametrization of each The real proof involves the Schwarz Lemma (as before): Best to restrict to a “symmetry region” inside the circle C 1, so that is well-defined.

194 Best to restrict to a “symmetry region” inside the circle C 1, so that is well-defined. Then we have a second map from the parameter plane to the dynamical plane, namely which is invertible on the symmetry sector

195 Then we have a second map from the parameter plane to the dynamical plane, namely which is invertible on the symmetry sector a map from a “disk” to itself. So consider the composition

196 a map from a “disk” to itself. So consider the composition Schwarz implies that has a unique fixed point, i.e., a parameter for which the second iterate of the critical point lands on the point, so this proves the existence of lots of parameters for which the critical orbits are periodic and land on 0.

197 Remarks: 1. This proves the existence of centers of Sierpinski holes and Mandelbrot sets. Producing the entire M-set involves polynomial-like maps; while the entire S-hole involves qc-surgery.

198 Remarks: 1. This proves the existence of centers of Sierpinski holes and Mandelbrot sets. Producing the entire M-set involves polynomial-like maps; while the entire S-hole involves qc-surgery. 2.It is known that each S-hole in the Mandelpinski necklace is also surrounded by infinitely many sub-necklaces, which in turn are surrounded by sub-sub-necklaces, etc.

199 n = 3

200 3. CanManPinski Trees A tree of Cantor necklaces with Mandelbrot sets interspersed between each branch parameter plane n = 2

201 Dynamical plane: n = 2 I1I1 I0I0 Recall that we have a Cantor necklace in the dynamical plane lying in I 0  T  I 1

202 Dynamical plane: n = 2 I1I1 I0I0 The regions I 2 and I 3 are mapped one-to-one over I 0  T  I 1, so there are Cantor necklaces in I 2 and I 3 I2I2 I3I3

203 Dynamical plane: n = 2 I1I1 I0I0 I2I2 I3I3 The regions I 2 and I 3 are mapped one-to-one over I 0  T  I 1, so there are Cantor necklaces in I 2 and I 3

204 This necklace is mapped one-to-one onto the original necklace.

205 This necklace is mapped one-to-one onto the original necklace. And so is the bottom necklace

206 S2S2 S0S0 S1S1 S3S3 Now consider the regions S j.

207 S2S2 S0S0 S1S1 S3S3 S 0 is mapped two-to-one onto S 0  S 1

208 S2S2 S0S0 S1S1 S3S3 Now consider the regions S j. S 0 is mapped two-to-one onto S 0  S 1 Similarly, S 1  S 2  S 3, S 2  S 0  S 1 and S 3  S 2  S 3

209 S2S2 S0S0 S1S1 S3S3 Assuming lies in the upper half plane, the critical values  v lie in S 0 and S 2 (easy check) v -v

210 S2S2 S0S0 S1S1 S3S3 Assuming lies in the upper half plane, the critical values  v lie in S 0 and S 2 (easy check) So there is a region in S 3 mapped one-to-one onto S 3. v -v

211 S2S2 S0S0 S1S1 S3S3 So there is a preimage of this Cantor necklace in S 3 v -v

212 S2S2 S0S0 S1S1 S3S3 So there is a preimage of this Cantor necklace in S 3, v -v

213 S2S2 S0S0 S1S1 S3S3 So there is a preimage of this Cantor necklace in S 3, and then another preimage, v -v

214 S2S2 S0S0 S1S1 S3S3 So there is a preimage of this Cantor necklace in S 3, and then another preimage, and so on, yielding infinitely many necklaces eventually mapping to the original necklace. Looking like branches of a tree.... v -v

215 S2S2 S0S0 S1S1 S3S3 By symmetry, we have similar branches in S 1 v -v

216 S2S2 S0S0 S1S1 S3S3 By symmetry, we have similar branches in S 1, S 0,

217 S2S2 S0S0 S1S1 S3S3 By symmetry, we have similar branches in S 1, S 0, and S 2

218 This produces trees of Cantor necklaces in the dynamical plane

219

220 Assuming is in the upper half plane, we can again use G( ) = 1/4 + 4 and an appropriate coding of points in the necklace, and then the Schwarz Lemma produces a similar tree in the upper half of the parameter plane.

