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Net Ionic Equations (8-4) Show only the species (atoms/ions) participating in a reaction o Single displacement reaction – exchange electrons o Double displacement.

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Presentation on theme: "Net Ionic Equations (8-4) Show only the species (atoms/ions) participating in a reaction o Single displacement reaction – exchange electrons o Double displacement."— Presentation transcript:

1 Net Ionic Equations (8-4) Show only the species (atoms/ions) participating in a reaction o Single displacement reaction – exchange electrons o Double displacement reaction – form new bonds (ionic or covalent) Steps 1.From formula equation write complete ionic equation use ion symbols for aqueous species use element, formula symbols for (g), (l), (s) 2.Cancel spectator ions (ions not forming new bonds)

2 Can be written for: o Single Displacement Reactions (electron transfer reactions) One spectator ion Charges must balance o Double Displacement Reactions (bond forming reactions) Two spectator ions Charges on reactants side must sum up to zero

3 To predict the products of single-replacement reactions. Refer to the activity series (page 281 or appendix A, page 832) Is the free element above the element to be replaced in the compound? If yes, the reaction will occur Is the free element below the element to be replaced in the compound? If yes, then a reaction will NOT occur The more active an element is, the more likely it will form compounds!

4 Simple Activity Series of Metals K Ca Na Mg Al Zn Fe Ni Pb H 2 Cu Ag Au Increasing Reactivity Decreasing Reactivity Activity Series of Halogens F 2 Cl 2 Br 2 I 2 Increasing Reactivity Decreasing Reactivity

5 Formula Equation: Cu (s) + 2 AgNO 3 (aq)  Cu(NO 3 ) 2 (aq) + 2 Ag (s) Complete Ionic Equation: Cu (s) + 2 Ag 1+ (aq) + 2 NO 3 1- (aq)  Cu 2+ (aq) + 2 NO 3 1- (aq) + 2 Ag (s) Identify Spectator Ion: NO 3 1- is found on both sides of the yields sign and will cancel out. Net Ionic Equation: Cu (s) + 2 Ag 1+ (aq)  Cu 2+ (aq) + 2 Ag (s) Note that charges balance. There are 2(+) charges on the reactants side and 2(+) charges on the products side. Example – Single Displacement Check Activity Series first!

6 A Precipitation Reaction must produce a new solid substance. Use solubility rules (p. 284) to decide whether a precipitation will take place: Reactants are usually all soluble ionic compounds (will dissolve easily in water). If one of the ions from reactant #1 will form an insoluble compound with an ion from reactant #2, a precipitation reaction will take place. (Insoluble means will not dissolve in water.)

7 Some Simple Solubility Rules All compounds of Group 1 and NH 4 + are soluble. All nitrates are soluble. All halides, except those of Ag + and Pb 2+, are soluble. All sulfates, except Ca 2+, Sr 2+, Ba 2+, Hg 2 2+, and Pb 2+ are soluble. All carbonates, except those of Group 1 and NH 4 +, are insoluble. Most hydroxides, except those of Group 1 and NH 4 +, are insoluble.

8 Example – Double Replacement Formula Equation: AgNO 3 (aq) + NaCl (aq)  AgCl + NaNO 3     Complete Ionic Equation: Ag 1+ (aq) + NO 3 1- (aq) + Na 1+ (aq) + Cl 1- (aq)  AgCl (s) + Na 1+ (aq) + NO 3 1- (aq) Identify Spectator Ions: Na 1+ and NO 3 1- are found on both sides of the yields sign and will cancel out. Net Ionic Equation: Ag 1+ (aq) + Cl 1- (aq)  AgCl (s) Note that charges balance. There is a net zero charge [(1+) + (1-)] on the reactants side and zero charge on the products side. (s)(aq)


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