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1 PROBLEM 1 PROBLEM 3 PROBLEM 2 PROBLEM 4 PROBLEM 5 PROBLEM 8PROBLEM 7 PROBLEM 6 STANDARD 13 SUPPLEMENT AND COMPLEMENT: NUMERIC PROBLEM 10PROBLEM 9 PRESENTATION.

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Presentation on theme: "1 PROBLEM 1 PROBLEM 3 PROBLEM 2 PROBLEM 4 PROBLEM 5 PROBLEM 8PROBLEM 7 PROBLEM 6 STANDARD 13 SUPPLEMENT AND COMPLEMENT: NUMERIC PROBLEM 10PROBLEM 9 PRESENTATION."— Presentation transcript:

1 1 PROBLEM 1 PROBLEM 3 PROBLEM 2 PROBLEM 4 PROBLEM 5 PROBLEM 8PROBLEM 7 PROBLEM 6 STANDARD 13 SUPPLEMENT AND COMPLEMENT: NUMERIC PROBLEM 10PROBLEM 9 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved SUPPLEMENT: GENERAL COMPLEMENT: GENERAL SUPPLEMENT AND COMPLEMENT: GENERAL WORD PROBLEMS: SUPPLEMENTARY AND COMPLEMENTARY ANGLES END SHOW

2 2 STANDARD 7: Students prove and use theorems involving the properties of parallel lines cut by a transversal, the properties of quadrilaterals, and properties of circles. ESTÁNDAR 7: Los estudiantes prueban y usan teoremas involucrando las propiedades de líneas paralelas cortadas por una transversal, las propiedades de cuadriláteros, y las propiedades de círculos. PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

3 3 STANDARD 13 Find the measure of the COMPLEMENT and SUPPLEMENT of the angle below: 90° – 65° = 25° 65° 115° Supplement: 180° – 65° = 115° Calculating the complement: Calculating the supplement: 25° Complement 65° PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

4 4 Find the measure of the COMPLEMENT and SUPPLEMENT of the angle below: 90° – 55° = 35° 55° 125° Supplement: 180° – 55° = 125° Calculating the complement: Calculating the supplement: STANDARD 13 35° Complement 55° PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

5 5 X° Find the measure of the SUPPLEMENT of the angle below: 180° – X° (180 – X)° Supplement: STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

6 6 Find the measure of the COMPLEMENT of the angle below: 90 – X° Complement (90-X)° X° STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

7 7 Find COMPLEMENT AND SUPPLEMENT of any given angle: 90° – X° (180 – X)° Supplement: 180° – X° Calculating the complement: Calculating the supplement: (90 – X)° Complement X° Let’s call our angle X: X° STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

8 8 Xis the angle 180 – X is the supplement 180 – X = X – 20 The supplement of an angle is twenty less than the angle, find this angle and the supplement. + X 180 = 2X – = 2X 2 X = 100 Then the supplement: 180 – X = 180 – 100 = 80 The angle is 100° and the supplement is 80°. X 180 –X STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

9 9 Xis the angle 90 – X is the complement 90 – X = 2X The complement of an angle is two times the angle, find this angle and the complement. + X 3 X = 30 Then the complement: 90 – X = 90 – 30 = 60 The angle is 30° and the complement is 60°. 90 = 3X X 90 - X STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

10 10 Xis the angle 90 – X is the complement 90 – X = X + 10 The complement of an angle is 10 more than the angle, find this angle and the complement. +X 90 = 2X = 2X 2 X =40 Then the complement: 90 – X = 90 – 40 = 50 The angle is 40° and the complement is 50°. X 90 - X STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

11 11 Xis the angle 180 – X is the supplement 180 – X = The supplement of an angle is a third of the angle, find this angle and the supplement. 540 = 4X 4 X = 135 Then the supplement: 180 – X = 180 – 135 = 45 The angle is 135° and the supplement is 45°. X 180 –X X 1 3 = X – 3X = X +3X STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

12 12 Xis the angle 180 – X is the supplement 180 – X = The supplement of an angle is a fourth of the angle, find this angle and the supplement. 720 = 5X 5 X = 144 Then the supplement: 180 – X = 180 – 144 = 36 The angle is 144° and the supplement is 36°. X 180 –X X 1 4 = X – 4X = X +4X STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

13 13 Xis the angle 90 – X is the complement 90 – X = 3X – 10 The complement of an angle is 10 less than three times the angle, find this angle and the complement. +X 90 = 4X – = 4X 4 X = 25 Then the complement: 90 – X = 90 – 25 = 65 The angle is 25° and the complement is 65°. X 90 - X STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

14 14 Xis the angle 180 – X is the supplement 180 – X = 3X + 40 The supplement of an angle is forty more than the triple of the angle, find this angle and the supplement. + X 180 = 4X = 4X 4 X = 35 Then the supplement: 180 – X = 180 – 35 = 145 The angle is 35° and the supplement is 145°. X 180 –X STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

15 15 Xis the angle 90 – X is the complement 90 – X = 2X – 30 The complement of an angle is thirty less than twice the angle, find this angle and the complement. +X 90 = 3X – = 3X 3 X = 40 Then the complement: 90 – X = 90 – 40 = 50 The angle is 40° and the complement is 50°. X 90 - X STANDARD 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

16 16 Xis the angle 180 – X is the supplement 5(180 – X) = (90 – X) Five times the supplement of an angle is 630 more than its complement. Find the angle, the supplement and the complement. +5X 900 = 4X = 4X 4 X = 45 Then the supplement: 180 – X = 180 – 45 = 135 The angle is 45°, the supplement is 135° and the complement is 45°. 900 – 5X = 720 – X Then the complement: 90 – X = 90 – 45 = 45 STANDARD – X is the complement X 180 –X X 90 - X PRESENTATION CREATED BY SIMON PEREZ. All rights reserved

17 17 (180 – X) + 20 = 3(90 – X) Twenty more than the supplement of an angle is three times its complement. Find the angle, the supplement and the complement. +X 200 = -2X = -2X -2 X = 35 Then the supplement: 180 – X = 180 – 35 = 145 The angle is 35°, the supplement is 145° and the complement is 55°. 200 –X = 270 – 3X Then the complement: 90 – X = 90 – 35 = 55 STANDARD 13 Xis the angle 180 – X is the supplement 90 – X is the complement X 180 –X X 90 - X PRESENTATION CREATED BY SIMON PEREZ. All rights reserved


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