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Basic Electronic Components

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In this section, we will show you how these principles apply to actual electronic components and which components are used to provide current, voltage, capacitance, and resistance.

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The Power Source In making an electric circuit the first thing you will need is electricity. If not, then it’s not electric, no electrons will flow, etc. So you have to get, create, or innovate a power or an energy source. A power source could be a Battery Voltage regulated source Straight from the plug in your house The first two are direct current or DC sources while the last is an alternating current or AC source.

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DC Power Source - Currents and voltage is supplied as a continuous or direct signal. - Can be represented as a straight horizontal line in either a voltage or a current vs. time graph. -DC voltages usually range from 1.5 V to 12 V for household devices to as high as 24 to 28 V for industrial machines. -Since voltage is a potential difference, you must need to indicate the polarity, where positive and the negative sides are.

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voltage 12 Volts time A 12-Volt DC Signal

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AC Power Source -Represented mathematically as a sine wave.

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The sine wave (hence, the current) alternates from positive to negative hence the name alternating current. In the Philippines, the frequency of the waveform is 60 cycles per second or 60Hz in some countries, it is 50Hz. AC Voltages (represented by the amplitude of the sine wave) usually are from 100 to 250V, divided into two ranges, 100 to 120V (average 110V) used in many western countries, and V (mostly220V) here in the Philippines. In the Philippines, our AC Voltage rating is 220V, 60Hz.

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What source to use? You must know whether a device you will be using needs a DC Source or an AC Source. Here are some tips: 1.Look at the labels of the device, you will see if it runs on AC, DC or both AC and DC. 2.Another concern when selecting supplies is the maximum current that the voltage source can supply.

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Power Source Circuits Figures below show the symbol for the most power (voltage) sources and sample values of voltages. Symbols for Some Power (Voltage) Sources

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A battery is indicated by alternating short and long parallel lines. Each pair of lines (ideally) indicates one cell of the battery: the shorter line indicates the negative end of the battery, and the longer the line indicates the positive end of the battery. DC Voltage source just indicate the polarity while he Ac voltage source is described by the sine wave. When solving mathematically, we assume that these voltages can supply an unlimited amount of current, unless indicated otherwise.

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The Load and Equivalent Components Loads –components that consume the power source which is the component that supplies energy. Power source must be at least of enough value to overcome the load.

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One example of a load is a light bulb. If you take a look at a 40-watt bulb, you would see something like this: 220V, 40W. What does 220V, 40 W on a light bulb mean? 220V means that this light (or load) needs a voltage source with 220-volts. If it’s too low, it won’t work. If it’s too high, it will destroy the bulb. 40W is the power consumption of the bulb. So in one hour, this bulb will consume about 0.4 kilowatt-hour (kwh).

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Fixed Resistors (Resistors) -Simply resistors -Are components that have a definite resistance. -Resistance is measured in ohms. -Resistor could have a resistance as low as 10 ohms (Ω) to as high as 10,000,000 ohms (Ω) -Also has a power rating -Come in 1/4 th watt, ½ watt and even 1-watt ratings This means that the power dissipation is equal to that amount

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Why do we need a resistors, since this will just impede the flow of current across a material? Here are the reasons. 1.Resistors are current limiters. According to Ohms Law, i = V/R, so give n a fixed voltage source, the current will be dependent on the resistance. Some component have specified current ranges for it to work.

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+ - 5 Volts Components High current, Low resistance R min = V / i max = 5 V / 0.05 A = 100 Ω Low current, High resistance R max = V/ i min = 5 V / 0.01 A = 500 Ω If a certain device A has a current range from 10mA (0.01 A) to 50mA (0.05 A), then you must have a resistor present that would produce a current that is equal to or less than 50mA, which from figure above must be from 100 to 500 ohms.

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If you use two rechargeable (NiCd) batteries (1.2 Volts each) to power a small lighting device which operates from 30mA to 80mA of current, what range of resistor values should you place in your circuit? Given Voltage sources V 2.4 Volts (2 NiCd batteries) Minimum current i min 30mA Maximum current i max 50mA Find: Range of resistor values (r min, r max ) Solution: Use Ohms Law to find the minimum and maximum values.

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High current, Low resistance Rmin = V/i max = 2.4 V / 0.08 A = 30 Ω Low current, High resitance Rmax = V/i min = 5 V / 0.03 A = 167 Ω So the range of resistors to use is from 30 ohms to 167 ohms

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2. Resistors are current distributors. “The greatest amount of current flows through the path with the least amount of resistance.” We have two lamps sharing one voltage source, the total current determined by the resistor R. Current is distributed evenly between L 1 and L 2

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If two lamps are identical, then the current i due to the resistor R will be distributed equally into the two lamps. So, V / R = i = i 1 + i 2 i 1 = 0.5i and i 2 = 5i Both lamps will have the same brightness because they have the same voltage and current.

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How do we do is we want the first lamp to be brighter than the second one? We can place resistors together with the lamps, which will determine how much current will pass through the lamps. Resistors control the current passing through L 1 and L 2

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The total current i is limited by the resistor R, given by i = V/ R The current i will then be distributed across the lamps i 1 and i 2 where i = i 1 + i 2 We can apply Ohms Law for both lamps i 1 = V / 0.5R 2 and i 2 = V / R 2 Equating both equations through the voltage V and solving for i 1 0.5i 1 R 2 = i 2 R 2 therefore i 1 = 2i 2 So, i = i 1 + i 2 = 2i 2 + i 2 where i 2 = (1/3) i i = i 1 + i 2 = i i 1 where i 1 = (2/3) i

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The current distribution will be as follows: Lamp 1: 2/3 of the current Lamp 2: 1/3 of the current If the resistor beside lamp 1 is half that of the resistor beside lamp 2.

