Chapter 6 Chemical Reactions Classification and Mass Relationship.

Chapter 6 Chemical Reactions Classification and Mass Relationship

Physical and Chemical Change
In a physical change, The identity and composition of the substance do not change. The state can change or the material can be torn into smaller pieces. In a chemical change, New substances form with different compositions and properties. A chemical reaction takes place.

Physical and Chemical Change

Some Examples of Chemical and Physical Changes

Learning Check Classify each of the following as a
1) physical change or 2) chemical change A. ____ Burning a candle. B. ____ Ice melting on the street. C. ____ Toasting a marshmallow. D. ____ Cutting a pizza. E. ____ Polishing a silver bowl.

Solution Classify each of the following as a
1) physical change or 2) chemical change A Burning a candle. B Ice melting on the street. C Toasting a marshmallow. D Cutting a pizza. E Polishing a silver bowl.

Chemical Reaction In a chemical reaction, a chemical change produces one or more new substances. During a reaction, old bonds are broken and new bonds are formed.

Chemical Reaction In a chemical reaction, atoms in the reactants are rearranged to form one or more different substances. In this reaction, Fe and O2 react to form rust (Fe2O3). 4Fe + 3O Fe2O3

Writing a Chemical Equation
Shows the chemical formulas of the reactants to the left of an arrow and the products on the right Reactants Products MgO C CO Mg Can be read in words. “Magnesium oxide reacts with carbon to form carbon monoxide and magnesium.”

Symbols Used in Equations
Symbols used in equations show the states of the reactants and products and the reaction conditions.

Quantities in A Chemical Reaction
4 NH O NO H2O Four molecules of NH3 react with five molecules of O2 to produce four molecules of NO and six molecules of H2O. or Four moles of NH3 react with 5 moles of O2 to produce four moles of NO and six moles of H2O.

Law of Conservation of Mass
In any ordinary chemical reaction, matter is not created nor destroyed. H Cl HCl= Total Mass 2(1.0) (35.5) 2(36.5) 73.0 g = g

6.2 Balancing a Chemical Equation
A chemical equation is balanced when there are the same numbers of each type of atom on both sides of the equation. Al S Al2S Not Balanced 2Al S Al2S3 Balanced

Using Coefficients to Balance
To balance an equation, place coefficients in front of the appropriate formulas. 4 NH O NO H2O Check the balance by counting the atoms of each element in the reactants and the products. 4 N (4 x 1N) = N (4 x 1N) 12 H (4 x 3H) = 12 H (6 x 2H) 10 O (5 x 2O) = 10 O (4O + 6O)

Learning Check Check the balance of atoms in the following: Fe3O H Fe H2O A. Number of H atoms in products. 1) 2 2) ) 8 B. Number of O atoms in reactants. C. Number of Fe atoms in reactants. 1) 1 2) ) 4

Solution Fe3O4 + 4 H2 3 Fe + 4 H2O Number of H atoms in products.
B. Number of O atoms in reactants. 2) 4 (Fe3O4) C. Number of Fe atoms in reactants. 2) 3 (Fe3O4)

Balancing with Polyatomic Ions
Polyatomic ions can be balanced as a unit when they appear on both sides. Pb(NO3)2 + NaCl NaNO3 + PbCl2 Balance NO3- as a unit Pb(NO3)2 + NaCl NaNO PbCl2 2 NO3– = NO3– Balance Na (or Cl) Pb(NO3) NaCl NaNO3 + PbCl2 2Na = 2Na+ 2Cl– = 2Cl–

Learning Check Balance each equation. The coefficients in the
answers are read from left to right. __Mg + __N __Mg3N2 1) 1, 3, ) 3, 1, ) 3, 1, 1 B. __Al __Cl __AlCl3 1) 3, 3, 2 2) 1, 3, ) 2, 3, 2

Solution A. 3) 3, 1, 1 3 Mg N Mg3N2 B. 3) 2, 3, 2 2 Al Cl AlCl3

Collection Terms A collection term indicates a specific number of items. For example, 1 dozen doughnuts contains 12 doughnuts. 1 ream of paper means 500 sheets. 1 case is 24 cans.

