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Marr CollegeHigher ComputingSlide 1 Part 2: Computer Structure – 6 hours Higher Computing: COMPUTER SYSTEMS.

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Presentation on theme: "Marr CollegeHigher ComputingSlide 1 Part 2: Computer Structure – 6 hours Higher Computing: COMPUTER SYSTEMS."— Presentation transcript:

1 Marr CollegeHigher ComputingSlide 1 Part 2: Computer Structure – 6 hours Higher Computing: COMPUTER SYSTEMS

2 Marr CollegeHigher ComputingSlide 2 The five box diagram represents the basic components of a computer system. It represents input devices, processor, main memory, output devices and backing storage. Computer Structure Five box diagram InputOutput Processor Main Memory Backing Store INT 2

3 Marr CollegeHigher ComputingSlide 3 Computer Structure The purpose of the processor The processor – also known as the central processing unit (CPU) - is the ‘brain’ or ‘engine’ of the computer system. Its purpose is to interpret instructions and process data contained in computer programs. INT 2

4 Marr CollegeHigher ComputingSlide 4 Computer Structure Parts of a processor The control unit has a timer to that sends signals to fetch, decode and execute program instructions. The arithmetic and logic unit performs arithmetic calculations e.g. / * + - and logic operations e.g. AND, OR etc. The registers are temporary storage areas that hold data being processed; instructions being executed; and addresses to be accessed. The CPU consists of three main parts: Control Unit ALU Registers RAM INT 2

5 Marr CollegeHigher ComputingSlide 5 Computer Structure The purpose of the ALU The arithmetic and logic unit is a digital circuit that performs arithmetic and logical operations. The ALU can perform many operations including: Integer arithmetic e.g. addition and subtraction Bitwise logic operations e.g. AND, OR, NOT, XOR Control Unit ALU Input (operand) Output (result) Operation (opcode) *The inputs to the ALU are the data to be operated on (called operands) *and a code from the control unit indicating which operation to perform. *Its output is the result of the computation.

6 Marr CollegeHigher ComputingSlide 6 Computer Structure The purpose of the Control Unit The control unit is the circuitry that controls the flow of data through the processor, and coordinates the activities of the other units within it. It can be described as the "brain within the brain", as it controls what happens inside the processor, which in turn controls the rest of the PC. It performs the tasks of fetching, decoding, managing execution and then storing results and has a timer to synchronise these events.

7 Marr CollegeHigher ComputingSlide 7 Computer Structure The Address Bus Carries address information from the CPU to main memory and any other attached devices It is uni-directional i.e. one-way only The width (i.e. the number of wires) determines the number of memory locations the CPU can address A 32 bit address bus has 32 parallel wires each switched on (1) or off (0) that can address locations starting from: 0000 0000 0000 0000 0000 0000 0000 0000 (decimal 0) up to and including address: 1111 1111 1111 1111 1111 1111 1111 1111 (decimal 2 32 –1) making a total of 2 32 addresses A 32 bit address bus has 32 parallel wires each switched on (1) or off (0) that can address locations starting from: 0000 0000 0000 0000 0000 0000 0000 0000 (decimal 0) up to and including address: 1111 1111 1111 1111 1111 1111 1111 1111 (decimal 2 32 –1) making a total of 2 32 addresses Every time a wire is added to the width of the address bus, the address range doubles

8 Marr CollegeHigher ComputingSlide 8 Computer Structure The Data Bus Carries data to and from the CPU, main memory and any other devices attached It is bi-directional i.e. two-way The number of wires determines the quantity of data that the bus can carry so increasing the number of wires in the data bus increases the quantity of data it can carry A typical 32-bit data bus can carry 32-bits of data or instructions at a time In Higher Computing we make the assumption that: The size (number of wires) on the data bus determines the size of the memory locations in RAM e.g. A 32 bit data bus means each memory location in RAM stores 32 bits (i.e. 4 bytes equivalent) In Higher Computing we make the assumption that: The size (number of wires) on the data bus determines the size of the memory locations in RAM e.g. A 32 bit data bus means each memory location in RAM stores 32 bits (i.e. 4 bytes equivalent)

