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Copyright © 2013, 2009, 2005 Pearson Education, Inc. Section 6.6 Modeling with Proportions and Variation.

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Presentation on theme: "Copyright © 2013, 2009, 2005 Pearson Education, Inc. Section 6.6 Modeling with Proportions and Variation."— Presentation transcript:

1 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Section 6.6 Modeling with Proportions and Variation

2 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Objectives Proportions Direct Variation Inverse Variation Joint Variation

3 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Proportions A proportion is a statement (equation) that two ratios (fractions) are equal. The following property is a convenient way to solve proportions: is equivalent to provided b 0 and d 0.

4 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Example On an elliptical machine, Francis can burn 370 calories in 25 minutes. If he increases his work time to 30 minutes, how many calories will he burn? Solution Let x be the equivalent amount of calories. Thus, in 30 minutes, Francis will burn 444 calories.

5 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Example A 6-foot tall person casts a shadow that is 8-foot long. If a nearby tree casts a 32-foot long shadow, estimate the height of the tree. Solution The triangles are similar because the measures of its corresponding angles are equal. Therefore corresponding sides are proportional. 6 fth 8 ft 32 ft The tree is 24 feet tall.

6 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Example A forest ranger catches 616 birds, tags them, and releases them. Two months later, 244 birds are captured and 51 were found with tags. Estimate how many birds are in the forest to the nearest hundred. Solution To the nearest hundred, there are approximately 2900 birds in the forest. Tagged in sample Total # in sample Total # tagged Total # of birds in forest

7 Copyright © 2013, 2009, 2005 Pearson Education, Inc.

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9 Example Let y be directly proportional to x, or vary directly with x. Suppose y = 9 when x = 6. Find y when x = 13. Solution Step 1 The general equation is y = kx. Step 2 Substitute 9 for y and 6 for x in y = kx. Solve for k. Step 3 Replace k with 9/6 in the equation y = 9x/6. Step 4 To find y, let x = 13.

10 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Example The table lists the amount of pay for various hours worked. a. Find the constant of proportionality. b. Predict the pay for 19 hours of work. HoursPay 6$138 11$253 15$345 23$529 31$713

11 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Example (cont) The slope of the line equals the proportionality, k. If we use the first and last data points (6, 138) and (31, 713), the slope is The amount of pay per hour is $23. The graph of the line y = 23x, models the given graph. To find the pay for 19 hours, substitute 19 for x. y = 23x, y = 23(19) y = hours of work would pay $437.00

12 Copyright © 2013, 2009, 2005 Pearson Education, Inc.

13 Example Let y be inversely proportional to x, or vary inversely with x. Suppose y = 6 when x = 4. Find y when x = 8. Solution Step 1 The general equation is y = k/x. Step 2 Substitute 6 for y and 4 for x in Solve for k. Step 3 Replace k with 24 in the equation y = k/x. Step 4 To find y, let x = 8.

14 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Example Determine whether the data in each table represent direct variation, inverse variation, or neither. For direct and inverse variation, find the equation. a. b. c. x37912 y x y12654 x y Neither the product xy nor the ratio y/x are constant in the data in the table. Therefore there is neither direct variation nor indirect variation in this table. As x increases, y decreases. Because xy = 60 for each data point, the equation y = 60/x models the data. This represents an inverse variation. The equation y = 6x models the data. The data represents direct variation.

15 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Let x, y, and z denote three quantities. Then z varies jointly with x and y if there is a nonzero number k such that JOINT VARIATION

16 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Example The strength S of a rectangular beam varies jointly as its width w and the square of its thickness t. If a beam 5 inches wide and 2 inches thick supports 280 pounds, how much can a similar beam 4 inches wide and 3 inches thick support? Solution The strength of the beam is modeled by S = kwt 2.

17 Copyright © 2013, 2009, 2005 Pearson Education, Inc. Example (cont) Thus S = 14wt 2 models the strength of this type of beam. When w = 4 and t = 3, the beam can support S = = 504 pounds


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