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Erik Jonsson School of Engineering and Computer Science FEARLESS Engineeringwww.utdallas.edu/~pervin EE/CE 2310 – HON/002 Introduction to Digital Systems.

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Presentation on theme: "Erik Jonsson School of Engineering and Computer Science FEARLESS Engineeringwww.utdallas.edu/~pervin EE/CE 2310 – HON/002 Introduction to Digital Systems."— Presentation transcript:

1 Erik Jonsson School of Engineering and Computer Science FEARLESS Engineeringwww.utdallas.edu/~pervin EE/CE 2310 – HON/002 Introduction to Digital Systems http://www.utdallas.edu/~pervin T1-T5,P1P4 Tuesday: Review Chapters T1-T5,P1-P4 Thursday 2-16-12

2 Decoders & Multiplexers – Dodge Lecture 6 http://www.utdallas.edu/~dodge/EE2310/lec6.pdf http://www.utdallas.edu/~dodge/EE2310/lec6.pdf Go over this carefully!! For Lab Assignment #1, see the next slide.

3 Design Problem You have now seen how to go from a requirement to a truth table to a Boolean Expression to a circuit (and even how to simplify the circuit). You now get to do a design. Do a first try by yourself. Then you may review and complete your design with your EE 2110 lab partner. Here is the requirement (“spec”): A circuit has three input variables, x, y, and z. Its output is 1 for the conditions x, y, z = 0, x, y = 0; z = 1, and x = 0; y, z = 1. Do the following: – Make a truth table from the requirements. – Devise an SOP Boolean expression from the truth table. Simplify it using the relationships discussed today, but keep in SOP form. (Do not use a Karnaugh map!) – In EE 2110 Lab. 1, build your design (see Lab. 1 instructions). – Using all combinations of the input variables, demonstrate with your partner to the lab TA that your real circuit obeys your truth table. Lecture #4: Boolean Algebra and Combinational Digital Logic © N. B. Dodge 01/12

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6 Karnaugh Map Simplify the Boolean expression: _ _ _ _ _ _ _ _ _ _ _ A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D = Y 0011 AB0110 00 01 11 10

7 Karnaugh Map Simplify the Boolean expression: _ _ _ _ _ _ _ _ _ _ _ A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D = Y 0011 AB0110 00 0111 1111 1011

8 Karnaugh Map Simplify the Boolean expression: _ _ _ _ _ _ _ _ _ _ _ A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D = Y 0011 AB0110 00 0111 1111 1011 _ _ Y = B.C + A.B.C

9 Multiplexer

10 Pin Diagrams

11 We went over Dr. Dodge’s Review for his first test.


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