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Ch. 11 Motion & Forces II. Describing Motion Acceleration

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C. Acceleration Acceleration the rate of change of velocity change in speed or direction a: acceleration v f : final velocity v i : initial velocity t: time a v f - v i t

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Acceleration This formula is used to find the acceleration of an object moving in a straight line.

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C. Acceleration Positive acceleration “speeding up” Negative acceleration “slowing down” Centripetal Acceleration “In a circular motion”

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D. Calculations A roller coaster starts down a hill at 10 m/s. Three seconds later, its speed is 32 m/s. What is the roller coaster’s acceleration? GIVEN: v i = 10 m/s t = 3 s v f = 32 m/s a = ? WORK : a = ( v f - v i ) ÷ t a = (32m/s - 10m/s) ÷ (3s) a = 22 m/s ÷ 3 s a = 7.3 m/s 2 a v f - v i t

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D. Calculations How long will it take a car traveling 30 m/s to come to a stop if its acceleration is -3 m/s 2 ? GIVEN: t = ? v i = 30 m/s v f = 0 m/s a = -3 m/s 2 WORK : t = ( v f - v i ) ÷ a t = (0m/s-30m/s)÷(-3m/s 2 ) t = -30 m/s ÷ -3m/s 2 t = 10 s a v f - v i t

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E. Graphing Motion slope = steeper slope = straight line = flat line = Distance-Time Graph A B faster speed constant speed no motion speed

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E. Graphing Motion Who started out faster? A (steeper slope) Who had a constant speed? AA Describe B from 10-20 min. B stopped moving Find their average speeds. A = (2400m) ÷ (30min) A = 80 m/min B = (1200m) ÷ (30min) B = 40 m/min Distance-Time Graph A B

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E. Graphing Motion Acceleration is indicated by a curve on a Distance-Time graph. Changing slope = changing velocity

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E. Graphing Motion Speed-Time Graph slope = straight line = flat line = acceleration +ve = speeds up -ve = slows down constant accel. no accel. (constant velocity)

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E. Graphing Motion Speed-Time Graph Specify the time period when the object was... slowing down 5 to 10 seconds speeding up 0 to 3 seconds moving at a constant speed 3 to 5 seconds not moving 0 & 10 seconds

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