A Mole A mole contains 6.02 x 1023 particles, which is the number of carbon atoms in g of carbon. 1 mole C = x 1023 C atoms The number 6.02 x 1023 is known as Avogadro’s number. One mole of any element contains Avogadro’s number of atoms. 1 mole Na = x 1023 Na atoms 1 mole Au = x 1023 Au atoms

A Mole of Molecules Avogadro’s number is also the number of molecules and formula units in one mole of a compound. One mole of a covalent compound contains Avogadro’s number of molecules. 1 mole CO2 = x 1023 CO2 molecules 1 mole H2O = x 1023 H2O molecules One mole of an ionic compound contains Avogadro’s number of formula units. 1 mole NaCl = 6.02 x 1023 NaCl formula units

Samples of One Mole Quantities

Learning Check A. Calculate the number of atoms in 2.0 moles of Al.
1) Al atoms 2) x 1023 Al atoms 3) x 1024 Al atoms B. Calculate the number of moles of S in 1.8 x 1024 S. 1) mole S atoms 2) mole S atoms 3) x 1048 mole S atoms

Solution A. Calculate the number of atoms in 2.0 moles of Al. 3) x 1024 Al atoms 2.0 moles Al x x 1023 Al atoms 1 mole Al B. Calculate the number of moles of S in 1.8 x 1024 S. 2) 3.0 mole S 1.8 x 1024 S atoms x mole S 6.02 x 1023 S atoms

Molar Mass The mass of one mole is called molar mass.
The molar mass of an element is the atomic mass expressed in grams.

Learning Check Give the molar mass to the nearest 0.1 g.
A. 1 mole of K atoms = ________ B. 1 mole of Sn atoms = ________

Solution Give the molar mass to the nearest 0.1 g.
A. 1 mole of K atoms = 39.1 g B. 1 mole of Sn atoms = g

Molar Mass of CaCl2 For a compound, the molar mass is the sum of the molar masses of the elements in the formula. We calculate the molar mass of CaCl2 to the nearest 0.1 g as follows. Element Number of Moles Atomic Mass Total Mass Ca 1 40.1 g/mole 40.1 g Cl2 2 35.5 g/mole 71.0 g CaCl2 111.1 g

Molar Mass of K3PO4 Determine the molar mass of K3PO4 to 0.1 g. K 3
Element Number of Moles Atomic Mass Total Mass in K3PO4 K 3 39.1 g/mole 117.3 g P 1 31.0 g/mole 31.0 g O 4 16.0 g/mole 64.0 g K3PO4 212.3 g

One-Mole Quantities 32.1 g g g g g

Learning Check A. 1 mole of K2O = ______g
B. 1 mole of antacid Al(OH)3 = ______g

Solution A. 1 mole of K2O 2 moles K (39.1 g/mole) + 1 mole O (16.0 g/mole) 78.2 g g = g B. 1 mole of antacid Al(OH)3 1 mole Al (27.0 g/mole) + 3 moles O (16.0 g/mole) + 3 moles H (1.0 g/mole) 27.0 g g g = g

Learning Check Prozac, C17H18F3NO, is an antidepressant that inhibits the uptake of serotonin by the brain. What is the molar mass of Prozac? 1) g/mole 2) 262 g/mole 3) 309 g/mole

Solution Prozac, C17H18F3NO, is a widely used antidepressant that inhibits the uptake of serotonin by the brain. What is the molar mass of Prozac? 3) 309 g/mole 17C (12.0) + 18H (1.0) + 3F (19.0) + 1N (14.0) + 1 O (16.0) =

Molar Mass Factors Methane CH4 known as natural gas is used in gas cook tops and gas heaters. 1 mole CH4 = g The molar mass of methane can be written as conversion factors. 16.0 g CH and mole CH4 1 mole CH g CH4

Learning Check Acetic acid C2H4O2 gives the sour taste to vinegar. Write two molar mass conversion factors for acetic acid.

Solution Acetic acid C2H4O2 gives the sour taste to vinegar. Write two molar mass factors for acetic acid. 1 mole of acetic acid = g acetic acid 1 mole acetic acid and g acetic acid 60.0 g acetic acid mole acetic acid

Calculations with Molar Mass
Mole factors are used to convert between the grams of a substance and the number of moles. Mole factor Grams Moles

Calculating Grams from Moles
Aluminum is often used for the structure of lightweight bicycle frames. How many grams of Al are in 3.00 moles of Al? 3.00 moles Al x g Al = g Al 1 mole Al mole factor for Al

Learning Check The artificial sweetener aspartame (Nutri-Sweet) C14H18N2O5 is used to sweeten diet foods, coffee and soft drinks. How many moles of aspartame are present in 225 g of aspartame?

