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Physics 213 General Physics Lecture 16. 1 Last Meeting: Reflection and Refraction of Light Today: Mirrors and Lenses t.

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Presentation on theme: "Physics 213 General Physics Lecture 16. 1 Last Meeting: Reflection and Refraction of Light Today: Mirrors and Lenses t."— Presentation transcript:

1 Physics 213 General Physics Lecture 16

2 1 Last Meeting: Reflection and Refraction of Light Today: Mirrors and Lenses t

3 2 Are the red and violet lights coming from the same raindrop?

4 Dispersion by drops of water. Red is bent the least so comes from droplets higher in the sky.

5 4 Why is the sky blue? Why is the sunset orange? hint

6 5 Why is the cloud white?

7 6

8 7

9 8

10 9

11 10 ∞

12 11 demo

13 12

14 13

15 14

16 Funny Mirror 15

17 16

18 17

19 18

20 19

21 20

22 21

23 22

24 23

25 24

26 25

27 26 Ray Diagram for Diverging Lens The image is virtual The image is upright

28 QUICK QUIZ 23.4 A plastic sandwich bag filled with water can act as a crude converging lens in air. If the bag is filled with air and placed under water, is the effective lens (a) converging or (b) diverging?

29 QUICK QUIZ 23.4 ANSWER (b). In this case, the index of refraction of the lens material is less than that of the surrounding medium. Under these conditions, a biconvex lens will be divergent.

30 Image Example Between F’ and O F’F O Behind lens, virtual, upright larger than object Magnifying glass F’F O At F’ No image Lighthouse Between F’ and 2F’ F’F O 2F’ Beyond 2F, real, inverted, larger Projector F’F O 2F’ At 2F, real, inverted, same as object Office copier At 2F’ F’F O 2F’ Between F and 2F, Real, inverted, smaller Camera Beyond 2F’ F’ O 2F’ At F, real, inverted, smaller F Camera At infinity

31 Example: (a) An object 31.5 cm in front of a certain lens is imaged 8.20 cm in front of that lens (on the same side as the object). What type of lens is this and what is its focal length? Is the image real or virtual? (b) If the image were located, instead, 38.0 cm in front of the lens, what type of lens would it be and what focal length would it have? Solution: (a) 1/d o +1/d i =1/f where d o =31.5 cm, d i =-8.20 cm 1/31.5+1/(-8.20)=1/f, which yields f=-11.1 cm, thus diverging lens. The image is in front of the lens, so it is virtual (b) Similarly, we have 1/31.5+1/(-38.0)=1/f. which gives f=+184 cm, thus, converging lens. F’F O (b) F Image F’ (a)

32 31 Question: An object infinitely far from a converging lens has an image that is (a) real (b) virtual (c) upright (d) larger than the object Answer: a

33 32 Question: An object farther from a converging lens than its focal point always has an image that is (a) inverted (b) virtual (c) the same in size (d) smaller in size Answer: a

34 33 Quiz: An object closer to a converging lens than its focal point always has an image that is (a) inverted (b) virtual (c) the same in size (d) smaller in size Answer: b

35 Sign Conventions for Mirrors Concave gives “+” conventions

36 Sign Conventions for Refracting Surfaces/Lenes These are the same sign conventions – so just remember them for thin lenses. n 1 is the source medium n 2 is the observing medium

37 Combinations of Thin Lenses The image produced by the first lens is calculated as though the second lens were not present The light then approaches the second lens as if it had come from the image of the first lens The image of the first lens is treated as the object of the second lens The image formed by the second lens is the final image of the system If the image formed by the first lens lies on the back side of the second lens, then the image is treated at a virtual object for the second lens  p will be negative The overall magnification is the product of the magnification of the separate lenses


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