Presentation on theme: "1/21 do now A particle of mass m slides down a fixed, frictionless sphere of radius R starting from rest at the top. In terms of m, g, R, and θ, determine."— Presentation transcript:
11/21 do nowA particle of mass m slides down a fixed, frictionless sphere of radius R starting from rest at the top. In terms of m, g, R, and θ, determine each of the following for the particle while it is sliding on the sphere. The kinetic energy of the particleThe centripetal acceleration of the massThe tangential acceleration of the massDetermine the value of θ at which the particle leaves the sphere.
2AssignmentRegent book chapter 8 questions are due Monday
3Dynamics of Rotational Motion Chapter 10Dynamics of Rotational Motion
4Goals for Chapter 10To examine examples of torqueTo see how torques cause rotational dynamics (just as linear forces cause linear accelerations)To examine the combination of translation and rotationTo calculate the work done by a torqueTo study angular momentum and its conservationTo relate rotational dynamics and angular momentum
510.1 TorqueThe quantitative measure of the tendency of a force to change a body’s rotational motion is called torque;Fa applies a torque about point O to the wrench.Fb applies a greater torque about O,and Fc applies zero torque about O.
6Lines of force and calculations of torques The tendency of a force F to cause a rotation about O depends onthe magnitude Fthe perpendicular distance l1 between point O and the line of force. We call the distance l1 the lever arm of force F1about O.We define the torque of the force F with respect to O as the product F∙l. We use the Greek letter τ (tau) for torque.τ = F∙lF: forcel: the perpendicular distance between point O and the line of force
8The units of torque The SI unit of torque is the Newton-meter. Torque is not work or energy, and torque should be expressed in Newton-meters, not joules.
9r∙sin - perpendicular distance If φ is angle between force F and distance rτ = F∙(r∙sin)r∙sin - perpendicular distanceτ = r∙(F∙sin)F∙sin - perpendicular force
10The direction of torque Torque is a vector quantityMagnitude:The direction of torque is perpendicular to both r and F, which is directed along the axis of rotation, with a sense given by the right-hand rule.counterclockwise torques are positive and clockwise torques are negative.A dot ● means pointing out of the screenA cross × means pointing into the screen
11Example 10.1 applying a torque A weekend plumber, unable to loosen a pipe fitting, slips a piece of scrap pipe over his wrench handle. He than applies his full weight of 900 N to the end of the cheater by standing on it. The distance from the center of the fitting to the point where the weight acts is 0.80 m, and the wrench handle and cheater make an angle of 19o with the horizontal. Find the magnitude and direction of the torque he applies about the center of the pipe fitting.
12Test Your Understanding 10.1 The figure shows a force P being applied to one end of a lever of length L. What is the magnitude of the torque of this force about point APLsinθPLcosθPLtanθ
13Example Torque is the rotational analogue of kinetic energy linear momentumaccelerationforcemass
14ExampleA force F of magnitude F making an angle θ with the x axis is applied to a particle located along axis of rotation A, at Cartesian coordinates (0,0) in the figure. The vector F lies in the xy plane, and the four axes of rotation A, B, C, and D all lie perpendicular to the xy plane. Express the torque about axis A at Cartesian coordinates (0,0).Express the torque about axis B in terms of F, θ, φ, π, and/or other given coordinate data.b
15ExampleA square metal plate m on each side is pivoted about an axis through point at its center and perpendicular to the plate. Calculate the net torque about this axis due to the three forces shown in the figure if the magnitudes of the forces are F1 = 21.0 N , F2 = 17.0 N, and F3 = 14.9 N . The plate and all forces are in the plane of the page. Take positive torques to be counterclockwise.
161/23 do nowRank the design scenarios (A through C) on the basis of the tension in the supporting cable from largest to smallest. In scenarios A, and C, the cable is attached halfway between the midpoint and end of the pole. In B, the cable is attached to the end of the pole.sign60osign45o30osignABCB, C, A
1710.2 Torque and Angular Acceleration for a Rigid Body For particle 1, Newton’s second law for the tangential component is:For every particle in the body, we add all the torques:τ = Iα is just like F = ma
184 things to note in Eq. The equation is valid only for rigid bodies. Since we used atan = r∙αz, αz must be measured in rad/s2.Since all the internal torques add to zero, so the sum ∑τ in Eq. ∑τ = Iα includes only the torques of the external forces.Often, an important external force acting on body is its weight. We assume that all the weight is concentrated at the center of mass of the body to get the correct torque (about any specified axis).
