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4. Newton's Laws 1.The Wrong Question 2.Newton’s 1 st & 2 nd laws 3.Forces 4.The Force of Gravity 5.Using Newton’s 2 nd Law 6.Newton’s 3 rd Law.

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Presentation on theme: "4. Newton's Laws 1.The Wrong Question 2.Newton’s 1 st & 2 nd laws 3.Forces 4.The Force of Gravity 5.Using Newton’s 2 nd Law 6.Newton’s 3 rd Law."— Presentation transcript:

1 4. Newton's Laws 1.The Wrong Question 2.Newton’s 1 st & 2 nd laws 3.Forces 4.The Force of Gravity 5.Using Newton’s 2 nd Law 6.Newton’s 3 rd Law

2 What forces govern the motion of the sailboard? Ans: Human body: contact force Wind & water: fluid pressure Gravity: action-at-a-distance

3 4.1. The Wrong Question Q: Why do things move? Aristotle (~350BC) : Because some forces are acting on them. Galileo (~1600) : Wrong question ( things move until stopped ). The right question: Why do moving things change direction? Newton: Because some forces are acting on them. If a ball is released here … … it always rises to its starting height … … so this ball should roll forever.

4 4.2. Newton’s 1 st & 2 nd laws Net force determines motion. Newton’s 1 st law of motion: A body at rest or in uniform motion remains so unless acted on by a nonzero net force. F net  0  v  F net = 0  v = const

5 GOT IT? 4.1. On a horizontal tabletop is a curved barrier that exerts a force on a ball, guiding its motion in a circular path. After the ball leaves the barrier, which of the dashed paths shown does it follow?

6 Newton’s 2 nd Law Newton’s 2 nd law of motion: The rate of change of momentum is equal to the net force. Momentum: ( quantity of motion ) For a constant mass:

7 Mass, Inertia, & Force Loaded truck has greater mass, more inertia, less acceleration. Inertia: resistance to changes in motion. 1 st law = law of inertia  Operational definition of mass 1 N (Newton)  force required to give a mass of 1 Kg an acceleration of 1 m / s 2. 1 N = 1 Kg m / s 2. 1 Dyne = 1 g cm / s 2.

8 Example 4.1. Accelerating Car A 1200 kg car accelerates constantly in a straight line from rest to 20 m/s in 7.8 s. a)What is the net force on it? b)What is the net force on it if it rounds a bend 85 m in radius at v = 20 m/s?

9 Inertial Reference Frames Inertial Reference Frames: reference frame in which Newton’s 1 st law works. Examples of non-inertial reference frames: Accelerating planes. Car rounding a curve. Merry-go-round. Earth (rotating). Examples of inertial reference frames: Newton: Distant “fixed” stars. Einstein: General relativity.

10 4.3. Forces Examples of forces: Pushes & pulls. Car collided with truck & stopped. Moon circles Earth. Person sitting on chair. Climber on rope. (action-at-a distance) (contact force) (tension force) F c =  F g T =  F g

11 The Fundamental Forces The fundamental forces: Gravity: large scale phenomena Electroweak force Electromagnetic force: everyday phenomena Weak (nuclear) force Strong (nuclear) force 1 10 25 10 36 10 38

12 4.4. The Force of Gravity m in f = m a is the inertia mass (same everywhere). Weight = force of gravity on mass: For a mass of 65 kg, weight on Earth = (65 kg) (9.8 m/s 2 ) = 640 N. weight on Moon = (65 kg) (1.6 m/s 2 ) = 100 N. weight in outer-space = (65 kg) (0 m/s 2 ) = 0 N. Caution: In daily use, weight is often measured in units of mass. E.g., a person “weights” 65 kg. Strictly speaking, m in w = m g is the gravitational mass. Galileo experiment: m I = m G (coincidence) Einstein: m I = m G (exact: gravity is geometry)

13 Weightlessness These astonauts feel “weightless” because they are in freefall. Their weight is about 93% of that on surface. same a

14 4.5. Using Newton’s 2 nd Law Tactics 4.1. Free-Body Diagram 1.Identify object of interest & forces on it. 2.Object  dot. 3.Draw forces on object as vectors at dot.

15 Example 4.3. Elevator A 740 kg elevator accelerates upward at 1.1 m/s 2. Find the tension force on the cable (of negligible mass).

16 GOT IT? 4.4. How’s T compared to w = m g if the elevator a)moves upward starting at rest. b)decelerates to stop while moving upward. c)starts moving downward, accelerating from rest. d)slows to stop while moving downward. e)moves upward with constant speed. greater equal less

17 Conceptual Example 4.1. At the Equator When you stand on a scale, the scale reading shows the force it pushes up to support you. If you stand on a scale at Earth’s equator, is the reading greater or less than your weight? Ans: You’re in uniform circular motion so that the net force on you is centripetal. F scale W = m g m a

18 Parabolic Flight

19 4.6. Newton’s 3 rd Law Newton’s 3 rd law: Action = Reaction Forces of 3 rd law pair act on different objects. Hence, they don’t cancel each other out. Horse-Cart dilemma

20 Example 4.4. Pushing Books 2 books lie on frictionless horizontal surface. You push with force F on books of mass m 1. which in turn on book of mass m 2. What force does the 2 nd book exert on the 1 st ? Acceleration of books: Net force on 2 nd book: Force exerted by 2 nd book on the 1 st

21 GOT IT? 4.5 Is the net force on the larger block (a) greater than 2 N, (b) equal to 2N or (c) less than 2 N ?

22 Normal force n : contact force acting normal to contact surface. 3 rd law also applies to non-contact forces such as gravity. Not a 3 rd law pair Normal force F net  0

23 Measuring Force Force can be measured using Newton’s 3 rd law. Ideal spring (Hooke’s law): k = spring constant Works only in inertial frame. f sp = 0 f sp =  f wall < 0 f sp =  f wall > 0

24 Example 4.5. Helicopter Ride Helicopter rises vertically. A 35 kg bag sits in it on a spring scale of k = 3.4 kN/m. By how much the spring compresses (a)when helicopter is at rest (b) when it’s accelerating upward at 1.9 m/s 2. (a) (b)

25 GOT IT? 4.6 Continued from Example 4.5: (a)Would the answer to (a) change if the helicopter were moving upward with constant speed? (b)Would the answer to (b) change if the helicopter were moving downward but still accelerating upward? Example 4.5: Helicopter rises vertically. A 35 kg bag sits in it on a spring scale of k = 3.4 kN/m. By how much the spring compresses (a)when helicopter is at rest (b) when it’s accelerating upward at 1.9 m/s 2. No


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