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Create a FBD that represents the situation below 2 ropes are holding the object up and the object is motionless F g (E, B) F t1 (R, B)F t2 (R, B) Should.

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Presentation on theme: "Create a FBD that represents the situation below 2 ropes are holding the object up and the object is motionless F g (E, B) F t1 (R, B)F t2 (R, B) Should."— Presentation transcript:

1 Create a FBD that represents the situation below 2 ropes are holding the object up and the object is motionless F g (E, B) F t1 (R, B)F t2 (R, B) Should the forces be balanced? Yes, because the object is motionless (constant velocity) Therefore, net force = 0 But this is different than any of the other problems we have done because for the first time, we’ve encountered a scenario where it’s not completely obvious to the eye exactly how the forces balance Balanced (obvious to the eye) Balanced (not so obvious to the eye)

2 = + 2-D force vector (up & to the right) Any vector directed in 2 dimensions can be thought of as having an influence in 2 different directions Made up of 2 parts Each part of a 2-D vector is known as a component vector The combined influence of the 2 components is equal to the influence of the single 2-D vector Therefore, we can replace the 2-D vector with the component vectors Component vectors 2 horizontal component vectors cancel (balanced) 2 vertical component vectors cancel downward vector (balanced) Much more obvious to the eye how the forces balance

3 Now try to create the FBD of this situation Object is motionless on an incline F g (E, B) F N (R, B) F f (R, B) Remember, normal force is perpendicular to surface Remember, friction force is parallel to surface We know that the force should balance since the object is motionless (constant velocity) Net force = 0 F g (E, B) F N (R, B) F f (R, B) Fg perp. Fg parallel

4 Object slides without friction We know that the forces must be unbalanced because the problem does not state that the object is going at a constant velocity We know from past experience that objects going down ramp accelerate Net force not equal to 0 F N (T, B) F g (E, B) Fg F net = 0 Fg By displaying this, we are 100% sure the force that is responsible for this accelerated motion and in what direction VERY IMPORTANT FOR OUR UNDERSTANDING OF MOTION!


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