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II. The Gas Laws Ch. 12 & 13 - Gases

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A. Boyles Law P V PV = k

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A. Boyles Law b The pressure and volume of a gas are inversely related at constant mass & temp P V PV = k

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A. Boyles Law

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GIVEN: V 1 = 100. mL P 1 = 150. kPa V 2 = ? P 2 = 200. kPa WORK: P 1 V 1 = P 2 V 2 E. Gas Law Problems b A gas occupies 100. mL at 150. kPa. Find its volume at 200. kPa. BOYLES LAW P V (150.kPa)(100.mL)=(200.kPa)V 2 V 2 = 75.0 mL

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V T B. Charles Law

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V T b The volume and absolute temperature (K) of a gas are directly related at constant mass & pressure

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B. Charles Law

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Charles Law Demo

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GIVEN: V 1 = 473 cm 3 T 1 = 36°C = 309K V 2 = ? T 2 = 94°C = 367K WORK: V 1 T 2 = V 2 T 1 E. Gas Law Problems b A gas occupies 473 cm 3 at 36°C. Find its volume at 94°C. CHARLES LAW T V (473 cm 3 )(367 K)=V 2 (309 K) V 2 = 560 cm 3

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P T C. Gay-Lussacs Law

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P T b The pressure and absolute temperature (K) of a gas are directly related at constant mass & volume

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GIVEN: P 1 = 765 torr T 1 = 23°C = 296K P 2 = 560. torr T 2 = ? WORK: P 1 T 2 = P 2 T 1 E. Gas Law Problems b A gas pressure is 765 torr at 23°C. At what temperature will the pressure be 560. torr? GAY-LUSSACS LAW P T (765 torr)T 2 = (560. torr)(296K) T 2 = 217 K = -56°C

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= kPV PTPT VTVT T D. Combined Gas Law P1V1T1P1V1T1 = P2V2T2P2V2T2 P 1 V 1 T 2 = P 2 V 2 T 1

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GIVEN: V 1 = 7.84 cm 3 P 1 = 71.8 kPa T 1 = 25°C = 298 K V2 = ?V2 = ? P 2 = kPa T 2 = 273 K WORK: P 1 V 1 T 2 = P 2 V 2 T 1 (71.8 kPa)(7.84 cm 3 )(273 K) =( kPa) V 2 (298 K) V 2 = 5.09 cm 3 E. Gas Law Problems b A gas occupies 7.84 cm 3 at 71.8 kPa & 25°C. Find its volume at STP. P T V COMBINED GAS LAW

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