221 Symmetry under complex conjugation yields a similar tree in the lower half-plane.

222 Then polynomial-like map theory produces a Mandelbrot set in each region in between the branches.

223 Open problems: Can we use these trees to give a complete map of the Sierpinski-hole regions and buried parameters in the parameter planes? Same question for the baby Mandelbrot sets. Using “Yoccoz puzzles,” do these trees allow us to see that the boundary of the parameter plane locus is a simple closed curve?

224 Open problems: Can we use these trees to give a complete map of the Sierpinski-hole regions and buried parameters in the parameter planes? Same question for the baby Mandelbrot sets. Using “Yoccoz puzzles,” do these trees allow us to see that the boundary of the parameter plane locus is a simple closed curve? Would it be better to call these things Cantormandelbrotsierpinski trees?

225 Open problems: Can we use these trees to give a complete map of the Sierpinski-hole regions and buried parameters in the parameter planes? Same question for the baby Mandelbrot sets. Using “Yoccoz puzzles,” do these trees allow us to see that the boundary of the parameter plane locus is a simple closed curve? Would it be better to call these things Cantormandelbrotsierpinski trees? Who the hell is this?

226 Parameter plane (rotated) when n = 2

227 Other topics: Main cardioid of a buried baby M-set Perturbed rabbit Convergence to the unit disk Major application

228 If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve. n = 4

229 If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

230 n = 4 If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

231 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

232 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

233 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

234 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

235 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

236 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

237 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

238 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

239 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

240 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

241 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

242 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones.

243 n = 4 A Sierpinski curve, but very different dynamically from the earlier ones. If lies in the main cardioid of a buried Mandelbrot set, then again the Julia set is a Sierpinski curve.

244 Consider the family of maps where c is the center of a hyperbolic component of the Mandelbrot set.

245 Consider the family of maps where c is the center of a hyperbolic component of the Mandelbrot set.

246 Consider the family of maps where c is the center of a hyperbolic component of the Mandelbrot set.

247 , the Julia set again expodes.When

248 , the Julia set again expodes.When

249 , the Julia set again expodes.When

250 , the Julia set again expodes.When

251 , the Julia set again expodes.When A doubly-inverted Douady rabbit.

252 If you chop off the “ears” of each internal rabbit in each component of the original Julia set, then what’s left is another Sierpinski curve (provided that both of the critical orbits eventually escape).

253

254 The case n = 2 is very different from (and much more difficult than) the case n > 2. n = 3 n = 2

255 One difference: there is a McMullen domain when n > 2, but no McMullen domain when n = 2 n = 3 n = 2

256 One difference: there is a McMullen domain when n > 2, but no McMullen domain when n = 2 n = 3 n = 2

257 There is lots of structure when n > 2, but what is going on when n = 2? n = 3 n = 2

258 There is lots of structure when n > 2, but what is going on when n = 2? n = 3 n = 2

259 There is lots of structure when n > 2, but what is going on when n = 2? n = 3 n = 2

260 Also, not much is happening for the Julia sets near 0 when n > 2 n = 3

261 The Julia set is always a Cantor set of circles. n = 3

262 The Julia set is always a Cantor set of circles.

263 The Julia set is always a Cantor set of circles. There is always a round annulus of some fixed width in the Fatou set, so the Julia set does not converge to the unit disk.

264 n = 2 But when n = 2, lots of things happen near the origin; in fact, the Julia sets converge to the unit disk as disk-converge

265 Here’s the parameter plane when n = 2:

266 Rotate it by 90 degrees: and this object appears everywhere.....

267


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