Solution Calculate the molar mass of C14H18N2O5.
(14 x 12.0) + (18 x 1.0) + (2 x 14.0) + (5 x 16.0) = 294 g/mole Set up the calculation using a mole factor. 225 g aspartame x 1 mole aspartame 294 g aspartame mole factor(inverted) = mole aspartame

Conservation of Mass In a chemical reaction, the mass of the reactants is equal to the mass of the products moles Ag mole S = 1 mole Ag2S 2 (107.9 g) (32.0 g) = 1 (247.9 g) 247.9 g reactants = g product

Moles in Equations We can read the equation in “moles” by placing the word “moles” between each coefficient and formula. 4 Fe O Fe2O3 4 moles Fe moles O moles Fe2O3 223.2g g

Writing Mole-Mole Factors
A mole-mole factor is a ratio of the coefficients for two substances. 4 Fe O Fe2O3 Fe and O mole Fe and 3 mole O2 3 mole O mole Fe Fe and Fe2O mole Fe and 2 mole Fe2O3 2 mole Fe2O mole Fe O2 and Fe2O mole O and 2 mole Fe2O3 2 mole Fe2O mole O2

Learning Check Consider the following equation: 3 H2 + N2 2 NH3
A. A mole factor for H2 and N2 is 1) 3 mole N ) 1 mole N ) 1 mole N2 1 mole H mole H mole H2 B. A mole factor for NH3 and H2 is 1) 1 mole H ) 2 mole NH ) 3 mole N2 2 mole NH mole H mole NH3

Solution 3 H2 + N2 2 NH3 A. A mole factor for H2 and N2 is
2) 1 mole N2 3 mole H2 B. A mole factor for NH3 and H2 is 2) 2 mole NH3

Calculations with Mole Factors
Consider the following reaction: 4 Fe O Fe2O3 How many moles of Fe2O3 are produced when 6.0 moles O2 react? Use the appropriate mole factor to determine the moles Fe2O3. 6.0 mole O2 x 2 mole Fe2O3 = 4.0 mole Fe2O3 3 mole O2

Mass Calculations

If 209 g of methanol are used up in the combustion,
Methanol (CH3OH) burns in air according to the equation 2CH3OH + 3O CO2 + 4H2O If 209 g of methanol are used up in the combustion, what mass of water is produced? grams CH3OH moles CH3OH moles H2O grams H2O molar mass CH3OH coefficients chemical equation molar mass H2O 1 mol CH3OH 32.0 g CH3OH x 4 mol H2O 2 mol CH3OH x 18.0 g H2O 1 mol H2O x = 209 g CH3OH 235 g H2O

The reaction between H2 and O2 produces 13. 1 g of water
The reaction between H2 and O2 produces 13.1 g of water. How many grams of O2 reacted? 2H O2 2H2O ? g g

Calculating the Mass of a Reactant
The reaction between H2 and O2 produces 13.1 g of water. How many grams of O2 reacted? 2H O2 2H2O ? g g Plan: g H2O mole H2O mole O g O2 13.1 g H2O x 1 mole H2O x 1 mole O2 x g O g H2O mole H2O mole O2 = g O2

Percent Yield You prepared cookie dough to make 5 dozen cookies. The phone rings and you answer. While you talk, a sheet of 12 cookies burns. You have to throw them out. The rest of the cookies are okay. The results of our baking can be described as follows: Theoretical yield 60 cookies possible Actual yield cookies to eat Percent yield 48 cookies x 100 = 80% yield cookies

Percent Yield The theoretical yield is the maximum amount of product calculated using the balanced equation. The actual yield is the amount of product obtained when the reaction is run. Percent yield is the ratio of actual yield compared to the theoretical yield. Percent Yield = Actual Yield (g) x Theoretical Yield (g)

Sample Exercise % Yield
Without proper ventilation and limited oxygen, the reaction of carbon and oxygen produces carbon monoxide. 2C O CO What is the percent yield if 40.0 g of CO are produced from the reaction of 30.0 g O2?