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The colors correspond to the values in the table below ColorCodeMultiplier Black0 Brown1 Red2 Orange3 Yellow4 Green5 Blue6 Violet7 Gray8 White9 Digits and Multiplier

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Tolerance Codes ColorTolerance No Band20% Silver Band10% Gold Band5%

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To memorize the sequence, the middle part is almost the same as the colors of the rainbow except for Indigo. Black Boy ROY G. BV Goes West, To No Silver and Gold The first word Black is used just to indicate the first color, to distinguish it from brown, which is the second color. The word To indicates the start of the tolerance. No means no Band.

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Variable Resistors -also common components as you can change their resistance from zero to a given value, called its rating. -for example a 100k Ω variable resistor means you can change the resistance from 0 to 100k Ω. -the value of a variable resistor is given as it’s highest resistance value.

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To change the resistance, some have a dial or a knob where a turn corresponds to a change in resistance. These are called Potentiometers.

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In some devices, you need to turn a slot in the component to change the resistance. These are called Trimmer resistors.

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Volume controls are variable resistors. When you change the volume you are changing the resistance, which changes the current. Making the resistance higher will let less current flow so the volume goes down. Making the resistance lower will let more current flow so the volume goes up.

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From the previous problem, it is said that if a certain device A has a current range from 10mA (0.01 A) to 50mA (0.05 A) and you have a 5 Volt source, then you must have a resistor value which can be anywhere from 100 to 500 ohms. Let us say that the device mentioned is a light source. If we put 500-ohm resistor, then it will light dimly. If we place a 100-ohm resistor, it will shine the brightest. We could improve that design using a variable resistor. We can use the resistor to make the light brighter or dimmer.

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1.Determine the lower limit of the resistance needed. This will be the value of our fixed resistor. In our circuit, we need to have at least 100-ohms or the lamp will be damaged. So place a 100-ohm resistor in the circuit. 2. The value of the potentiometer R pot must be at least the differences between the resistance values R pot =500 ohms – 100 ohms = 400 ohms

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Adding a potentiometer, we can make the light source brighter or dimmer by moving the knob.

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Resistors in Series A battery and three resistors connected together end to end, forming a single line as shown Resistors in Series

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These would result in a current flow of only one path in the loop, across each of the resistors, making them in series with each other. Since the current flows only one path, then the amount of current flowing across each resistor is the same. For example if three resistors R 1, R 2, and R 3 are in the series, then the voltage across each resistor will be V 1 = i x R 1 V 2 = i x R 2 V 3 = i x R 3 The total voyage across the three resistors will just be the same as the voltage of the battery, thus.. V = V 1 + V 2 + V 3 = i x R 1 + i x R 2 + i x R 3 = i (R 1 + R 2 + R 3 ) This means the total resistance will just be the sum of the individual resistances of the resistors, so resistors in series have an additive effect.

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we can also substitute a single resistor having a resistance R eq, where R eq = R 1 + R 2 + R 3 For any number of resistors n it will just be R eq = R 1 + R 2 + ……….. + R n Thus V = i * R eq

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R eq is termed as the equivalent resistance of the three resistors in series. So when combining three resistors in series, the result is a resistor with a bigger resistance. Equivalent circuit of the three resistors

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Series connections are used in many different ways. The most familiar example is that type of Christmas tree light set in which all bulbs go off if one burns out.

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Resistors in Parallel Let us now consider a battery and three resistors connected together at the ends where one end of each is connected at point A, with the other ends connected at point B. Resistors in Parallel

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The figure can be drawn in another way Another way of representing resistors in parallel

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In this set-up, we consider the component to be parallel to each other. Since all are connected at the ends of the battery, then they all have the same voltage, the same as that of the battery. But then, the current that flows out of the battery will be divided among the three resistors in the circuit. So the current flow across each resistor will be given by The tool current across the three resistors will just be the same as the current flowing out of the battery.

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This equation means that the inverse of the total resistance will just be the sum of the inverse of the individual resistances of the resistors.

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From Ohms Law that i = V/R. if we compare this with the equation we just derived, we can get the following relationship. Cancelling out V,

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For n resistors it will just be From this equation, a single resistor R can be substituted in place of R 1, R 2 and R 3. thus R in this equation is the equivalent resistance of R eq of resistors in parallel. Because of the inverse relationship, the equivalent resistance R eq is smaller that each of the resistance in the circuit.

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Switches -device that create a short circuit or an open circuit depending on the position of the switch. For a light, ON means short circuit. When the switch is OFF, that means there is an open circuit. When the switch is ON it looks and acts like a wire. When the switch is OFF there is no connection.

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The Minimum Circuit with a Switch What is the current when the switch is off or open? When the switch is on? Answer We won’t be needing the mathematical computations in this example.

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Switch Off if the switch is off, then the circuit is “open”. Actually it is not a circuit anymore because the circuit is a closed loop. Current flows in a circuit. There is no current flowing if there is no circuit, so i = 0 if the switch is of. If the switch is on, the current will flow.

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