9 Marr CollegeHigher ComputingSlide 9 Computer Structure The Control Bus - control lines Signals are sent out and received on the control bus. The control bus is not really a ‘bus’ as it does not transfer data or addresses. It is made up of discrete wires each with a specific function: Read and Write signals are initiated to fetch – execute instructions in memory Clock line carries a series of clock pulses at a constant rate to keep the CPU in step (clock rate measured megahertz or gigahertz) Reset halts the execution of the stored program. Internal registers are cleared and the machine reboots. Interrupts are signals usually from I/O devices that halt program execution temporarily. The CPU may ignore them e.g. printer out of paper Non-maskable Interrupts cannot be ignored e.g. power failure

10 Marr CollegeHigher ComputingSlide 10 Computer Structure The buses: Address, Data and Control Control Unit Arithmetic and Logic Unit (ALU) Other registers Memory Address Register Memory Data Register Main Memory Address bus Data bus Control Bus (Read / Write) Electronic clock Clock pulses

11 Marr CollegeHigher ComputingSlide 11 Computer Structure The fetch-execute cycle The fetch-execute cycle of the processor refers to the sequence that is completed for each instruction in a program. Fetch Sequence Move the value in the program counter to the memory address register Send the value in the memory address register to memory via the address bus Return the value stored in memory via the data bus Store the value in the memory data register Copy the instruction from the memory address register to the instruction register Increment the program counter. The instruction in the instruction register is then Decoded Execute Sequence Instruction is executed

12 Marr CollegeHigher ComputingSlide 12 Computer Structure The purpose of the Registers The registers are small, fast storage areas that temporarily hold data. Instructions or addresses. The registers in the CPU have three main functions. They are to hold data being processed, instructions being executed, and addresses being accessed. memory address register (MAR) – holds the address of a location in memory memory data register (MDR) – holds data just read from or written to memory program counter (PC) – holds the address of the next instruction to be fetched Instruction register (IR) – holds the current instruction being executed general purpose registers – can be used by programmers

13 Marr CollegeHigher ComputingSlide 13 Computer Structure Computer Memory - Cache CPU Cache Main Memory (RAM) 1. Cache fetches data from next to current addresses in main memory 2. CPU checks to see whether the next instruction it requires is in cache 4. If not, the CPU has to fetch next instruction from main memory - a much slower process 3. If it is, then the instruction is fetched from the cache – a very fast position Cache Memory Is a small area of ‘super fast’ access memory, between the processor and main memory, which stores frequently used instructions and data.

14 Marr CollegeHigher ComputingSlide 14 Computer Structure Main memory is commonly referred to as RAM (random access memory). RAM is used to hold program instructions and data before and after processing by the CPU. RAM chip Increasing memory size (capacity in Mb/Gb) improves system performance as more programs and data can be held. INT 2 Main memory – RAM RAM is volatile i.e. loses it contents when switched off. Reading from RAM is slower than accessing registers or cache. Use of cache avoids slower fetches from RAM.

15 Marr CollegeHigher ComputingSlide 15 Computer Structure Main memory - ROM Another type of memory is Read Only Memory (ROM). ROM is used to store the bootstrap loader program that locates the operating system on the hard disc when the computer ‘boots up’. Features - ROM ROM data is permanently etched on chip Read-only so data cannot be changed Data not lost when computer switched off ROM chip INT 2

16 Marr CollegeHigher ComputingSlide 16 Computer Structure Backing storage Backing storage is where the computer permanently saves computer programs and data. This includes devices such as the hard disc and media such as DVD. INT 2

17 Marr CollegeHigher ComputingSlide 17 Computer Structure Distinguishing between different parts of memory Registers – fastest access time as internal to CPU Cache – slower than registers but fast as no READ needed RAM – slower than registers and cache Backing store – slowest speed of access

18 Marr CollegeHigher ComputingSlide 18 Computer Structure Memory Investigate the following elements of computer memory: Registers cache main memory backing storage Distinguish between the above elements of memory according to: Function speed of access Produce a brief word processed report or powerpoint presentation. Include an image/diagram of each component. Task

19 Marr CollegeHigher ComputingSlide 19 Computer Structure Addressability Main memory consists of a number of storage locations, each of which is identified by a unique address. The ability of the CPU to identify each location is known as its addressability. Each location stores a word i.e. the number of bits that can be processed by the CPU in a single operation. Word length may be typically 16, 24, 32 or as many as 64 bits. A large word length improves system performance, though may be less efficient on occasions when the full word length is not used

