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THOERY OF MECHANISMS AND MACHINES Module-10 CAMS (DESIGN) Instructed by: Dr. Anupam Saxena Associate Professor Department of Mechanical Engineering Indian.

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Presentation on theme: "THOERY OF MECHANISMS AND MACHINES Module-10 CAMS (DESIGN) Instructed by: Dr. Anupam Saxena Associate Professor Department of Mechanical Engineering Indian."— Presentation transcript:

1 THOERY OF MECHANISMS AND MACHINES Module-10 CAMS (DESIGN) Instructed by: Dr. Anupam Saxena Associate Professor Department of Mechanical Engineering Indian Institute of Technology Kanpur anupams@iitk.ac.in FB 361 Prepared by: Abhishek Attal & Abhishek Sharma Final Year Dual Degree Student Department of Mechanical Engineering Indian Institute of Technology Kanpur attalab@iitk.ac.in, abhishr@iitk.ac.in NL312, FB369

2 The follower starts to rise ‘simple harmonically’ from 0 to 40 mm in 90 degrees of cam rotation, dwells for the next 60 degrees, returns to a height of 25 mm via a parabolic profile in 90 degrees, dwells for another 60 degrees and returns finally to 0 mm ‘simple harmonically.’ Take the base circle diameter as 30mm. Find the cam profiles for (a) flat face follower, (b) roller follower with radius 5 mm and (c) roller follower with radius 5 mm and eccentricity 20 mm. Consider cam rotation counterclockwise in all cases. Y = Asin  ; y = 40 for  =  /2  A = 40 Y = 40 – B(  -5  /6)^2; B = 60/  ^2;  Y = 40 – 60(  /  -5/6)^2

3  /2  /3 1 1 5 5 8 8 12 15 18, 18

4  /2  /3 1 1 5 5 8 8 12 15 18, 18 Roller follower Pitch points

5  /2  /3 1 1 5 5 8 8 12 15 18, 18 Roller follower Pitch points Represent the centers Of the roller Profile tangent to The roller positions Look for dwell regions

6  /2  /3 1 1 5 5 8 8 12 15 18, 18 Flat face follower Pitch points Profile tangent to These lines Slopes left out? lR_max lL_max Follower length Clearance to be added

7  /2  /3 1 1 5 5 8 8 12 15 18, 18 Roller follower with eccenctricity Pitch points

8  /2  /3 1 1 5 5 8 8 12 15 18, 18 Roller follower with eccenctricity Pitch points

9  /2  /3 1 1 5 5 8 8 12 15 18, 18

10  /2  /3 1 1 5 5 8 8 12 15 18, 18


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