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The State of the Atmosphere 1.Atmospheric mass and pressure 2.Temperature structure 3.Geopotential 4.Circulation 5.Water in the atmosphere.

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Presentation on theme: "The State of the Atmosphere 1.Atmospheric mass and pressure 2.Temperature structure 3.Geopotential 4.Circulation 5.Water in the atmosphere."— Presentation transcript:

1 The State of the Atmosphere 1.Atmospheric mass and pressure 2.Temperature structure 3.Geopotential 4.Circulation 5.Water in the atmosphere

2 Atmospheric mass and pressure From the equation of continuity, after integration for a polar cap limited by  In the long-term mean: Assuming that the atmosphere is a ideal gas (p=  RT) in hydrostatic equilibrium we have and by integrating: We can then rewrite the first equation as:(1)

3 The rapid decrease of density with height distinguishes the atmosphere from the ocean

4 Distribution of mass in terms of pressure

5 If H_surf=2.56x10 14 m 2 P North_h =983.6mb, P South_h =988.0mb, P Globe =983.6mb g=9.8 m/s 2 Then m_ North_h =2.57x10 18 kg m_ Souh_h =2.58x10 18 kg m_ Globe =5.15x10 18 kg...Distribution of mass in terms of pressure

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7 The interhemispheric transport From Eq. (1) we can calculate the transport trough the equator: If  p=1mb/month

8 Global distribution of temperature

9 Vertical and meridional change

10 Temporal variability of temperature

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12 Geopotential heights

13 Mean circulation

14 Correlation coefficient between northern hemisphere stratospheric geopotential at 50hPa and an index representing the tropospheric 500hPA NAO.

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17 Hadley model Hadley (1735) wanted to explain trade wind circulation Complements of E. Kant and J. Dalton Ferel (1856): Coriolis force and Geostrophic wind Helmholtz: the role of friction-deviation of wind includes turbulent viscosity for the first time

18 Actual vertical circulation

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20 Kinetic energy of the atmosphere K=K TE +K SE +K M K=0.5[u 2 m +v 2 m ] K TE =0.5[(u‘ 2 +v‘ 2 ) m ] K SE =0.5[u m *2 +v m *2 ] K M =0.5([u m ] 2 +[v m ] 2 )

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23 Precipitation

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