Presentation on theme: "Mole Review 1.) Calculate the number of moles in 60.4L of O2. 2.) How many moles are there in 63.2g of Cl2? 1 mol O2 60.4L O2 = 2.7 mol O2 22.4L O2 1mol."— Presentation transcript:
1Mole Review1.) Calculate the number of moles in 60.4L of O2. 2.) How many moles are there in 63.2g of Cl2?1 mol O260.4L O2= 2.7 mol O222.4L O21mol Cl263.2g Cl2= 0.903mol Cl270g Cl2
3Scheduled to make 640 tricycles. How many wheels should they order? Proportional RelationshipsTiny Tyke Tricycle CompanyF + S + 3W + H + 2P → FSW3HP2Scheduled to make 640 tricycles. How many wheels should they order?
4Proportional Relationships 2 1/4 c. flour1 tsp. baking soda1 tsp. salt1 c. butter3/4 c. sugar3/4 c. brown sugar1 tsp vanilla extract2 eggs2 c. chocolate chipsMakes 5 dozen cookies.I have 5 eggs. How many cookies can I make?Ratio of eggs to cookies5 eggs5 doz.2 eggs= 12.5 dozen cookies
5Proportional Relationships Stoichiometrymass relationships between substances in a chemical reactionfor example: you can determine the amount of a compound required to make another compoundbased on the mole ratioMole Ratioindicated by coefficients in a balanced equation2 Mg + O2 2 MgO2 Moles of magnesium react with 1 mole of oxygen to form 2 moles of magnesium oxide.
62 Mg + O2 2 MgOWhat would be the mole ratio of magnesium to magnesium oxide? 2 : 2 Conversion factor = 2 mol Mg 2 mol MgO What would be the mole ratio of oxygen to magnesium? 1 : 2 Conversion factor = 1 mol O2 (Mole Ratio) 2 mol Mg
7Practice5 F2 + 2NH3 N2F4 + 6HF1. What is the mole ratio of NH3 to F2?Write the mole ratio as a conversion factor.2. What is the mole ratio of HF to N2F4?2:52mol NH35mol F26:16mol HF1mol N2F4
8Stoichiometry Steps 1. Write a balanced equation Identify known & unknown.3. Convert known to mole (if necessary), line up conversion factors.4. Use Mole Ratio.5. Convert moles to unknown unit (if necessary).6. Calculate and write units.Mole ratio- get from equationUnits of unknownknownMol of unknownMol of knownMol of unknown
9Mole - Mole Stoichiometry Formula:known mol mol unknownmol knownWrite the known and unknown.Use the balanced equation to find the mole ratio.Calculate.
10Mole-Mole Examples __S + __O2 → __SO3 Write the equation. #1__S + __O2 → __SO3Write the equation.Balance the equation.How many moles of SO3 are produced when there are 4.5 moles of S?Known =Unknown =
11Mole-Mole Examples 2C3H7OH + 9O2 → 6CO2 + 8H2O Write the equation. #2Isopropyl alcohol (C3H7OH) burns in the air to this equation:2C3H7OH + 9O2 → 6CO2 + 8H2OWrite the equation.Calculate the moles of oxygen needed to react with 3.40 moles of isopropyl alcohol.
12Mole-Mole Examples 2C3H7OH + 9O2 → 6CO2 + 8H2O #32C3H7OH + 9O2 → 6CO2 + 8H2OFind the moles of water when 6.20 mol O2 reacts with C3H7OH.
13Mass-Mass Stoichiometry Mass of reactants equals the mass of products, Law of Conservation of MassONLY mass and atoms are conserved in every chemical reaction1. Write the known and unknown.2. Find the molar mass of the known and unknown substances.3. Use mole and molar mass conversion factors from Ch. 7 and mole ratios from the balanced equation to solve.Known g1 mol KnownMolar massKnownmol unknownmol knownMol ratio-get from equationMolar mass unknown1 mol unknown
14Mass-Mass Stoichiometry #1The reaction of fluorine with ammonia produces dinitrogen tetrafluoride and hydrogen fluoride.5F2 + 2 NH3 → N2F4 + 6HFHow many grams of NH3 are required to produce 7.38g HF?
15Mass-Mass Stoichiometry #25F2 + 2 NH3 → N2F4 + 6HFHow many grams of N2F4 can be produced from 265g F2?
16Mass-Mass Stoichiometry #32C2H2 + 5O2 → 4CO2 + 2H2OHow many grams of oxygen are required to burn 52.0g C2H2?
