2. Whiteboardmaths.com © 2004 All rights reserved 5 7 2 1

3. BBBB EEEE DDDD BBBB DDDD CCCC EEEE BBBB DDDD CCCC DDDD CCCC EEEE BBBB CCCC EEEE ALGEBRA NUMBER SHAPE SPACE & M SPACE & M HANDLING DATA

4. Back to board Answer 1 2 + 2 2 + 3 2 + 4 2  (28 + 8) Work out:

5. Back to board 5 1 2 + 2 2 + 3 2 + 4 2  (28 + 8) Work out: Explain?

6. Back to board 5 1 2 + 2 2 + 3 2 + 4 2  (28 + 8) Work out: 30 6 =

7. Back to board Answer 8.5 cm The car below is a scale model of a real car. The scale used is 1: 50. How long is the real car?

8. Back to board 8.5 cm 4.25 m Explain? The car below is a scale model of a real car. The scale used is 1: 50. How long is the real car?

9. Back to board 8.5 cm 4.25 m 50 x 8.5 = 425 cm The car below is a scale model of a real car. The scale used is 1: 50. How long is the real car?

10. Back to board Answer Jenny bought a house for £185 000. After 2 years the market value had increased by 12%. Using a multiplier, find the new value of the house. £185 000

11. Back to board Explain? £185 000 £207 200 Jenny bought a house for £185 000. After 2 years the market value had increased by 12%. Using a multiplier, find the new value of the house.

12. Back to board £185 000 £207 200 185 000 x 1.12 = 207 200 Jenny bought a house for £185 000. After 2 years the market value had increased by 12%. Using a multiplier, find the new value of the house.

13. Back to board Answer A square has its all its sides increased by 10%. Calculate the percentage increase in its area.

14. Back to board Explain? A square has its all its sides increased by 10%. Calculate the percentage increase in its area. 21%

15. Back to board A square has its all its sides increased by 10%. Calculate the percentage increase in its area. 21% P P 1.1P New area = 1.1p x 1.1p = 1.21p 2  percentage increase = 21%

16. Back to board Answer p p q q q q P and q are lengths. Write down an expression for the perimeter of the hexagon.

17. Back to board p p q q q 2p + 4q P and q are lengths. Write down an expression for the perimeter of the hexagon. q

18. Back to board Answer 0 1 2 3 4 5 -2 -3 -4 1 2 3 4 5 -2 -3 -4 x y All five of the straight lines graphs pass through the point (3,3). Match each graph to its equation. A B C D E A B C D E y = x x = 3 y = 3 y = 2x - 3 y = x + 2 1 3

19. Back to board 0 1 2 3 4 5 -2 -3 -4 1 2 3 4 5 -2 -3 -4 x y A B C D E All five of the straight lines graphs pass through the point (3,3). Match each graph to its equation. A B C D E y = x x = 3 y = 3 y = 2x - 3 y = x + 2 1 3

20. Back to board Answer Write down an expression for the area of the shape below. x x 3 4

21. Back to board Explain? Write down an expression for the area of the shape below. x x 3 4 x 2 + 7 x + 12

22. Back to board Write down an expression for the area of the shape below. x x 3 4 x 2 + 7 x + 12 x2x2 3x 4x 12

23. Back to board Answer Solve the inequality below and find the largest integer solution. 2(2n + 1)  - 5

24. Back to board Explain? and - 2 n  - 1¾ 2(2n + 1)  - 5 Solve the inequality below and find the largest integer solution.

25. Back to board 4n + 2  - 5 4n  - 7 n  -7/4 n  - 1¾ and - 2 2(2n + 1)  - 5 Solve the inequality below and find the largest integer solution.

26. Back to board Answer 5 cm 7 cm Is the triangle shown below equilateral, Isosceles or scalene?

27. Back to board 5 cm 7 cm Is the triangle shown below equilateral, Isosceles or scalene? Isosceles Explain?

28. Back to board 5 cm 7 cm Is the triangle shown below equilateral, Isosceles or scalene? Isosceles Two sides have equal lengths.

29. Back to board Answer Rhombus Kite Rectangle Square (a) What name do we give 2D shapes like those shown? (b) One of the shapes has diagonals that do not cross at right angles. Which one?