19Example 10.2 An unwinding cable I A cable is wrapped several times around a uniform solid cylinder that can rotate about its axis. The cylinder has diameter m and mass 50 kg. The cable is pulled with a force of 9.0 N. Assume that the cable unwinds without stretching or slipping, what is its acceleration?
20Example 10.3 An unwinding cable II Consider the situation on the diagram, find the acceleration of the block of mass m.
21Test Your Understanding 10.2 The figure shows a glider of mass m1 that can slide without friction on horizontal air tract. It is attached to an object of mass m2 by a massless string. The pulley has radius R and moment of inertia I about it axis of rotation. When released, the hanging object accelerates downward, the glider accelerates to the right, and the string turns the pulley without slipping or stretching. Rank the magnitudes of the following forces that acting during the motion, in order from largest to smallest magnitude.The tension force (magnitude T1) in the horizontal part of the string;The tension force (magnitude T2) in the vertical part of the string;The weight m2g of the hanging object.
22ExampleA light rigid massless rod with masses attached to its ends is pivoted about a horizontal axis as shown above. When released from rest in a horizontal orientation, what is the magnitude of the angular acceleration of the rod?
241/24 do nowFind the magnitude of the angular acceleration α of the swing bar.
25Assignments Due Monday 1/27 Regents book questions 8A-8E All classwork packets
261/27 do nowIf Anya decides to make the star twice as massive, and not change the length of any crossbar or the location of any object, what does she have to do with the mass of the smiley face to keep the mobile in perfect balance? Note that she may have to change masses of other objects to keep the entire structure balanced.make it eight times more massivemake it four times more massivemake it twice as massiveNothingimpossible to tell
27Assignments Due today: Due Friday: Regents book questions 8A-8E The two class work packetsDue Friday:Additional practice packet: #1,4,8,13,19,22,26,27,28,29
2810.3 A rigid body in motion about a moving axis When a rigid body rotate about a moving axis, the motion of the body is combined translation and rotation. We need to combine:Translational motion of the center of massRotation about an axis through the center of mass.
29Combined Translation and Rotation: Energy Relationships The kinetic energy of a rigid body that has both translational and rotational motions is the sum of a part ½ Mvcm2 associated with motion of the center of mass and a part ½ Icmω2 associated with rotation about an axis through the center of mass.
30Rolling without slipping vcm = Rω(condition for rolling without slipping)If a rigid body changes height as it moves, we must also consider gravitational potential energy. U = Mgycm
31Example 10.4 Speed of a primitive yo-yo A primitive yo-yo is made by wrapping a string several times around a solid cylinder with mass M and radius R. You hold the end of the string stationary while releasing the cylinder with no initial motion. The string unwinds but does not slip or stretch as the cylinder drops and rotates. Use energy considerations to find the speed vcm of the center of mass of the solid cylinder after it has dropped a distance h.
32Example 10.5 Race of the rolling bodies In a physics lecture demonstrations, an instructor “races” various round rigid bodies by releasing them from rest at the top of an inclined plane. What shape should a boby have to reach the bottom of the incline first?The smaller the moment of inertia the body has, the faster the body is moving at the bottom because they have less of their kinetic energy tied up in rotation and have more available for translation.The order of finish is as follows:Solid sphereSolid cylinder,Thin-walled hollow sphereThin-walled hollow cylinder
33Combined translation and rotation: Dynamics When a rigid body with total mass M moves, its motion can be described by combining translational motion and rotational motionIn translational motion:The rotational motion about the center of mass:Note: when we learned this equation, we assumed that the axis of rotation was stationary. But in fact, this equation is valid even when the axis of rotation moves, provided the following two conditions are met:The axis through the center of mass must be an axis of symmetry.The axis must not change direction.
34Example 10.6 Acceleration of a primitive yo-yo For the primitive yo-yo in Example 10.4, find the downward acceleration of the cylinder and the tension in the string.
