# STOY-KEE-AHM-EH-TREE. It‘s the study of amounts of substances that are involved in reactions.

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STOY-KEE-AHM-EH-TREE. It‘s the study of amounts of substances that are involved in reactions.

Basics of Stoichiometry  Al + O 2 → Al 2 O 3 If the equation is not balanced, the first step is to balance the equation. 4 Al + 3 O 2 → 2 Al 2 O 3

What are the possible ratios in this equation? 4 Al + 3 O 2 → 2 Al 2 O 3 4Al, 3O 2, 4Al, 2Al 2 O 3, 3O 2, 2Al 2 O 3 3O 2 4Al 2Al 2 O 3 4Al 2Al 2 O 3 3O 2

Mole  Mole setup: 4Al + 3O 2 → 2Al 2 O 3 How many moles of aluminum are in 6.40 moles of Aluminum Oxide? Step 1: Determine the ratio needed 4 mol Al or 2 mol Al 2 O 3 2 mol Al 2 O 3 4 mol Al Step 2: Set up the problem using dimensional analysis. 6.40 mol Al 2 O 3 = 12.80 mol Al 4 mol Al 2 mol Al 2 O 3 This is the Ratio determined in step 1. We picked this one because the given was Al 2 O 3 and the bottom compound also had to be Al 2 O 3 to cancel. # moles Given # moles This is the given. It’s the NUMBER given in the problem

Mole to Mole Stoichiometry Assignment Complete this assignment on a separate sheet of paper. Show all work. Consider the balanced equation: 1 C 3 H 8 + 5 O 2 → 3 CO 2 + 4 H 2 O Propane reacts with oxygen to produce carbon dioxide and water. 1. How many moles of water are produced when using 6.50 moles of propane? 2. If 9.1 moles of carbon dioxide are produced, how many moles of oxygen were used? 3. What amount of moles of water are produced when producing 22 moles of carbon dioxide? 4. If 4.25 moles of propane are used, how many moles of oxygen must be used in this reaction? 5. How many moles of carbon dioxide are produced if 38.10 moles of propane are used?

Mole  Mass Setup : 4 Al + 3 O 2 → 2 Al 2 O 3 How many grams of aluminum are in 8.00 moles of oxygen? Step 1: Determine the ratio needed: 4 mol Al or 3 mol O 2 3 mol O 2 4 mol Al 8.00 mol O 2 = g Al 3 mole O 2 4 mole Al 1 mole Al 26.982 g Al 287.81 This is the Ratio determined in step 1 Step 2: Set up the problem This is the molar mass of aluminum 1 mol Al x 26.982 g = 26.982 g/mol mol Given mol mol Molar mass g 1 mol

Mole to Mass Stoichiometry Assignment Complete this assignment on a separate sheet of paper. Show all work. Consider the balanced equation: 1 C 3 H 8 + 5 O 2 → 3 CO 2 + 4 H 2 O Propane reacts with oxygen to produce carbon dioxide and water.  How many grams of oxygen are needed to produce 8.75 moles of carbon dioxide?  What is the mass in grams of water if 25 moles of propane are used?  How many grams of propane are needed to produce 18.20 moles of oxygen?  If 93.45 moles of carbon dioxide were produced in the reaction, how many grams of propane were used?  What is the mass in grams of oxygen if 3.01 moles of water are produced?

Mass  Mole Setup: How many moles of oxygen are in 154.20 g of aluminum oxide? Step 1: Determine the ratio needed. 2 mol Al 2 O 3 or 3 mol O 2 3 mol O 2 2 mol Al 2 O 3 Step 2: Set up the problem 101.961 g Al 2 O 3 1 mol Al 2 O 3 2 mol Al 2 O 3 3 mol O 2 = 2.27 mol O 2 This is the Ratio determined in step 1 This is the molar mass of Al 2 O 3 2 mol Al x 26.982 g = 53.964 g 3 mol O x 15.999 g = 47.997 g 101.961 g/mol Given (g) 1 mol Molar mass (g) mol 154.20 g Al 2 O 3

Mass to Mole Stoichiometry Assignment Complete this assignment on a separate sheet of paper. Show all work. Consider the balanced equation: 1 C 3 H 8 + 5 O 2 → 3 CO 2 + 4 H 2 O Propane reacts with oxygen to produce carbon dioxide and water.  How many moles of oxygen are needed to produce 125.50 g of carbon dioxide?  How many moles of water are produced if 218.15 g of propane are used?  How many moles of propane are needed to produce 70 g of oxygen?  If 300 g of carbon dioxide were produced in the reaction, how many moles of propane were used?  How many moles of oxygen are needed if 38.75 g of water are produced?

Mass  Mass How many grams of oxygen are in 54 g of aluminum? Step 1: Determine the ratio needed. 4 mol Al or 3 mol O 2 3 mol O 2 4 mol Al Step 2: Set up the problem ` 54 g Al 1 mol Al3 mol O 2 31.998 g O 2 = 26.982 g Al 4 mol Al 1 mol O 2 48.03 g O 2 This is the Ratio determined in step 1 Given (g) 1 mol Molar mass (g) mol Molar mass (g) 1 mol This is the molar mass of aluminum 1 mol Al x 26.982 g = 26.982 g/mol This is the molar mass of O 2 2 mol O x 15.999 g = 31.998 g/mol

Mass to Mass Stoichiometry Assignment Complete this assignment on a separate sheet of paper. Show all work. Consider the balanced equation: 1 C 3 H 8 + 5 O 2 → 3 CO 2 + 4 H 2 O Propane reacts with oxygen to produce carbon dioxide and water. 1. How many grams of water are produced when using 200 g of propane? 2. If 59.39 g of carbon dioxide are produced, how many grams of oxygen were used? 3. What mass in grams of water are produced when producing 145.00 g of carbon dioxide? 4. If 499 g of propane are used, how many grams of oxygen must be used in this reaction? 5. How many grams of carbon dioxide are produced if 84.30 g of propane are used?

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