Presentation on theme: "Chapter 11: Rolling Motion, Torque and Angular Momentum"— Presentation transcript:
1 Chapter 11: Rolling Motion, Torque and Angular Momentum Rolling motion (axis of rotation is moving)Kinetic Energy of rolling motionRolling motion on an inclineTorqueAngular momentumAngular momentum is conserved
2 Rolling motion of a particle on a wheel (Superposition of rolling and linear motion)
3 Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS 11-2 Rolling motionSmooth rolling:There is no slippingLinear speed of center of mass:4/16/2017Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS
4 Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS 11-2 Rolling motionThe angular velocity of any point on the wheel is the same.The linear speed of any point on the object changes as shown in the diagram!!For one instant (bottom), point P has no linear speed.For one instant (top), point P’ has a linear speed of 2·vCOM4/16/2017Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS
5 Superposition principle: 11-3 Kinetic Energy of RollingSuperposition principle:Rolling motion = Pure translation Pure rotationKinetic energyof rolling motion:4/16/2017Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS
6 Sample Problem 11-1Approximate each wheel on the car Thrust SSC as a disk of uniform thickness and mass M = 170 kg, and assume smooth rolling. When the car’s speed was 1233 km/h, what was the kinetic energy of each wheel?
7 11-4 Forces of Rolling Friction and Rolling If the wheel rolls without sliding (smooth rolling) and is accelerating, then from ,(smooth rolling)where is the linear acceleration of the center of mass and α is the angular acceleration.The force to provide for macom is the static frictional force (assuming the wheel rolls without sliding).Therefore, for a wheel to roll without sliding, the maximum static frictional force, between the wheel and the ground must be greater than macom.and point to the right if the wheel if the wheel rotates faster, for example, at the start of a bicycle race.Do not assume that is equal to the maximum value of
8 Rolling Down a RampxyThe positive direction here is chosen to be down the plane.Do not assume that is at its maximum value of The value of self-adjusts so the body rolls without sliding.α is counterclockwise and positive.where acom points down plane +veTherefore from (2) and substituting this in (1) Note that a positive acom points down plane.
9 DemoA ring and and disk of equal mass and diameter are rolling down a frictionless incline.Both start at the same position; which one will be faster at the end of the incline?4/16/2017
10 Sample Problem 11-2A uniform ball, of mass M = 6.00 kg and radius R, rolls smoothly from rest down a ramp at angle q = 30.0°(a) The ball descends a vertical height h = 1.20 m to reach the bottom of the ramp. What is its speed at the bottom?A positive vcom points down plane.
11 (b) What are the magnitude and direction of the friction force on the ball as it rolls down the ramp?A positive acom points down plane.A positive fs means that the direction we selected for fs (up) is correct! fsR is a clockwise torque (+ve)
12 11-5 Yo-Yo The yo-yo can be considered as a rolling down a ramp: Instead of rolling down a ramp at angle q with the horizontal, the yo-yo rolls down a string at angle q = 90° with the horizontal.Instead of rolling on its outer surface at radius R, the yo-yo rolls on an axle of radius Ro.Instead of being slowed by frictional force fs, the yo-yo is slowed by the net force T on it from the string.So we would again get the same expression for the acceleration as for rolling with q = 90°.
13 11-6 Torque and the vector product 4/16/2017Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS
14 Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS Sample Problem 11.3In Fig a, three forces, each of magnitude 2.0 N, act on a particle. The particle is in the xz plane at point A given by position vector , where r = 3.0 m and q = 30°. Force is parallel to the x axis, force is parallel to the z axis, and force is parallel to the y axisWhat is the torque, with respect to the origin O, due to each force?To find the directions of the torques, we use the right hand rule and rotate into through the smaller of the two angles between their directions.4/16/2017Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS
15 Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS Sample Problem 11.34/16/2017Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS
16 11-7 Angular momentum of a particle The SI unit of angular momentum l isAngular momentum is a “vector”, the direction is determined by the right hand rule.The magnitude of angular momentum iswhere φ is the angle between and when these two vectors are arranged tail to tail.4/16/2017Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS
17 Sample Problem 11-4Figure shows an overhead view of two particles moving at constant momentum along horizontal paths. Particle 1, with momentum magnitude p1 = 5.0 kg·m/s, has position vector and will pass 2.0 m from point O. Particle 2, with momentum magnitude p2 = 2.0 kg·m/s, has position vector and will pass 4.0 m from point O.What is the net angular momentum about point O of the two-particle system?The RHR indicates that l1 is positive.RHR = right hand ruleThe RHR indicates that l2 is negative.
