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Ideal Gas Law PV=nRT.

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Presentation on theme: "Ideal Gas Law PV=nRT."— Presentation transcript:

1 Ideal Gas Law PV=nRT

2 Remember… Boyle’s Law Charles’ Law:
Combined Gas Law: (Units MUST Match Temp in Kelvin!!!)

3 A gas with a volume of 350 ml is collected at 15o C and 120 kPa
A gas with a volume of 350 ml is collected at 15o C and 120 kPa. If the temperature changes to 30o C, what pressure would be required to put this gas in a 300 ml container?

4 A balloon has a volume of 500 ml at a temperature of 22oC and a pressure of 755 mmHg. If the balloon is cooled to 0o C and a pressure of 145 mmHg, what is its new volume?

5 Avogadro’s Principle Under similar conditions (same Temp and Pressure) equal volumes of gases contain equal numbers of particles. 10 L of H2 (g) and 10 L of O2 (g) Both at Standard Temperature and Pressure (STP) contain… The same number of particles!

6 The volume of 1 mole of gas particles
Molar Volume The volume of 1 mole of gas particles at STP is 22.4 L

7 Ideal Gas Law Animation:

8 Try this: 1 mole of gas occupies 22.4 L at STP = __________ ml (22400)
= ___________ moles of gas (1 mole) = ___________ particles (6.02 x 1023)

9 How many particles in 11.2 dm3 of gas at STP?
0.5 moles = 3.01 x 1023 particles 22,400 cm3 of NH3 gas at STP weighs? = 22.4 L = 1 mole = 17 grams (add up MW) 44.8 L of NH3 at STP weighs? = 2 moles = 34 grams _____ grams = 1 mole of nitrogen gas = _____ L at STP? 28.00 22.4

10 How many N2 molecules are in 22.4 dm3 at STP?
= 1 mole = 6.02 x 1023 What volume will 1.2 x 1024 H2 molecules occupy at STP? = 2 moles = 44.8 L at STP

11 Ideal Gas Equation Use when NOT at STP!!!
PV= nRT P = Pressure (in kPa) V = Volume (in Liters or dm3) n = number of moles T = Temperature (in Kelvin) R = L• kPa mole • K

12 Development of R in

13 1. What volume will 2 moles of NO2 occupy at 300 Kelvin and 90 kPa?

14 What will be the temp of 2 grams of H2 if 5000 cm3 is at 5 atm?

15 Finding Molecular Weight of a Gas
Remember: MW = grams / moles Converting grams to moles Divide grams by the molecular weight

16 PV=nRT 92kPa • 5.0 L= n • 8.31 • 293 K n = 0.19 mol
1) 5.0 L of a gas weighs g at 20o C & 92 kPa. What is the mole weight of the gas? PV=nRT 92kPa • 5.0 L= n • 8.31 • 293 K n = 0.19 mol

17 2)If the mole weight of a gas is 26 g/mol and 18
2)If the mole weight of a gas is 26 g/mol and g of the gas is 30 L at 21o C, what is the pressure of the gas? PV= nRT P x 30 L=0.69 mol x 8.31 x 294 K P = 56.2kPa

18 Stoichiometry Solving Steps. Balance the Equation
Change grams to moles Use mole ratio to solve Change moles to volumes

19 Use mole ratio (coefficients) Use MW on P.T. Use 22.4 L/mol
@ STP Or PV = nRT Use 22.4 L/mol @ STP Or PV = nRT Use MW on P.T.

20 Mg (c) + HCl (ag)  MgCl2 + H2 (g)
If 2.43 g Mg react what volume of H2 is produced? (at STP) 1:1 0.1 mole 0.1 moles Mg (c) HCl (ag)  MgCl2 + H2 (g) 2 ? L 2.24 L H2 2.43 g Mg

21 Mg (c) +2 HCl (ag)  MgCl2 + H2 (g)
If 2.43 g Mg react what volume of H2 is produced at 40oC and 85 kPa? 1:1 0.1 mole 0.1 moles Mg (c) HCl (ag)  MgCl2 + H2 (g) 2 ? L 3.06 L H2 2.43 g Mg

22 Mg (c) + HCl (ag)  MgCl2 + H2 (g)
If 250 ml of H2 is produced at 20o C & 100 kPa, what mass of Mg reacted? 1:1 0.01 mole 0.01 moles Mg (c) HCl (ag)  MgCl2 + H2 (g) 2 0.243 g Mg ? g 250 ml

23 Volume to Volume THE MOLE RATIO IS THE SAME AS THE VOLUME RATIO.
Liters B Use mole ratio (coefficients) Liters A

24 What vol. of oxygen is needed to completely burn 1 L of methane?
Burning of methane: What vol. of oxygen is needed to completely burn 1 L of methane? 1:2 1.0 L 2.0 L CH O2  CO2 (g) H2O (l) 2 2

25 To produce 11.2 L of CO2 requires how many moles of O2 at STP?
Burning of methane: To produce 11.2 L of CO2 requires how many moles of O2 at STP? 2:1 1 mole = 22.4 L 11.2 L CH O2  CO2 (g) H2O (l) 2 2


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