Sample Exercise % Yield (cont.)
1. Calculate theoretical yield of CO. 30.0 g O2 x 1 mole O2 x 2 mole CO x g CO 32.0 g O mole O mole CO = g CO (theoretical) 2. Calculate the percent yield. 40.0 g CO (actual) x 100 = % yield 52.5 g CO(theoretical)

Learning Check In the lab, N2 and 5.0 g of H2 are reacted
and produce 16.0 g of NH3. What is the percent yield for the reaction? N2(g) + 3H2(g) NH3(g) 1) % 2) 57% 3) %

Solution 2) 57% N2(g) + 3H2(g) 2NH3(g)
2) 57% N2(g) + 3H2(g) NH3(g) 5.0 g H2 x 1 mole H2 x 2 moles NH3 x 17.0 g NH3 2.0 g H moles H mole NH3 = g NH3 (theoretical) Percent yield = g NH3 x 100 = 57 % 28 g NH3

Chapter 6 Chemical Reactions
6.8

Types of Reactions Combination Decomposition Single Replacement
Double Replacement Combustion

Combination Reactions
In a combination reaction, two or more elements or simple compounds combine to form one product. A B AB Examples H Cl2 2HCl 2S O2 2SO3 4Fe O2 2Fe2O3

Combination Reactions
In a combination reaction, magnesium and oxygen react to form magnesium oxide. 2Mg + O MgO O2 MgO Mg

Decomposition Reactions
In a decomposition reaction, one substance is broken down (split) into two or more simpler substances. AB A + B 2HgO 2Hg + O2 2KClO3 2KCl + 3 O2

Learning Check Classify the following reactions as
1) combination or 2) decomposition: ___A. H2 + Br HBr ___B. Al2(CO3)3 Al2O3 + 3CO2 ___C. 4 Al + 3C Al4C3

Solution Classify the following reactions as
1) combination or 2) decomposition: 1 A. H2 + Br HBr 2 B. Al2(CO3)3 Al2O3 + 3CO2 1 C. 4 Al + 3C Al4C3

Single Replacement In a single replacement, one element takes the place of an element in a reacting compound. A BC AC B Zn(s) + 2HCl(aq) ZnCl2(aq) + H2(g) H2 HCl Zn ZnCl2

Double Replacement In a double replacement, the positive ions in the reacting compounds switch places. AB CD AD CB AgNO3 + NaCl AgCl + NaNO3 ZnS HCl ZnCl2 + H2S

Example of a Double Replacement
When solutions of sodium sulfate and barium chloride are mixed, solid BaSO4 is produced. BaCl Na2SO BaSO NaCl BaSO4

Learning Check Classify each of the following reactions as a
1) single replacement or 2) double replacement __A. 2Al H2SO Al2(SO4) H2 __B. Na2SO AgNO Ag2SO NaNO3 __C. 3C + Fe2O Fe CO

Solution Classify each of the following reactions as a
1) single replacement or 2) double replacement 1 A. 2Al + 3H2SO Al2(SO4)3 + 3H2 2 B. Na2SO AgNO Ag2SO4 + 2NaNO3 1 C. 3C + Fe2O Fe + 3CO

Combustion In a combustion reaction, a reactant often containing carbon reacts with oxygen O2. C O CO2 CH4 + 2O CO H2O C3H O CO H2O Many combustion reactions utilize fuels that are burned in oxygen to produce CO2, H2O, and energy.

Learning Check Balance the combustion equation:
___C5H ___O ___CO2 + ___H2O

Solution Balance the combustion equation: 1 C5H O CO H2O

Reaction of lead nitrate with sodium Iodide
PbI2

Class of Chemical Reactions 01
Precipitation Reactions: A process in which an insoluble solid precipitate drops out of the solution. Most precipitation reactions occur when the anions and cations of two ionic compounds change partners. Pb(NO3)2(aq) + 2 NaI(aq)  2 NaNO3(aq) + PbI2(s)

Types of Chemical Reactions 02
Acid–Base Neutralization: A process in which an acid reacts with a base to yield water plus an ionic compound called a salt. The driving force of this reaction is the formation of the stable water molecule. HCl(aq) + NaOH(aq)  NaCl(aq) + H2O(l)

Types of Chemical Reactions 03
Oxidation–Reduction (Redox) Reaction: A process in which one or more electrons are transferred between reaction partners. The driving force of this reaction is the decrease in electrical potential. 4 Fe O Fe2O3

