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RC Circuits

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R i(t) V + C -

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VR= i R R i V + C -

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VR= i R R i V + C - Vc= q/C

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VR= i R R i V + C - Vc= q/C V- iR-q/C = 0 V-dq/dt R –q/C =0

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RC Circuits, Charging a Capacitor:

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**27.9: RC Circuits, Time Constant:**

The product RC is called the capacitive time constant of the circuit and is represented with the symbol t: At time t= t =( RC), the charge on the initially uncharged capacitor increases from zero to: During the first time constant t the charge has increased from zero to 63% of its final value CE.

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**R V C Initially capacitor is uncharged q t a) q t b) q t c) q t d)**

+ - When the switch is closed what, which graph depicts the charge on the capacitor over time ? Initially capacitor is uncharged q t a) q t b) q t c) q t d)

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RC Circuits, Discharging a Capacitor:

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A simple circuit consists of a resistor R, a capacitor C charged to a potential Vo, and a switch that is initially open but then thrown closed. Immediately after the switch is thrown closed, the current in the circuit is Vo/R. B) zero. C) need more information

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**R V C Initially capacitor is uncharged q t a) q t b) q t c) q t d)**

+ - When the switch is closed what, which graph depicts the current through the resistor over time ? Initially capacitor is uncharged q t a) q t b) q t c) q t d)

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**What is the initial I through the battery when the switch is closed?**

V/R V/2R q/RC R V C + -

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**R V C What is current through the battery after a long time? V/R V/2R**

+ - What is current through the battery after a long time? V/R V/2R q/RC

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**R V C What is the charge on the capacitor after a long time? CV CV/4**

+ - What is the charge on the capacitor after a long time? CV CV/4 2CV CV/2

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**R i2 i1 V C i1=0, i2= -V/2R i1=0, i2= V/2R i1=V/2R, i2= V/2R**

With capacitor charged, we open the circuit. What happens immediately after? i1=0, i2= -V/2R i1=0, i2= V/2R i1=V/2R, i2= V/2R i1=V/R , i2=0 R V C + - i2 i1

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What effect, if any, does increasing the battery emf in an RC circuit have on the time to charge the capacitor? a) The charging time will decrease because the rate of charge flowing to the plates will increase. b) The charging time will decrease because the rate of charge flowing to the plates will decrease. c) The charging time will not change because the charging time does not depend on the battery emf. d) The charging time will increase because the emf is increased. e) The charging time will decrease because potential difference across the plates will be larger.

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In physics lab, Rebecca measured the voltage across an unknown capacitor in an RC circuit, every ten seconds after a switch in the circuit that allows the capacitor to discharge is closed. The capacitor was initially fully charged. Using the graph, estimate the time constant. a) 7.5 s b) 15 s c) 30 s d) 45 s e) 60 s

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Circuits Chapter 27 Copyright © 2014 John Wiley & Sons, Inc. All rights reserved.

Circuits Chapter 27 Copyright © 2014 John Wiley & Sons, Inc. All rights reserved.

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