35Example 10.7 Acceleration of a rolling sphere A solid bowling ball rolls without slipping down the return ramp at the side of the alley. The ramp is inclined at an angle β to the horizontal. What are the ball’s acceleration and the magnitude of the friction force on the ball? Treat the ball as a uniform solid sphere, ignoring the finger holes.
37Test Your Understanding 10.3 Suppose the solid cylinder used as a yo-yo in example 10.6 is replaced by a hollow cylinder of the same mass and radiusWill the acceleration of the yo-yoIncreaseDecrease,Remain the same?Will the string tensionIncrease,
38exampleTwo uniform identical solid spherical balls each of mass M, radius r and moment of inertial about its center 2/5MR2, are released from rest from the same height h above the horizontal ground Ball A falls straight down, while ball B rolls down the distance x along the inclined plane without slipping.If the velocity of ball A as it hits the ground is VA, what is the velocity VB of ball B as it reaches the ground?In terms of acceleration due to earth’s gravity g, determine the acceleration of ball B along the inclined plane.
39ExampleWhile exploring a castle, Dan spotted by a dragon who chases him down a hallway. Dan runs into a room and attempts to swing the heavy door shut before the dragon gets to him. The door is initially perpendicular to the wall, so it must be turned through 90o to close it. The door is 3.00 m tall and 1.25 m wide, and it weighs 750 N. You can ignore the friction at the hinges. If Dan applies a force of 220 N at the edge of the door and perpendicular to it, how much time does it take him to close the door?If Dan doubles the force, how long would it take to close the door.
4010.4 Work and Power in Rotational Motion The work dW done by the force Ftan while a point on the rim moves a distance ds is dW = Ftan∙ds. If dθ is measured in radians, then ds = R∙dθIf τz is constant
41Work done by a constant torque The work done by a constant torque is the product of torque and the angular displacement. If torque is expressed in Newton-meters and angular displacement in radian, the work is in joules. Only the tangent component of force does work, other components do no work.When a torque does work on a rotating rigid body, the kinetic energy changes by an amount equal to the work done.Wtot = ½ I∙ω22 – ½ I∙ω12
42Power is the rate of doing work When a torque acts on a body the rotates with angular velocity ωz, its power is the product of τz and ωz. This is the analog of the relationship P = F∙v
43Example 10.8 Engine power and torque The power output of an automobile engine is advertised to be 200 hp at 6000 rpm. What is the corresponding torque?
44Example 10.9 Calculating power from torque An electric motor exerts a constant torque of 10 N∙m on a grinding stone mounted on its shaft. The moment of inertia of the grinding stone about the shaft is 2.0 kg∙m2. If the system starts from rest, find the work done by the motor in 8.0 seconds and the kinetic energy at the end of this time. What was the average power delivered by the motor?
45Test Your Understanding 10.4 You apply equal torques to two different cylinders, one of which has a moment of inertial twice as large as the other cylinder. Each cylinder is initially at rest after one complete rotation, which cylinder has the greater kinetic energy?The cylinder with the larger moment of inertia;The cylinder with the smaller moment of inertia;Both cylinders have the same kinetic energy.
46exampleA thin, uniform, 19.0 kg post, 1.95 m long, is held vertically using a cable and is attached to a 5.00 kg mass and a pivot at its bottom end as shown. The string attached to the 5.00 kg mass passes over a massless, frictionless pulley and pulls perpendicular to the post. Suddenly the cable breaks. Find the angular acceleration of the post about the pivot just after the cable breaks.
4710.5 angular Momentumangular momentum of a particle is a vector quantity denoted as L.The value of L depends on the choice of origin O, since it involves the particle’s position vector relative to O.The unit of angular momentum are kg∙m2/s.L is perpendicular to the xy-plane. It direction is determined by the right-hand rule.The magnitude of L is L = (mvsinΦ)r or L = mv(rsinΦ)Perpendicular component of pPerpendicular component of ror
48When a net force F acts on a particle, its velocity and momentum changes: Similarly, when the torque of the net force acting on a particle, its angular velocity and angular momentum changes:
49The derivation ofIf we take the time derivative of , using the rule for the derivative of a product:
50Angular Momentum of a Rigid Body In a rigid body rotating around an axis, each particle moves in a circle centered at the origin, and at each instant its velocity vi is perpendicular to its position vector ri. Hence Φ = 90o for every particle. A particle with mass mi at a distance ri from O has a speed vi = riω. The magnitude of its angular momentum is:Li = (mivisinΦ)ri = (miriω)ri = miri2ωThe total angular momentum of the slice of the body lying in the xy-plane is the sum ∑Li of the angular momenta Li of the particles:
51ExampleA particle of mass m moves with a constant speed v along the dashed line y = a. When the x-coordinate of the particle is xo, what is the magnitude of the angular momentum of the particle with respect to the origin of the system?
