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**AP Electricity Quiz Review**

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In the circuit shown above, the battery supplies a constant voltage V when the switch S is closed. The value of the capacitance is C, and the value of the resistances are R1 and R2. Immediately after the switch is closed, the current supplied by the battery is (A) V/(R1 + R2) (B) V/R1 (C) V/R2 (D) V(R1 + R2)/R1R2 (E) zero

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B. When the switch is closed, the circuit behaves as if the capacitor were just a wire, shorting out the resistor on the right.

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In the circuit shown above, the battery supplies a constant voltage V when the switch S is closed. The value of the capacitance is C, and the value of the resistances are R1 and R2. A long time after the switch has been closed, the current supplied by the battery is (A) V/(R1 + R2) (B) V/R1 (C) V/R2 (D) V(R1 + R2)/R1R2 (E) zero

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A. When the capacitor is fully charged, the branch with the capacitor is “closed” to current, effectively removing it from the circuit for current analysis.

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