18 11-8 Newton’s Second Law in Angular Form (single particle)(single particle)Note that the torque and angular momentum must be defined with respect to the same origin.Proof:Because , this leads toTherefore,
19 11-9 Angular momentum of a system of Particles (L = total angular momentum)is the net torque on the ith particle is the sum of all the torque (internal and external) on the system. However the internal torques sums to zero. Let represent the net external torque on the system.( system of particles )The net external torque acting on a system of particles is equal to the time rate of change of the system's total angular momentum .
20 11-10 Angular momentum of a rigid object rotating about a fixed axis We’ll consider an object that is rotating about the z-axis.The angular momentum of the object is given by:Note that in this case L and w are along the z axis.Also note the analog formula for linear momentum p = m·v
21 Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS 11-11 Conservation of angular momentumThe total angular momentum of a system is constant in both magnitude and direction if the resultant external torque acting on the system is zero.If the system undergoes an internal “rearrangement”, thenIf the object is rotating about a fixed axis (say z-axis), then:4/16/2017Lecture notes by Dr. M. S. Kariapper KFUPM - PHYSICS
22 DemoA students stands still on a rotating platform and holds two texts on outstretched arms. He brings the arms closer. What happens? DiscussA students stands still on a rotatable platform and holds a spinning wheel. The bicycle wheel is spinning in the clockwise direction when viewed from above.He flips the wheel over.What happens?
23 Translational Rotational Force Torque Linear momentum Angular momentum TABLE 11-1 More Corresponding Variables and Relations for Translational and Rotational MotionaTranslational Rotational Force Torque Linear momentum Angular momentum Linear momentumb Angular momentumb Linear momentumb Angular momentumc Newton's second lawb Newton's second lawb Conservation lawd Conservation lawd a See also Table b For systems of particles, including rigid bodies. c For a rigid body about a fixed axis, with L being the component along that axis. d For a closed, isolated system.
24 P22Force F = 2i-3k acts on a particle with position vector r = 0.5j-2.0k relative to the origin. In unit vector notation, what is the resulting torque on the pebble about (a) the origin and (b) the point (2.0, 0, -3.0)?P72A uniform solid ball rolls smoothly along a floor and up a ramp inclined at 15.0°. It is momentarily stops when it has rolled 1.50 m along the ramp. What was its initial speed?
25 P85In fig , a constant horizontal force Fapp of magnitude 12 N is applied to a uniform solid cylinder by a fishing line wrapped around the cylinder. The mass of the cylinder is 10 kg, its radius is 0.10 m, and the cylinder rolls smoothly on the horizontal surface. (a) What is the magnitude of the acceleration of the com of the cylinder? (b) What is the magnitude of the angular acceleration of the cylinder about the com? (c) In unit vector notation, what is the frictional force acting on the cylinder?P90A uniform rod rotates in a horizontal plane about a vertical axis through one end. The rod is 6.00 m long, weighs 10.0 N, and rotates at 240 rev/min. Calculate (a) its rotational inertia about the axis of rotation and (b) the magnitude of its angular momentum about the axis.
26 P48A cockroach of mass 0.17 kg runs counterclockwise around the rim of a lazy Susan (a circular disk mounted on a veritcal axle) that has radius 15 cm, rotational inertia 5.0 x 10-3 kgm2, and frictionless bearings. The cockroach’s speed (relative to the ground) is 2.0 m/s, and the lazy Susan turns clockwise with angular velocity wo = 2.8 rad/s. The cockroach finds a bread crumb on the rim and, of course, stops. (a) What is the angular speed of the lazy Susan after the cockroach stops?