Reaction of lead nitrate with sodium Iodide
PbI2

Precipitation Reactions
Precipitate – insoluble solid that separates from solution PbI2 precipitate Pb(NO3)2 (aq) + 2NaI (aq) PbI2 (s) + 2NaNO3 (aq) molecular equation Pb2+ + 2NO3- + 2Na+ + 2I PbI2 (s) + 2Na+ + 2NO3- ionic equation Pb2+ + 2I PbI2 (s) net ionic equation Na+ and NO3- are spectator ions

Writing Net Ionic Equations
Write the balanced equation (molecular equation). Write the ionic equation showing the water soluble compounds in their ionic forms. Determine precipitate from solubility rules Cancel the spectator ions on both sides of the ionic equation Write the net ionic equation for the reaction of silver nitrate with sodium chloride in water. AgNO3 (aq) + NaCl (aq) AgCl (s) + NaNO3 (aq) Ag+ + NO3- + Na+ + Cl AgCl (s) + Na+ + NO3- Ag+ + Cl AgCl (s)

Chapter 6 Chemical Reactions
6.12 Redox Reactions

Oxidation and Reduction
Are an important type of reaction. Provide us with energy from food. Provide electrical energy in batteries. Occur when iron rusts. 4Fe + 3O Fe2O3

Electron Loss and Gain An oxidation-reduction reaction involves the transfer of electrons from one reactant to another. In oxidation, electrons are lost. Zn Zn2+ + 2e- (loss of electrons) In reduction, electrons are gained. Cu e Cu (gain of electrons)

Half-Reactions for Oxidation-Reduction
In the oxidation-reduction reaction of zinc and copper(II) sulfate, the zinc is oxidized and the Cu2+ (from Cu2+ SO42-) is reduced. Zn Zn e- oxidation Cu e Cu reduction

Redox Reactions 02

Learning Check Identify each of the following as an
1) oxidation or a 2) reduction: __A. Sn Sn e- __B. Fe e- Fe2+ __C. Cl e- 2Cl-

Solution Identify each of the following as an
1) oxidation or a 2) reduction: 1 A. Sn Sn e- 2 B. Fe e- Fe2+ 2 C. Cl e- 2Cl-

Balanced Red-Ox Equations
In a balanced oxidation-reduction equation, the loss of electrons is equal to the gain of electrons. Zn + Cu Zn2+ + Cu The loss and gain of two electrons is shown in the separate oxidation and reduction reactions. Zn Zn2+ + 2e- oxidation Cu e Cu reduction

Learning Check In light-sensitive sunglasses, UV light initiates
an oxidation-reduction reaction. uv light Ag+ + Cl Ag Cl A. Which reactant is oxidized? 1) Ag ) Cl ) Ag B. Which reactant is reduced? 1) Ag ) Cl ) Cl

Solution In light-sensitive sunglasses, UV light initiates
an oxidation-reduction reaction. uv light Ag+ + Cl– Ag Cl A. Which reactant is oxidized 2) Cl– Cl– Cl + e– B. Which reactant is reduced? 1) Ag+ Ag+ + e– Ag

Learning Check Write the separate oxidation and reduction half reactions for the following equation. 2Cs F CsF

Solution Write the separate oxidation and reduction reactions for the following equation. 2Cs F CsF 2Cs Cs e– oxidation F e– 2F- reduction

Oxidation with Oxygen An early definition of oxidation is the addition of oxygen O2 to a reactant. A metal or nonmetal is oxidized while the O2 is reduced to O2-. 4K + O K2O C + O CO2 2SO2 + O SO3

Gain and Loss of Hydrogen
In organic and biological reactions, oxidation involves the loss of hydrogen atoms and reduction involves a gain of hydrogen atoms. oxidation = Loss of H reduction = Gain of H CH3OH H2CO H (loss of H) Methanol Formaldehyde

Oxidation–Reduction Reactions 02
Is Loss (of electrons) Anode Oxidation Reducing Agent

Oxidation–Reduction Reactions 03
Is Gain (of electrons) Cathode Reduction Oxidizing Agent

Oxidation Number Rules
Applies to Statement 1 Elements The oxidation number of an atom in an element is zero. 2 Monatomic ions The oxidation number of an atom in a monatomic ion equals the charge of the ion. 3 Oxygen The oxidation number of oxygen is –2 in most of its compounds. (An exception is O in H2O2 and other peroxides, where the oxidation number is –1.)

