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King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 21.

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Presentation on theme: "King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 21."— Presentation transcript:

1 King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 21

2 Objective To introduce the concept of angular impulse and momentum.

3 Definition Moment = “عزم” = r x F Angular momentum about point O is defined as the “ moment ” of the particle ’ s linear momentum about O. Angular momentum (H o ) = moment of linear momentum ( r x mV)

4 Line of action of the force F Torque = Fl l Torque” Moment” = F l Torque = F l F l l Cheater Pipe F

5 ANGULAR MOMENTUM For a point object the angular momentum is r m v Units - kg. m 2 /s or sl. ft 2 /s It is a vector. Here the vector is pointing toward you. Using right-hand rule

6 Angular Momentum

7 Relation Between Moment of a Force and Angular Momentum Resultant moment = Rate of change of angular momentum Resultant force = Rate of change of linear momentum

8 System of Particles Internal force cancel each other Sum of the moments about O of all the external forces acting On a system of particle = rate of change of the total angular Momentum of the system of particles about point O

9 Example 15-12

10 Angular Impulse and Momentum Principles

11 Scalar Formulation Conservation of Angular Momentum Angular impulse is zero

12 Example 15-13

13 Example 15-14 W = 0.8 Ib Smooth table r 1 =1.7 ft v 1 = 4 ft/s v c =6ft/s v 2 = ? at (r 2 )= 0.6ft Work done = ? Work Done

14 Example 15-15

15 Problem 15-101 m = 400 g v 1 = 2 m/s M = 0.6 N.m v 2 =? t = 3 s

16 Problem 102 m = 5-Ib v 1 = 0 ft/s M = ( 0.5 t + 0.8 ) Ib.ft v 2 = ? t = 4 s

17


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