52Example 10.10 Angular momentum and torque A turbine fan in a jet engine has a moment of inertia of 2.5 kg∙m2 about its axis of rotation. As the turbine is starting up, its angular velocity as a function of time isFind the fan’s angular momentum as a function of time, and find its value at time t = 3.0 sFind the net torque acting on the fan as a function of time, and find the torque at time t = 3.0 s.
53ExampleA uniform rod of mass M and length L has a moment of inertia about one end I = ML2/3. It is released from rest in horizontal direction about the fixed axis perpendicular to the paper as shown below.What is the linear velocity of the center of mass, cm, when the rod is in the vertical position?What is the angular momentum of the rod about the axis of rotation at one end?
54Test Your Understanding 10.5 A ball is attached to one end of a piece of string. You hold the other end of the string and whirl the ball in a circle around your hand.If the ball moves at a constant speed, is its linear momentum p constant? Why or why not?Is its angular momentum L constant? why or why not?
5510.6 conservation of Angular Momentum Like conservation of energy and of linear momentum, the principle of conservation of angular momentum is a universal conservation law, valid at all scales from atomic and nuclear systems to the motions of galaxies.The principle follows directly from equation: ∑τ = dL/dtIf ∑τ = 0, then dL/dt = 0, and L is constant.When the net external torque acting on a system is zero, the total angular momentum of the system is constant (conserved).
56A circus acrobat, a diver, and an ice skater pirouetting on the toe of one skate all take advantage of this principle.I1ω1z = I2ω2zWhen a system has several parts, the internal forces that the parts exert on each other cause changes in the angular momenta of the parts, but the total angular momentum doesn’t change. The total angular momentum of the system is constant.
57Example 10.11 Anyone can be a ballerina An acrobatic physics professor stands at the center of a turntable, holding his arms extended horizontally with a 5.0 kg dumbbell in each hand. He is set rotating about a vertical axis, making one revolution in 2.0 s. Find the prof’s new angular velocity if he pulls the dumbbells in to his stomach. His moment of inertia without the dumbbells is 3.0 kgm2 when his arms are out-stretched, dropping to 2.2 kgm2 when his hands are at his stomach. The dumbbells are 1.0 m from the axis initially and 0.20 m from it at the end. Treat the dumbbells as particles.
58Example 10.12 A rotational “collision” I The figure bellow shows two disks: A is an engine flywheel, and B is a clutch plate attached to a transmission shaft. Their moments of inertia are IA and IB; initially, they are rotating with constant angular speeds ωA and ωB, respectively. We then push the disks together with forces acting along the axis, so as not to apply any torque on either disk. The disks rub against each other and eventually reach a common final angular speed ω. Derive an expression for ω.
59Example 10.12 A rotational “collision” II In Example 10.12, suppose flywheel A has a mass of 2.0 kg, a radius of 0.20 m, and an initial angular speed of 50 rad/s and that clutch plate B has a mass of 4.0 kg, a radius of 0.10 m, and an initial angular speed of 200. rad/s. Find the common final angular speed ω after the disks are pushed into contact. What happens to the kinetic energy during this process?
60Example 10.4 Angular momentum in a crime bust A door 1.00 m wide, of mass 15 kg, is hinged at one side so that it can rotate without friction about a vertical axis. It is unlatched. A police officer fires a bullet with a mass of 10 g and a speed of 400 m/s into the exact center of the door, in a direction perpendicular to the plane of the door. Find the angular speed of the door just after the bullet embeds itself in the door. Is kinetic energy conserved?
61Test Your Understanding 10.6 If the polar ice caps were to completely melt due to global warming, the melted ice would redistribute itself over the earth. This change would cause the length of the day (the time needed for the earth to rotate once in its axis) toIncreaseDecreaseRemain the same(hint: use angular momentum ideas. Assume that the sun, moon, and planets exert negligibly small torques on the earth.)L = IωI increases, ω decreases, days is longer.
