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Solving Two Step Equations Students will solve two-step equations using inverse operations. 3a + 5 = 11 -2x – 8 = 16 -3n + 16 = - 2 2y + ( - 3 ) = - 15.

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Presentation on theme: "Solving Two Step Equations Students will solve two-step equations using inverse operations. 3a + 5 = 11 -2x – 8 = 16 -3n + 16 = - 2 2y + ( - 3 ) = - 15."— Presentation transcript:

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2 Solving Two Step Equations Students will solve two-step equations using inverse operations. 3a + 5 = 11 -2x – 8 = 16 -3n + 16 = - 2 2y + ( - 3 ) = - 15

3 Review One-step Equations - 9 m = -6 check: = ? 3 = 3 m + 9 = f = -2 check: -2 – 3 = ? -5 = -5 f – 3 = -5 3 a = -6 Check: 3 (-6) = ? -18 = -18 3a = -18 (-5) x = = -2 Check:

4 Two-Step Equations It takes two steps to solve an equation that has more than one operation. Use PEMDAS backwards 1.Simplify by using the addition or subtraction property of equality. (use the inverse of addition or subtraction) 2.Simplify further by using the multiplication or division property of equality. (use the inverse of multiplication or division)

5 2-step Equation w/ Algebra Tiles = x = 1 3x + 2 = 11 + = Subtract 2 from each side of the equation. = Divide into equal groups. = x = 3

6 Example 1 2x – 15 = 5 CHECK YOUR WORK: 2 ( 10 ) – 15 = ? 20 – 15 5 = Addition Property of Equality 2x = Division Property of Equality x = 10

7 Example 2 11n + 1 = 67 CHECK YOUR WORK: 11 ( 6 ) + 1 = ? = 67 – 1 – 1 Subtraction Property of Equality 11n = Division Property of Equality n = 6

8 Example 3 -2y + 4 = 8 CHECK YOUR WORK: -2 (-2 ) + 4 = ? = 8 – 4 – 4 Subtraction Property of Equality -2y = Division Property of Equality y = -2

9 Example 4 5x – 2 = 3 CHECK YOUR WORK: 5 ( 1 ) – 2 = ? 5 – 2 3 = Addition Property of Equality 5x = Division Property of Equality x = 1

10 Example 5 x5x5 – 9 = Addition Property of Equation x5x5 = 7 ( 5 ) ( 5 ) Multiplication Property of Equation x = 35 Check your answer: 35 5 – 9 = ? 7 – 9 -2 = -2

11 T = 4 Word Problem #1 Bobby bought 3 T-shirts at the mall and a pair of pants for $16 at the clothing store. All together he spent $28 for the clothes. How much was each shirt? – 16 – 16 Subtraction Property of Equations 3T = Division Property of Equations Each T-shirt cost $4. Let T = the price of each T-shirt. 3T3T3T3T + 16 = 28

12 Word Problem #2 F = 5 Diane sold 9 decorated flowers that cost the same amount each plus a dozen roses for $28. All together she sold $73 in flowers. How much was each decorated flower? 9F = 45 – 28 – 28 Subtraction Property of Equations 9 9 Division Property of Equations The decorated flowers were $5.00 each. Let F = the price of each decorated flower. 9F + 28 = 73

13 Solve for x with variables ax + b = y – b – b Subtract b from both sides. ax = Since y and b are not like terms, we cannot combine them. y – b Divide both sides of the equation by a. a x = y – b a OR x = ya ba

14 Summary Remember, use inverse operations to solve equations. Work in reverse order of operations. STOP


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