1. Mechanical Vibrations In many mechanical systems: The motion is an oscillation with the position of static equilibrium as the center

2. Mechanical Vibrations Examples: http://www.aw-bc.com/ide/idefiles/media/JavaTools/smpharos.html http://www.aw-bc.com/ide/idefiles/media/JavaTools/smpharos.html –The motion of the flywheel in a watch –The suspension of an automobile –A solid structure like a bridge or a concrete weir vibrates due to the action of wind, water, or earth tremors.

3. Mechanical Vibrations Spring with damping: –Consider a spring of length l –A bob and a damping mechanism (as so-called dashpot, which is just a cylinder filled with fluid, and a piston, much like a shock absorber) are attached to the other end. –The other end is fastened to a vertical hook in such a way that the whole system hangs motionless –Then the spring will lengthen to a Length of l+h in this static position, with h a real positive number.

4. Mechanical Vibrations –Let the total mass on the lower end of the spring be m. –When the bob is displaced from the position of static equilibrium and then projected at a given initial speed in a vertical direction, we would expect the bob to execute an oscillatory motion. Elastic force of the spring: when a force is applied to the lower end of the spring, one feels intuitively that the spring should bear some relation to the magnitude of the force. The empirical Law (Hookw’s law due to Robert Hooke (1635-1703): The force necessary to extend a spring or an elastic string of natural length l to a length l+h is proportional to the extension h, provided that h<<l. –The proportionality constant in this law is called the spring constant or stiffness, usually denote as k. –Modulus: product of the spring constant and the natural length

5. Mechanical Vibrations A Mathematical Model –Variables Independent variable: t (time) State variable: x(t): displacement of the bob from its equilibrium (Here the x-axis is chosen vertically downward with the origin at the position of the bob when the system is in static equilibrium) –Assumptions: The mass of the spring is much smaller than the mass of the bob The amplitude (i.e.,the maximal displacement from the center) of the oscillations is so small that it is less than h, and the Hooke’s law is valid. The magnitude of the resistance to the motion (due to air resistance and the damping mechanism) is directly proportional to the speed at any time t, and always in the opposite direction to the velocity.

6. Mechanical Vibrations –Construct the model based on the assumption We ignore the weight of the spring itself. When the system is hanging in equilibrium, the acceleration is zero. Hence the resultant force on the bob must also be zero by Newton’s second law, i.e. Total forces: –The weight m g which is always downward –The force –k(x+h) which is always upward since |x|<h –The resistance (or damping) –c x’ which is always in the opposite direction to x, and where c is the proportionality constant –An (possible) external force f(t) directed downwards when its sign is positive, and upwards when its sign is negative.

7. Mechanical Vibrations Newton’s second law –Initial value problem (IVP) m>0, k>0 & c>=0 are parameters and given The initial values are given The equation is second linear ODE with constant coefficients !!! For given initial data, f(t) and the parameters, there exists a uniqueness solution of the IVP !!!!!

8. Mechanical Vibrations Solution of IVP: –Case 1: free motion, i.e. f(t)=0 Overdamping: Critical damping: Underdamping: No damping (simple harmonic oscillator): c=0 –Case 2: forced motion, i.e. Undamed motion: c=0 –Resonance Damped motion:

9. Solution structures of the ODE For the homogeneous equation –If y 1 (t) is a solution, then a y 1 (t) is also a solution for any constant a ! –If y 1 (t) and y 2 (t) are two nonzero solutions, then c 1 y 1 (t) + c 2 y 2 (t) is also a solution (superposition) –If y 1 (t) and y 2 (t) are two linearly independent solutions, then the general solution is c 1 y 1 (t) + c 2 y 2 (t)

10. Solution structure of the ODE Solution structure of linear problem –If y 1 (t) is a solution of the homogeneous equation, y 2 (t) is also a specific solution. Then y 2 (t)+a y 1 (t) is also a solution for any constant a ! –If y 1 (t) and y 2 (t) are two solutions, y 1 (t)-y 2 (t) is a solution of the homogeneous equation. –If y 1 (t) and y 2 (t) are two linearly independent solutions of the homogeneous equation, y 3 (t) is a specific solution, then the general solution is c 1 y 1 (t) + c 2 y 2 (t)+y 3 (t)

11. Mechanical Vibrations Free motion, i.e.f(t)=0: http://www.aw-bc.com/ide/idefiles/media/JavaTools/massprng.html http://www.aw-bc.com/ide/idefiles/media/JavaTools/massprng.html –Since the equation is linear with constant coefficients, try the solution in the form –Plug into the equation, we get the characteristic equation –The two roots are

12. Mechanical Vibrations –Overdamping: p and q are two real distinct negative numbers By superposition, we get the general solution To satisfy the initial values, we have Solve it, we get

13. Mechanical Vibrations The analytical solution Properties –Long time behavior: x(t)  0, when t  infinity –Question: How many times would the bob pass through the origin of the x-axis (or the point of static equilibrium)?

