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Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3  Objective:  SWBAT perform stoichiometric conversions from mole to mass,

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Presentation on theme: "Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3  Objective:  SWBAT perform stoichiometric conversions from mole to mass,"— Presentation transcript:

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2 Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3  Objective:  SWBAT perform stoichiometric conversions from mole to mass, from mass to mass  Catalyst:  How many basketballs are in a dozen?  How many turkeys are in a dozen?  How was your break? *This week… bring scientific calculators if you have them!

3 Exit Question  What do you need to do to get where you want to be in this class?

4 Agenda  Catalyst/Welcome Back  Test Review/Tracking/Corrections  OMG! YOUR NEW BFFL! The mole.  Bring back the train tracks  Exit Question

5 What is a mole to us chemists?  A benign overgrowth of cells because of a failure in mitosis?  NO! But gross…  A rascly little rodent?  NOOOO!  A TV show featuring celebrities?  NOOOOO!  Then WHAT IS IT?????!!!???!?!?!???!!!!

6 The Mole Think of the term “ a dozen ”… How many donuts are in a dozen? How many eggs are in a dozen?

7 The Mole Just like a dozen refers to 12 objects …

8 The Mole Just like a dozen refers to 12 objects … … the mole refers to …

9 The Mole Just like a dozen refers to 12 objects … … the mole refers to … 6.02 x 10 23 particles

10 The Mole This number is called Avogadro ’ s number … 6.02 x 10 23 602,000,000,000,000,000,000,000

11 Avogadro ’ s Number 1 mol = 6.02 x 10 23 atoms 1 mol = 6.02 x 10 23 molecules Why do YOU think we would do this?

12 Interpreting Equations 4 Fe + 3 O 2  2 Fe 2 O 3 “4 moles of iron react with 3 moles of oxygen gas to produce 2 moles of iron(III) oxide” Coefficients in chemical reactions just refer to how many moles are reacting!

13 Interpreting Equations C 3 H 8 + 5 O 2  3 CO 2 + 4H 2 O “1 mole of propane (C 3 H 8 ) reacts with 5 moles of oxygen gas to produce 3 moles of carbon dioxide and 4 moles of water”

14 How many moles needed? (moles – moles) C 3 H 8 + 5 O 2  3 CO 2 + 4H 2 O If you start with 10.0 moles of propane (C 3 H 8 ), how many moles of oxygen gas is needed to fully combust (react)?

15 How many moles produced? (moles – moles) C 3 H 8 + 5 O 2  3 CO 2 + 4H 2 O If you start with 10.0 moles of propane (C 3 H 8 ), how many moles of carbon dioxide will be produced?

16 What’s the point of all this?  Key Point #1: Stoichiometry relates the amount of REACTANTS with the amount of PRODUCTS.  It all relates back to the mole…  Scientists use stoichiometry to plan reactions!  And guess what else is coming back….

17 TRAIN TRACKS!!!  Step 1:  What to what?  Step 2:  Write conversion factor(s)  Step 3:  Train tracks

18 Avogadro ’ s Number 1 mol = 6.02 x 10 23 atoms How many atoms are in.25 mol N 2 ?

19 Avogadro ’ s Number 1 mol = 6.02 x 10 23 atoms How many atoms are in.25 mol N 2 ?.25 mol N 2

20 Avogadro ’ s Number 1 mol = 6.02 x 10 23 atoms How many atoms are in.25 mol N 2 ?.25 mol N 2 1 mol N 2 6.02 x 10 23 atoms I guess you can use your calculator for this…

21 Your turn! Whiteboards. How many atoms are in 1.1 moles of C 12 H 22 O 11 ?

22 OOOH, I want some more train tracks!  Key Point #2:  Molar mass the amount of grams in the mole of a substance.  But Mr. J, how am I ever going to find out this information?

23 Molar Mass 1 mol C =

24 Molar Mass 1 mol C = 12 g C

25 Molar Mass  The atomic weight of an atom is also the molar mass of that atom.  Carbon has an atomic weight of 12.01.  In 1 mole of carbon, there are 12.01 grams.  In 1 mole of sodium, how many grams are there?

26 Molar Mass 1 mol Na =

27 Molar Mass 1 mol Na = 23 g Na

28 Molar Mass-Can you figure out this one?? 1 mol CO 2 =

29 Molar Mass 1 mol CO 2 = C = 12 gO = 16 gO = 16 g

30 Molar Mass 1 mol CO 2 = C = 12 g+ O = 16 g + O = 16 g

31 Molar Mass 1 mol CO 2 = 44 g CO 2 C = 12 g+ O = 16 g + O = 16 g

32 Molar Mass 1 mol KNO 3 = K = + N = + O =

33 Molar Mass 1 mol KNO 3 = K = 39 g + N = 14 g + (3) O = 16 g

34 Molar Mass 1 mol KNO 3 = 101 g K = 39 g + N = 14 g + (3) O = 16 g

35 Molar Mass- Let’s try a problem 1 mol KNO 3 = 101 g If we have 3.5 moles of KNO 3, how many grams would we have?

36 Molar Mass 1 mol CH 4 = If we have 20 grams CH 4, how many moles of CH 4 do we have?

37 Independent Practice  1, 11, 16… we will go over to show you how to solve this hilarious assignment!  Attach your work on a separate sheet of paper.

38 Exit Question  How many molecules are in a mole of NH 4 ?  How many grams are there in 2.3 moles of NH 4 ?


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