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Warm Up –. 7.3 – Similar Figures Similar Polygons – Two polygons are similar if their vertices can be paired so that: 1. Corresponding angles are congruent.

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Presentation on theme: "Warm Up –. 7.3 – Similar Figures Similar Polygons – Two polygons are similar if their vertices can be paired so that: 1. Corresponding angles are congruent."— Presentation transcript:

1 Warm Up –

2 7.3 – Similar Figures Similar Polygons – Two polygons are similar if their vertices can be paired so that: 1. Corresponding angles are congruent. 2. Corresponding sides are in proportion. Symbol for Similar: ~

3 P T S R Q V Z Y X W Example: 7.3 – Similar Figures Therefore – 1.  P   T   S    R   Q   2. Pent. TSRQP ~ Pent. ZYXWV VZY X W WXXYYZZV

4 When two polygons are similar, then the ratio of the lengths of two corresponding sides is called the Scale Factor. 7.3 – Similar Figures

5 B Example 1: A C KL J 21 18 12 76 4 To determine the scale factor – match up the lengths of the corresponding sides. Reduce ratios. Scale factor of  ABC to  JKL is 3 to 1.  ABC ~  JKL ORDER MATTERS!

6 Example 2: 7.3 – Similar Figures A D C B E H G F 20 30 8 z y 10 x Quad. ______ ~ Quad. ______ 1. If m  D = 92, then m  H = ____. 2. If m  C = 60, then m  G = ____. ABCDEFGH 92 60

7 A D C B E H G F 20 30 8 z y 10 21 x Example 2: Once you determine the scale factor, you can calculate the lengths of all of the sides of the similar figures. 7.3 – Similar Figures Scale factor of ABCD to EFGH is 2 to 3.

8 7.3 – Similar Figures Example 2 continued: A D C B E H G F 20 30 8 z y 10 21 x Use the scale factor of 2 to 3 to set up proportions. x = _____ y = _____ z = _____ 14 15 12 42 = 3x; x = 14 30 = 2y; y= 15 24 = 2z; z = 12

9 Example 3 – Find the missing side lengths and angle measures. A C E F B D  ABC ~ Scale Factor: = x: y: 15 9 6 y x 5 122  23  35  23  35  zz  FDE 15 to 9 5 to 3 x = 10 y = 3 zz

10 Example 4: Name all of the pairs of congruent angles. a.  IKJ ~ b. Find x. c. Find y. J I K L H y 6 9 15 12 x  HLJ  JIK   JHL;  JKI   JLH 6 9 12 6 + y x 24 3 8


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