14. Mechanical Vibrations »Condition for the bob not passing the origin: the bob will tend to the origin when t goes to infinity. »Condition for the bob passing the origin only one time: the bob would pass only once through the origin and then tend to the origin as t goes to infinity!! –In the case of overdamping, there is no oscillation of the bob. http://www.aw-bc.com/ide/idefiles/media/JavaTools/massprng.html

15. Mechanical Vibrations –Critical damping: p=q=-c/2m are two same real negative numbers, we only have one function which satisfies the equation To find another solution, we try and find another function By superposition, we get the general solution To satisfy the initial values, we have

16. Mechanical Vibrations Solve it, we get The analytical solution Properties –Long time behavior: x(t)  0, when t  infinity –The bob passes through the origin exactly once when –Otherwise,the bob merely tends to the origin from its initial position –In this case, there is no oscillation of the bob. http://www.aw-bc.com/ide/idefiles/media/JavaTools/massprng.html

17. Mechanical Vibrations –Underdamping: p and q are complex conjugate numbers and we write We have two complex solutions Since the ODE is homogeneous and linear, linear combination of the two solutions are still a solution, we get two real solutions

18. Mechanical Vibrations By superposition, we get the general solution To satisfy the initial values, we have Solve it, we get

19. Mechanical Vibrations The analytical solution Introduce a phase angle The analytical solution

20. Mechanical Vibrations Properties: http://www.aw-bc.com/ide/idefiles/media/JavaTools/massprng.html http://www.aw-bc.com/ide/idefiles/media/JavaTools/massprng.html –Long time behavior: x(t)  0, when t  infinity –The bob passes through the origin infinite many times with each time a fix period, the maximum amplitude in each period decreases when time increases! –Examples: k=m=1, c=0.5 or 0.25

21. Mechanical Vibrations –No damping (simple harmonic motion): c=0 The analytical solution To satisfy the initial values, we have Solve it, we get

22. Mechanical Vibrations The analytical solution Introduce a phase angle The analytical solution The bob oscillates periodically with amplitude D0 around the position of static equilibrium x=0. The period of the oscillation is defined as the time for a complete oscillation http://www.aw-bc.com/ide/idefiles/media/JavaTools/massprng.html

23. Mechanical Vibrations Forced motion: http://www.aw-bc.com/ide/idefiles/media/JavaTools/vibefdmp.html http://www.aw-bc.com/ide/idefiles/media/JavaTools/vibefdmp.html The external force is periodic: –E and a are positive constants, b is any constant Two different cases: –Undamped motion: Resonance: –Damped motion: c>0

24. Mechanical Vibrations Undamped motion: –For the homogeneous ODE –We know the two linearly independent solutions: –We need find a specific solution and try the form

25. Mechanical Vibrations –Plug into the equation, we get –This implies –The general solution –To satisfy the initial condition, we have –Solve the above equations, we get A and B and the solution.

26. Mechanical Vibrations –The solution: http://www.aw-bc.com/ide/idefiles/media/JavaTools/vibefdmp.html http://www.aw-bc.com/ide/idefiles/media/JavaTools/vibefdmp.html With It is the sum of two simple harmonic motions but with different periods, in general, it is NOT a periodic function!!

27. Mechanical Vibrations Resonance: –For the homogeneous ODE –We know the two linearly independent solutions: –We need find a specific solution and try the form

28. Mechanical Vibrations –Plug into the equation, we get –This implies –The general solution –To satisfy the initial condition, we have –Solve the above equations, we get A and B and the solution.

29. Mechanical Vibrations –The solution: http://www.aw-bc.com/ide/idefiles/media/JavaTools/vibefdmp.html http://www.aw-bc.com/ide/idefiles/media/JavaTools/vibefdmp.html Resonance: This phenomena of unbounded oscillation when the natural frequency coincides with the frequency of the external force

30. Mechanical Vibrations –Examples of resonance When men are marching over a bridge When waves hit a concrete damwall When wind impacts on a structure like a bridge or a tower –In actual fact, the structure would break up when the oscillations get too large, so that the oscillation never really becomes unbounded!!! More examples: e.g. damped motion, c>0 http://www.aw-bc.com/ide/idefiles/navigation/toolindexes/12.htm#12

31. Other examples Electrical networks (Kirchhoff’s law) –q(t): charge on The plates of the Capacitor C –L: Inductance of transformer –R: resistor –E: electromotor

32. Method for linear constant ODE Consider: Find two linearly independent solutions for –Try to find the solution in the form –Plug into the equation, we get the characteristic equation –Write the two solutions based on the two roots Find a specific solution of the original equation

33. Methods for linear constant ODE How to determine two functions f(t) and g(t) are linearly independent? Wronskian of f and g: –Linearly independent: the Wronskina is everywhere nonzero –Linearly dependent: otherwise Examples: –Linearly independent: f(t)=sin t, g(t)=cos t, W=1 –Linearly dependent: f(t)=sin t, g(t)=3 sin t, W=0.