30. Back to board Rhombus Kite Rectangle Square (a) What name do we give 2D shapes like those shown? (b) One of the shapes has diagonals that do not cross at right angles. Which one? (a) Quadrilaterals

31. Answer 14 cm 8 cm 2 cm 5 cm 2 cm Back to board Find the surface area of the solid shape shown (including the base).

32. Back to board Explain? 14 cm 8 cm 2 cm 5 cm 2 cm Find the surface area of the solid shape shown (including the base). 412 cm 2

33. Back to board 14 cm 8 cm 2 cm 5 cm 2 cm 2 x 8 x 14 = 224 (Top and bottom surfaces) 2 x 8 x 7 = 112 (L and R side views) Find the surface area of the solid shape shown (including the base). 412 cm 2 224 + 112 + 56 + 20 = 412 2 x 5 x 2 = 20 2 x 14 x 2 = 56

34. Back to board Answer A cylinder has a radius of 3.5 cm and a volume of 64  cm 3. Find the height h of the cylinder (1 dp) h 3.5 cm

35. Back to board Explain? h 3.5 cm A cylinder has a radius of 3.5 cm and a volume of 64  cm 3. Find the height h of the cylinder (1 dp) 5.2 cm

36. Back to board h 3.5 cm A cylinder has a radius of 3.5 cm and a volume of 64  cm 3. Find the height h of the cylinder (1 dp) 5.2 cm V =  r 2 h 64  =  x 3.5 2 x h 64 = 3.5 2 x h 64 3.5 2 h = = 5.2

37. Back to board Answer WalkBus BikeCar 4 8 12 16 20 The bar chart shows how some children came to school on Monday morning. What percentage of pupils came by bike or car?

38. Back to board WalkBus BikeCar 4 8 12 16 20 The bar chart shows how some children came to school on Monday morning. What percentage of pupils came by bike or car? 28% Explain?

39. Back to board WalkBus BikeCar 4 8 12 16 20 The bar chart shows how some children came to school on Monday morning. What percentage of pupils came by bike or car? 10 28% 4 14/50 = 28/100

40. Back to board Answer Jenny has a bag containing an unknown number of beads. The beads are coloured red, green and blue. The probability of Jenny selecting a red or green bead is 0.8 What is the probability of Jenny selecting a blue bead?

41. Back to board 0.2 Jenny has a bag containing an unknown number of beads. The beads are coloured red, green and blue. The probability of Jenny selecting a red or green bead is 0.8 What is the probability of Jenny selecting a blue bead? Explain?

42. Back to board 0.2 Jenny has a bag containing an unknown number of beads. The beads are coloured red, green and blue. The probability of Jenny selecting a red or green bead is 0.8 What is the probability of Jenny selecting a blue bead? P(blue) = 1 - P(red or green)

43. Back to board Answer Test Marks0-910-1920-2930-3940-50 Frequency581432 The frequency table below shows the number of marks gained in a test by a class of students. Calculate an estimate for the mean mark. (1 dp)

44. Back to board Explain? Test Marks0-910-1920-2930-3940-50 Frequency581432 21.1 The frequency table below shows the number of marks gained in a test by a class of students. Calculate an estimate for the mean mark. (1 dp)

45. Back to board Test Marks0-910-1920-2930-3940-50 Frequency581432 Mean estimate = (5 x 4.5 + 8 x 14.5 + 14 x 24.5 + 3 x 34.5 + 2 x 45)/32 = 675/32 = 21.1 21.1 The frequency table below shows the number of marks gained in a test by a class of students. Calculate an estimate for the mean mark. (1 dp)

46. Back to board Answer A toy factory makes teddy bears. It tested a random sample of the teddies from a large batch that were to go into shops for Christmas. The factory manager calculated the probability of any teddy being faulty as 0.015 Stuart intends to buy 2 teddies for his small sisters. Calculate the probability that both teddies would be faulty.

47. Back to board Explain? A toy factory makes teddy bears. It tested a random sample of the teddies from a large batch that were to go into shops for Christmas. The factory manager calculated the probability of any teddy being faulty as 0.015 Stuart intends to buy 2 teddies for his small sisters. Calculate the probability that both teddies would be faulty. 0.000225

48. Back to board A toy factory makes teddy bears. It tested a random sample of the teddies from a large batch that were to go into shops for Christmas. The factory manager calculated the probability of any teddy being faulty as 0.015 Stuart intends to buy 2 teddies for his small sisters. Calculate the probability that both teddies would be faulty. 0.000225 P(faulty and faulty) = 0.015 x 0.015