17Volume-Volume Stoichiometry Formula to use:Known (L) 1 mol known mol unknown L unknownL known mol known mol unknownWrite the known and unknown.Use mole and volume conversion factors from Ch. 7 and the mole ratios from the balanced equation to solve.
18Volume-Volume Example #4C3H8 + 5O2 → 3CO2 + 4H2OIf 25 liters of oxygen are consumed in the above reaction, how many liters of carbon dioxide are produced?
19Formulas to Use Mole - Mole Known mol of unknown mol of known Mol Ratio – from equationMass - Massmol of unknownKnown g1 mol knownmolar mass unknownmol of known1 mol unknownmolar mass knownOROROther6.02 × 1023 particlesmol of unknownKnown L1 mol known22.4 L unknownORparticlesmol of known1 mol unknown22.4 L known6.02 × 1023 particles
20Stoichiometry Problems How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas?2KClO3 2KCl + 3O2Known: 9 moles O2Unknown: moles KClO39 mol O22 mol KClO33 mol O2= 6 molKClO3
21Stoichiometry Problems How many grams of KClO3 are required to produce 9.00 L of O2 at STP?2KClO3 2KCl + 3O2Known: 9.00 L O2Unknown: g KClO39.00 LO21 molO222.4 L2 molKClO33 molO2122 gKClO31 mol= gKClO3
22Stoichiometry Problems How many grams of silver will be formed from 12.0 g copper?Cu + 2AgNO3 2Ag + Cu(NO3)2Known: 12.0 g Cu Unknown: g Ag12.0g Cu1 molCu64g Cu2 molAg1 molCu108 gAg1 mol= 40.5 gAg
23Stoichiometry Problems How many grams of silver will be formed from 12.0 g copper?Cu + 2AgNO3 2Ag + Cu(NO3)2Known: 12.0 g Cu Unknown: g Ag12.0g Cu1 molCu64g Cu2 molAg1 molCu108 gAg1 mol= 40.5 gAg
24Limiting Reactants/Reagents Available Ingredients4 slices of bread1 jar of peanut butter1/2 jar of jellyLimiting Reactant/ReagentsbreadExcess Reactants/Reagentspeanut butter and jelly
25Limiting Reactants/Reagents Limiting Reactant/Reagentused up in a reactiondetermines the amount of productExcess Reactant/Reagentadded to ensure that the other reactant is completely used upcheaper & easier to recycle
26To Determine Limiting Reagents 1. Write a balanced equation.2. For each reactant, calculate the amount of product formed.3. Smaller answer indicates:limiting reactantactual amount of product
27Limiting Reagents Zn + 2HCl ZnCl2 + H2 79.1 g of zinc react with 0.90 L of HCl. Identify the limiting and excess reactants. How many liters of hydrogen are formed at STP?Zn HCl ZnCl H279.1 g0.90 L? L
28Limiting Reagents Zn + 2HCl ZnCl2 + H2 79.1 g 0.90 L ? L 79.1 g Zn 1 molZn65g Zn1 molH2Zn22.4 LH21 mol= LH2
29Limiting Reagents Zn + 2HCl ZnCl2 + H2 79.1 g 0.90 L ? L 0.90 L HCl 1 molHCl22.4L HCl1 molH22 molHCL22.4 LH21 mol= 0.45 LH2
30Limiting Reagents Zn: 27.26 L H2 HCl: 0.45 L H2 Limiting reagent: HCl Excess reagent: Zn
31Percent YieldPercent yield- the ratio of the actual yield to the theoretical yieldActual yield- the amount of product formed when a reaction is carried out in the laboratoryTheoretical yield- the calculated amount of product formed during a reaction (mathematical calculation used to make answer keys)
32Percent Yieldmeasured in labcalculated on paper32
33Percent Yield K2CO3 + 2HCl 2KCl + H2O + CO2 When 45.8 g of K2CO3 react with excess HCl, 46.3 g of KCl are formed. Calculate the theoretical and % yields of KCl.K2CO3 + 2HCl 2KCl + H2O + CO245.8 g? gactual: 46.3 g
34B. Percent Yield K2CO3 + 2HCl 2KCl + H2O + CO2 45.8 g ? g actual: 46.3 gTheoretical Yield:45.8 gK2CO31 molK2CO3138 g2 molKCl1 molK2CO374g KCl1 molKCl= 49.12g KCl
35B. Percent Yield K2CO3 + 2HCl 2KCl + H2O + CO2 45.8 g 49.12 g actual: 46.3 gTheoretical Yield = g KCl46.3 g49.12 g% Yield = 100 =94.3%