20 Marr CollegeHigher ComputingSlide 20 Computer Structure Calculating memory capacity of a computer Example A computer has a 24 bit address bus and a 16 bit data bus. Calculate the maximum amount of memory this computer can use. 2 24 * 2 bytes= 33,554,432 bytes 33,554,432 / 1024= 32,768 kilobytes 32768 / 1024= 32 megabytes Memory capacity can be calculated if we know: the number of lines on the address bus and the number of bits stored in each memory location Note: in Higher we assume the number of bits in a memory location to be the same as the number of bits the data bus can carry. Formula Amount of storage locations = 2 width of the address bus Memory capacity = 2 the width of the address bus * width of data bus Formula Amount of storage locations = 2 width of the address bus Memory capacity = 2 the width of the address bus * width of data bus

21 Marr CollegeHigher ComputingSlide 21 Computer Structure Calculating memory capacity of a computer Calculate the total memory requirements of the following computer systems: a)Processor has a 16-line address bus and each location stores 16 bits. b)Processor has a 16-line address bus and each location stores 32 bits. c)Processor has a 32-line address bus and a 24-line data bus. d)Processor has a 36-bit address bus and a word length of 32 bits. Questions Remember: Location size = data bus size = word length / size

22 Marr CollegeHigher ComputingSlide 22 Computer Structure Desktop computer INT 2 Processing Power - measured by clock speed e.g. 3 Ghz. Memory size - typically 3 Gb. Backing storage – large hard disc typically 750 Gb – 1 Tb. Also, CD-RW and DVD-RW. Input devices – keyboard, microphone, mouse, webcam etc. Output devices – monitors, printers, speakers, modem etc Typical uses – applications (word, excel), email, internet, gaming Processing Power - measured by clock speed e.g. 3 Ghz. Memory size - typically 3 Gb. Backing storage – large hard disc typically 750 Gb – 1 Tb. Also, CD-RW and DVD-RW. Input devices – keyboard, microphone, mouse, webcam etc. Output devices – monitors, printers, speakers, modem etc Typical uses – applications (word, excel), email, internet, gaming

23 Marr CollegeHigher ComputingSlide 23 Computer Structure Laptop computer INT 2 Processing Power - measured by clock speed e.g. 1.75 Ghz – 2.4 GHz Memory size - typically 512 Mb – 1 Gb. Backing storage – large hard disc typically 40 - 100 Gb. Also, CD- RW and DVD-RW. Input devices – keyboard, touchpad Output devices – LCD integrated monitor, printers, speakers, modem etc Typical uses – applications (word, excel), email, internet, gaming. Portable to work on the move. Processing Power - measured by clock speed e.g. 1.75 Ghz – 2.4 GHz Memory size - typically 512 Mb – 1 Gb. Backing storage – large hard disc typically 40 - 100 Gb. Also, CD- RW and DVD-RW. Input devices – keyboard, touchpad Output devices – LCD integrated monitor, printers, speakers, modem etc Typical uses – applications (word, excel), email, internet, gaming. Portable to work on the move.

24 Marr CollegeHigher ComputingSlide 24 Computer Structure Palmtop computer Processing Power - measured by clock speed e.g. 200 – 500 Mhz Memory size - typically 32 – 64 Mb. Can extend with memory card. Backing storage – Same as memory (battery powered) Input devices – stylus and touch screen Output devices – integrated LCD screen Typical uses – personal organiser and connectivity to PC. INT 2

25 Marr CollegeHigher ComputingSlide 25 Computer Structure Mainframe computer A large and powerful computer that deals with very high volumes of data processing. Features Processing power: several processors RAM: 32 GB or more Backing storage: 100s of GB, tape drives I/O: keyboard, printers, monitors Uses Used by large organisations to provide remote access to central computer via terminals e.g. a bank’s ‘cashpoint’ machines are directly connected to a mainframe at head office. INT 2

26 Marr CollegeHigher ComputingSlide 26 Computer Structure Embedded computer Embedded computers are special-purpose systems where the computer is embedded within the machine it controls e.g. a computer system in a car. They perform a specific task Considered a INT 2

27 Marr CollegeHigher ComputingSlide 27 Computer Structure System Performance: Clock Speed INT 2 Clock speed indicates processing power but some instructions need more clock pulses on one processor than on another. Is the number of clock pulses a CPU generates per second. Measured in gigahertz i.e. 1GHz = 1 billion pulses per second. Clock Speed These pulses synchronise the steps of the fetch-execute cycle e.g. a clock pulse starts a ‘fetch’, or triggers placing data in the MDR. The faster the clock speed – the more operations can be executed per second.