62ExampleA uniform rod of mass M and length L has a moment of inertia about one end I = ML2/3. It is released from rest in horizontal direction about the fixed axis perpendicular to the paper as shown below.What is the linear velocity of the center of mass, cm, when the rod is in the vertical position?What is the angular momentum of the rod about the axis of rotation at one end?
63exampleTwo equal masses, each m, are resting at the ends of a uniform rod of length 2a and negligible mass. The system is in equilibrium about the center C of the rod. A piece of clay of mass m is dropped down on the mass at the right end, hits it with velocity v as shown below and sticks to it.What is the ratio of the kinetic energy Ef just after the collision to the kinetic energy Ei just before the collision, Ef/Ei, of the system?
64exampleA skater is spinning on ice with her arms outstretched about the vertical axis at an angular speed of ω. When she brings her arms close to her body, which of the following statements is correct?Her angular velocity and angular momentum remain constant.Her angular momentum is increased.Her kinetic energy is increased.Her kinetic energy is decreased.The net torque on her about the axis of rotation increases.
65exampleA uniform diving board, 12 meters long and 20 kg in mass, is hinged at P, which is 5 meters from the edge of the platform. An 80 kg diver is standing at the other end of the board.What will be the force exerted by the hinge on the board?What will be the normal force on the board at the edge of the platform?
66ExampleMasses M1 and M2 are separated by a distance L. what is the distance of the center of mass of the system at P from M1 as shown above?What is the moment of inertial of the system about the center of mass at P?
67exampleA mass M slides down a smooth surface from height h and collides inelastically with the lower end of a rod that is free to rotate about a fixed axis at P as shown below. The mass of the rod is also M, the length is l, and the moment of inertial about P is ml2/3.What is the angular velocity of the rod about the axis P jut after the mass sticks to it?
68ExampleA solid, uniform cylinder with mass 8.45 kg and diameter 11.0 cm is spinning with angular velocity 230 rpm on a thin, frictionless axle that passes along the cylinder axis. You design a simple friction-brake to stop the cylinder by pressing the brake against the outer rim with a normal force. The coefficient of kinetic friction between the brake and rim is What must the applied normal force be to bring the cylinder to rest after it has turned through 5.15 revolutions?
69ExampleA wheel with a weight of 395 N comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at an angular velocity of 26.8 rad/s. The radius of the wheel is 0.652 m and its moment of inertia about its rotation axis is MR2 . Friction does work on the wheel as it rolls up the hill to a stop, at a height of above the bottom of the hill; this work has a magnitude of 3520 J. Calculate h. Use 9.81 m/s2 for the acceleration due to gravity.
70ExampleThe radius of the pulley is r and mass M is initially at height h. The system is initially at rest and is then released at time t = 0. Assume M>m.Assuming the pulley to be massless and frictionless, what is the angular acceleration of the pulley while M is falling?hMmr
71ExampleAn object of moment of inertial I is initially at rest when torque T begins to act on it as shown below. After t seconds,what is the angular velocity of the object in terms of T, I and t?What is the kinetic energy of the object?
72ExampleA solid, uniform cylinder with mass 8.45 kg and diameter 11.0 cm is spinning with angular velocity 230 rpm on a thin, frictionless axle that passes along the cylinder axis. You design a simple friction-brake to stop the cylinder by pressing the brake against the outer rim with a normal force. The coefficient of kinetic friction between the brake and rim is What must the applied normal force be to bring the cylinder to rest after it has turned through 5.15 revolutions?
73ExampleA hoop is rolling to the right without slipping on a horizontal floor at a steady 1.8 m/s (Vcm).Find the velocity vector of each of the following points, as viewed by a person at rest on the ground:The highest point on the hoopThe lowest point on the hoopA point on the right side of the hoop, mideway abetween the top and the bottomfind the velocity vector of each of the above points, as viewed by a person moving along with the same velocity as the hoop.
74ExampleFind the magnitude of the angular momentum of the second hand on a clock about an axis through the center of the clock face. The clock hand has a length of 15.0 cm and a mass of 6.00 g. Take the second hand to be a slender rod rotating with constant angular velocity about one end.