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Do I need a magic 8 ball for this?. When predicting products of chemical equations, you will only be given the reactant side of the equation. –Reactants.

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Presentation on theme: "Do I need a magic 8 ball for this?. When predicting products of chemical equations, you will only be given the reactant side of the equation. –Reactants."— Presentation transcript:

1 Do I need a magic 8 ball for this?

2 When predicting products of chemical equations, you will only be given the reactant side of the equation. –Reactants  Products In order to determine the products, you must recognize the reaction type.

3 There are five reaction types that we will consider. 1.Synthesis 2.Decomposition 3.Single Replacement 4.Double Replacement 5.Combustion

4 If it is a Synthesis reaction... Synthesis follows the general equation –A + B  AB –This means that the reactants come together. In Synthesis reactions, there will be only one product. There will be more than one reactant.

5 If it is a Synthesis reaction... These reactants can be either elements or compounds. If there are only two elements, than the reaction is Synthesis.

6 If it is a Decomposition reaction... Decomposition reactions have the general equation of –AB  A + B –This means that the reactant will be broken down into simpler substances. In a Decomposition reaction, there will only be one reactant.

7 If it is a Single Replacement reaction... Single Replacement reactions follow the general equation of –AB + C  AC + B –This means that the single element may replace part of the compound. Reactants will have one compound and one element.

8 If it is a Double Replacement reaction... Double Replacement reactions follow the general equation of –AX + BY  AY + BX –In these reactions, the reactants switch parts to create two new products. There must be two compounds on the reactants side.

9 If it is a Combustion reaction... Combustion reactions do not have a specific general equation. These may overlap with Synthesis reactions, but they do have different products. Combustion reactions will always have O 2 on the reactants side.

10 Knowing the reaction type will allow us to realize what we must do. Each reaction type will have a different process to reach the correct product.

11 Synthesis Products H 2 + N 2  –There are two elements. This is a Synthesis reaction. –Draw the Lewis structure for each element.

12 Synthesis Products –The Lewis Dot Structure shows how many bonds each atom can make. –How many bonds can hydrogen make? One single bond

13 Synthesis Products –How many bonds can nitrogen make? One triple bond One double bond and one single bond Three single bonds

14 Synthesis Products –Looking at both elements, choose the bonds that suit the situation. –For our hydrogen and nitrogen, single bonds are the answer.

15 Synthesis Products Looking at the Lewis dot structures, determine the ratio of elements.

16 Synthesis Products Our product will have the formula of NH 3.

17 Synthesis Products H 2 + N 2  NH 3 This is our equation with our predicted products. Is it the final equation? –No What is wrong? –It’s not balanced.

18 Synthesis Products Final step is to balance the equation. 3H 2 + N 2  2NH 3

19 Decomposition Products Ba(OH) 2  There is only one reactant, so it is a Decomposition reaction. There must be at least two products. Look at the reactant. What two compounds could have made it?

20 Decomposition Products Ba(OH) 2  When there is a hydroxide group (the OH), then there will be water as one of the products. Next, we must look at the element attached to the hydroxide group. –Elements combining with water tend to be in oxide form.

21 Decomposition Products Ba(OH) 2  H 2 O + BaO The last step is always to balance equations. This equation is always balanced.

22 Decomposition Some nonmetal oxides, such as the halogen oxides, also decompose upon heating –Cl 2 O 5 

23 Decomposition Other nonmetal oxides, such as dinitrogen pentoxide, decompose to an element and a compound: –2N2O5 (g) → O2 (g) + 4NO2 (g)

24 Decomposition Many metal salts containing oxoanions decompose upon heating. These salts either give off oxygen gas, forming a metal salt with a different nonmetal anion, or they give off a nonmetal oxide, forming a metal oxide. For example, metal nitrates containing Group 1A or 2A metals or aluminum decompose to metal nitrites and oxygen gas: Mg(NO3)2 (s) → Mg(NO2)2 (s) + O2 (g)

25 Decomposition All other metal nitrates decompose to metal oxides, along with nitrogen dioxide and oxygen: 2Cu(NO3)2 (s) → 2CuO (s) + 4NO2 (g) + O2 (g)

26 Decomposition Salts of the halogen oxoanions decompose to halides and oxygen upon heating: 2KBrO3 (s) → 2KBr (s) + 3O2 (g)

27 Decomposition Carbonates, except for those of the alkali metals, decompose to oxides and carbon dioxide. CaCO3 (s) → CaO (s) + CO2 (g)

28 Decomposition A number of compounds—hydrates, hydroxides, and oxoacids—that contain water or its components lose water when heated. Hydrates, compounds that contain water molecules, lose water to form anhydrous compounds, free of molecular water. CaSO4 · 2H2O (s) → CaSO4 (s) + 2H2O (g)

29 Decomposition Metal hydroxides are converted to metal oxides by heating: 2Fe(OH)3 (s) → Fe2O3 (s) + 3H2O (g)

30 Decomposition Most oxoacids lose water until no hydrogen remains, leaving a nonmetal oxide: H2SO4 (l) → H2O (g) + SO3 (g)

31 Decomposition Oxoanion salts that contain hydrogen ions break down into the corresponding oxoanion salts and oxoacids: Ca(HSO4)2 (s) → CaSO4 (s) + H2SO4 (l)

32 Single Replacement Product Single Replacement reactions do not always occur. For these reactions, we must look at an activity series. –An activity series shows the reactivity of elements. –If the single element in the reaction is less reactive than the element in the compound, the reaction will not occur.

33 Single Replacement Product Open your textbooks to page 293 Now let’s look at –Al + HCl  Look at the reactivity series. In this case, the aluminum is attempting to replace the hydrogen.

34 Single Replacement Product The Aluminum will replace the hydrogen. So what happens?

35 Single Replacement Product We know our two products will be hydrogen by itself and aluminum bonded with chlorine. Looking at hydrogen first, what do we know about hydrogen? –It’s diatomic. –It will be written as H 2.

36 Single Replacement Product Now we look at our aluminum and chlorine. Once again draw Lewis structures. AlCl 3 Our final equation –Al + HCl  H 2 + AlCl 3 Last thing to do is balance.

37 Single Replacement Product 2Al + 6HCl  3H 2 + 2AlCl 3

38 Double Replacement Product Ca(OH) 2 + HCl  In this reaction, there will be two compounds on the reactants side. There will also be two compounds on the product’s side.

39 Double Replacement Product These reactions produce water, a precipitate or a gas. Ca(OH) 2 + HCl  In this reaction, there is a hydroxide group, and a hydrogen. Water will be one of the products: H 2 O

40 Double Replacement Product The other product will result from the remaining elements. –Ca –Cl Calcium has two valence electrons. Chlorine has seven. From an ionic standpoint, the calcium needs two chlorines to form an ionic bond.

41 Double Replacement Product CaCl 2 is the other product. Once again, the last step is to balance the equation. Ca(OH) 2 + 2HCl  2H 2 O + CaCl 2

42 Combustion Products Often composed of hydrocarbons –C (n) H (m) Reacting with O 2 CH 4 + O 2  In cases of hydrocarbons, there will be two products –CO 2 and H 2 O

43 Combustion Products The last step is to balance. CH 4 + 2O 2  2H 2 O + CO 2

44 The End


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