Oxidation Number Rules
Applies to Statement 4 Hydrogen +1, it will be -1 when hydrogen comes with metal. NaH 5 Halogens Fluorine is –1 in all its compounds. Each of the other halogens is –1 in binary compounds unless the other element is oxygen. 6 Compounds and ions The sum of the oxidation numbers of the atoms in a compound is zero. The sum in a polyatomic ion equals the charge on the ion.

HCO3- O = -2 H = +1 3x(-2) + 1 + ? = -1 C = +4
Oxidation numbers of all the elements in HCO3- ? HCO3- O = -2 H = +1 3x(-2) ? = -1 C = +4

IF7 F = -1 7x(-1) + ? = 0 I = +7 K2Cr2O7 NaIO3 Na = +1 O = -2 O = -2
Oxidation numbers of all the elements in the following ? F = -1 7x(-1) + ? = 0 I = +7 K2Cr2O7 NaIO3 Na = +1 O = -2 O = -2 K = +1 3x(-2) ? = 0 7x(-2) + 2x(+1) + 2x(?) = 0 I = +5 Cr = +6

Chapter Summary Chemical equations must be balanced, that is, the numbers and kinds of atoms must be the same in the reactants and the products. To balance an equation, coefficients are placed before formulas. The coefficients in a balanced equation represent the numbers of moles of reactants and products in a reaction. A mole refers to Avogadro’s number (6.022x1023) of formula units of a substance.

Chapter Summary Contd. One mole of any substance has a mass equal to the molecular or formula weight of the substance in grams. The ratios of coefficients act as mole ratios that relates amounts of reactants and/or products. The yield of a reaction is the amount of product obtained. The percent yield is the amount of product obtained divided by the amount theoretically possible and multiplied by 100.

Chapter Summary Contd. Three common types of reactions of ionic compounds are: Precipitation reactions Acid-base neutralization reaction Oxidation-reduction reactions By comparing the oxidation numbers of an atom before and after reaction, we can tell whether the atom has gained or lost shares in electrons and thus whether a redox reaction has occurred. Oxidation numbers are assigned to atoms in reactants and products to provide a measure for whether an atom is neutral, electron-rich, or electron-poor.

End of Chapter Six

Personal Response System Questions for use with Fundamentals of General, Organic, and Biological Chemistry, 5th ed. Media Update Edition McMurry and Castellion Chapter 6

Assume the mixture of substances in drawing (a) undergoes a reaction
Assume the mixture of substances in drawing (a) undergoes a reaction. Which of the drawings (b)-(d) represents a product mixture consistent with the law of mass conservation? All drawings (b)-(d) Only drawing (b) Only drawing (c) Only drawing (d)

Reaction of A (unshaded spheres) with B (shaded spheres is shown schematically in the diagram below. Which equation best describes the reaction? A + B  AB 4 A + 2 B  4 AB A2 + B2  A2B 2 A2 + B2  2 A2B

a CH3CH2OH + b O2  c CO2 + d H2O When the above equation is balanced, the coefficients a, b, c, and d are a=1, b=1, c=1, d=1 a=1, b=2, c=2, d=3 a=1, b=3, c=2, d=3 a=2, b=7, c=4, d=6

Which of the following reactions is an acid-base neutralization reaction?
AgNO3(aq) + NaBr(aq)  AgBr(s) + NaNO3(aq) 2 CH3OH(l) + 3 O2 (g)  2 CO2(g) + 4 H2O(l) 2 Na(s) + Br2(l)  2 NaBr(s) H2SO4(aq) + 2 KOH(aq)  2 H2O(l) + K2SO4(aq)

Predict which of the following solutions will result in a precipitation reaction.
Cr(NO3)3(aq) + KCl(aq)  CuCl2(aq) + Na2S(aq)  NH4Br(aq) + Na2SO4(aq)  CsOH(aq) + RbCl(aq) 

Identify the oxidized reactant, the reduced reactant, the oxidizing agent, and the reducing agent in the reaction: Fe2O3(s) + 3 CO(g)  2 Fe(s) + 3 CO2(g). CO(g) is oxidized and is the oxidizing agent and Fe2O3(s) is reduced and is the reducing agent. CO(g) is oxidized and is the reducing agent and Fe2O3(s) is reduced and is the oxidizing agent. CO(g) is reduced and is the oxidizing agent and Fe2O3(s) is oxidized and is the reducing agent. CO(g) is reduced and is the reducing agent and Fe2O3(s) is oxidized and is the oxidizing agent.

Chapter 6 Chemical Reactions Classification and Mass Relationship.

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