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**Find the exact trig values for an angle of **

This angle has a terminal side in the 2nd quadrant (because 5/4 = 1.2) y x

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**Finding Trig Values from an x-y coordinate**

Find the 6 trig functions for an angle which has terminal side passing through (-5, -3) y x

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**From the chart we get that 60 degrees has a**

Find the for all angles that are between 0 and 360 degrees (also in include the radian measurements y From the chart we get that 60 degrees has a x sin is negative in the 3rd and 4th quadrants

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**Law of Cosines – Solve the Triangle**

15 23 C 34 B

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**Law of Cosines – Solve the Triangle**

15 23 C 34 B

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**Law of Cosines – Solve the Triangle**

15 23 C 34 B=21º

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**Law of Cosines – Solve the Triangle**

15 23 C=33º 34 B=21º

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**Law of Cosines – Solving a Triangle**

Find missing side of the triangle, and then use the law of sines to find the missing angles 14 75º 43 A 41.63 B

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**Law of Cosines – Solving a Triangle**

Find missing side of the triangle, and then use the law of sines to find the missing angles 14 75º 43 A We can now use law of sines to find one of the angles that is missing 41.63 B

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**Law of Cosines – Solving a Triangle**

14 75º 43 A 41.63 B

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**Law of Cosines – Solving a Triangle**

Now use this angle and the 75 that you were given in the beginning to find the 3rd angle 14 75º 43 A 41.63 B

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**724 #81 (find all missing sides and angles – DO NOT FIND AREA) **

727 #1-3 (sketch the angles and reference angles – then find the answers) 727 #4-6 (find all angles between 0 and 360 and their radian counterparts) 724 #75, 79 (find all missing angles and show ALL work along with a drawing) 724 #81 (find all missing sides and angles – DO NOT FIND AREA) 697 #9, 11, 13, 15 (make sure they have the proper signs and show ALL work) 697 #22, 23, 25, 27 (sketch and find the reference angle) 697 #36, 38, 40 (you need a sketch and to explain how you know without using the calculator)

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14. Law of Sines The Ambiguous Case (SSA). Yesterday we saw that two angles and one side determine a unique triangle. However, if two sides and one opposite.

14. Law of Sines The Ambiguous Case (SSA). Yesterday we saw that two angles and one side determine a unique triangle. However, if two sides and one opposite.

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