28 Marr CollegeHigher ComputingSlide 28 Computer Structure System Performance: MIPS rate Millions of Instructions per Second (MIPS) MIPS roughly measures the number of machine code instructions that a CPU can execute per second. Pros Rough measure of processor performance e.g. Intel 8080:500 kIPS at 2 MHz Intel 486 DX2:54 MIPS at 66 MHz Intel Pentium III:1354 MIPS at 500 MHz Intel Core 2 X6800:27,079 MIPS at 2.93 GHz Cons No standard way of measuring MIPS as does not take into account complexity of an nstruction e.g. some instructions require more time than others. Refers only to CPU speed, not other factors such as I/O Therefore a machine with a high MIP rate may not run an application faster than a CPU with a lower rate due to other limiting factors.

29 Marr CollegeHigher ComputingSlide 29 Computer Structure System Performance: MIPS rate How to calculate a CPU’s MIPS rating There is a simple formula to calculate MIPS. Formula MIPS = n / (t x 1,000,000) Where n is the number of instructions executed and t Example No standard way of measuring MIPS as does not take into account complexity of an nstruction e.g. some instructions require more time than others. Refers only to CPU speed, not other factors such as I/O Therefore a machine with a high MIP rate may not run an application faster than a CPU with a lower rate due to other limiting factors.

30 Marr CollegeHigher ComputingSlide 30 Computer Structure System Performance: MIPS rate Millions of Instructions Per Second (MIP) A clock speed of 200 MHz does not mean that 200 million instructions are executed per second. Because of this, clock speed isn’t an accurate measure of performance. It may therefore be the case that two processors have the same clock speed but different MIP rates. In order to get a better picture of performance we measure the CPUs ability in how many million instructions it can process per second, also referred to as the machine cycle time.

31 Marr CollegeHigher ComputingSlide 31 Computer Structure System Performance: MIPS rate Working out MIPS rate It can take at least five clock pulses to execute an instruction. Example – a CPU with a clock speed of 200 MHz =>200,000,000 clock pulses / 5 pulses per instruction =>40,000,000 instructions per sec. Thus CPU = 40 MIPS

32 Marr CollegeHigher ComputingSlide 32 Computer Structure Problems with MIPS rate Using MIPS rate as a comparison factor also has problems. MIPS rate depends on what sort of instructions are being carried out There is no standard set and so some manufacturers could use instructions which require less clock pulses to complete thus giving the impression of a faster MIPS rate than it actually is. System Performance: MIPS rate

33 Marr CollegeHigher ComputingSlide 33 Computer Structure System Performance: FLOPS Floating Point Operations per Second (FLOPS) Measures how many floating point operations are processor can perform per second. FLOPS are more accurate than MIPS. They measure a number of clearly definable arithmetic tasks carried out per second.

34 Marr CollegeHigher ComputingSlide 34 Computer Structure System Performance: Application-based Test (Benchmarks) This involves running various application programs on different computer systems and observing which system runs these programs the fastest. Most reliable measure of processor performance because it provides the user with actual evidence of how well different processors perform complex operations at high speed. Benchmarks

35 Marr CollegeHigher ComputingSlide 35 Computer Structure Factors that affect system performance Data bus width – Increasing the data bus width increases processor throughput i.e. an 8-bit bus can transfer 1 byte of data; a 16-bit can transfer 2 bytes etc. Cache memory - Using / increasing cache (SRAM) means less ‘fetches’ from slower main memory (DRAM). Peripheral speed – Slow transfer rates slow the system down so better to choose peripherals with faster transfer rates.

36 Marr CollegeHigher ComputingSlide 36 Computer Structure Current trends in computer hardware Faster clock speeds – improved CPU throughput as millions more instructions per second. More RAM – more sophisticated software can be run, and improved multitasking i.e. more programs loaded simultaneously. More backing storage capacity means more data can be stored permanently.


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