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Gases & Atmospheric Chemistry Charles’ & Gay-Lussac’s Gas Laws Unit 5.

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Presentation on theme: "Gases & Atmospheric Chemistry Charles’ & Gay-Lussac’s Gas Laws Unit 5."— Presentation transcript:

1 Gases & Atmospheric Chemistry Charles’ & Gay-Lussac’s Gas Laws Unit 5

2 Review  What is the relationship between pressure and volume?  Can you tell me the name of the Law for this phenomenon?  Who can come and write the Law on the board?  Let’s Practice!

3 Kelvin Temperature Scale  Absolute Zero = believed to be the lowest possible temperature  Temperature at which a volume of gas would be zero  = -273ºC  0 K = - 273 o C ( -273.15 o C to be more precise)  Kelvin Temperature Scale = a temperature scale with zero kelvin (0 K) at absolute zero and the same size divisions as the Celsius temperature scale Lord Kelvin used Charles’ Law to determine this

4 Kelvin Scale To convert: e.g. 1. Convert to Kelvin scale a) 25 o Cb) - 58 o C 2. Convert to Celsius scale a) 475 Kb) 17 K T K = T oC + 273 100 0 C 0 0 C -273 0 C 373 K 273 K 0 K

5 Absolute Zero  As temperature decreases the volume of a gas decreases (or the pressure drops, if you keep the volume the same)  We can deduce how cold you would have to make the gas, in order for the volume to be zero (-273°C or 0K)  A gas cannot have a zero volume therefore absolute zero is an unattainable limit

6 Relationship: Volume & Temp. Regardless of gas, V = 0 when T= - 273 o C

7 Charles’s Law Relationship: Volume & Temp.  As temperature increases volume increases V  T (direct proportion)

8 As temperature increases volume increases

9 Charles’s Law Relationship: Volume & Temp.  Charles’s Law = the volume of a gas varies directly with its temperature in kelvin, if the pressure and the amount of gas are constant v = kT  v = volume (L)  T = Temperature in Kelvin (K)  k = constant (slope of the straight line in the graph)

10 Charles’s Law Relationship: Volume & Temp.  Charles’s Law can be written comparing any two sets of volumes and temperatures:  k = v 1 /T 1 and k = v 2 /T 2  Therefore: v 1 /T 1 = v 2 /T 2 (Charles’s Law)

11 Charles’ Law Sample Problems: 1. 75 mL of dry hydrogen gas at 22 o C is drawn into a syringe. If the temperature is raised to 125 o C, keeping the pressure constant, what volume will this same mass of hydrogen gas occupy? (ans: 1.0 x 10 2 mL) 2. A balloon filled with dry He (g) has a volume of 3.75 L at 25 o C. The same balloon is placed in a freezer and the volume of the balloon now is 3.05 L. Calculate the temperature (in o C) of the freezer. (ans: -31 o C)

12 Practical Applications  Should you throw an aerosol can into a fire? What could happen?  When should your automobile tire pressure be checked?

13 Gay-Lussac’s Law Relationship: Pressure & Temp. Graphically: P  T (direct proportion)

14 Gay-Lussac’s Law Relationship: Pressure & Temp.

15  Pressure & Temperature Law = the pressure exerted by a gas varies directly with the absolute temperature if the volume and the amount of gas remain constant p 1 /T 1 = p 2 /T 2

16 Gay-Lussac’s Law Sample Problems: 1. Assuming that room temperature is 22 o C, to what temperature must a given mass of gas be raised such that its pressure is doubled? (ans: 317 o C) 2. The pressure gauge reading on a cylinder of oxygen gas is 8.5x10 3 kPa, at 22 o C. What will be the pressure if the cylinder is placed in boiling water? (ans: 1.1 x 10 4 kPa)

17 Summary Boyle’s Law (P i V i =P f V f ) o P ↑ V ↓ or P ↓ V ↑ Charles Law (V i /T i =V f /T f ) o V ↑ T ↑ or V ↓ T ↓ Gay-Lussac’s Law (P i /T i =P f /T f ) o P ↑ T ↑ or T ↓ T ↓ Eventually leads to combined gas law o (P i V i /T i =P f V f /T f ) next chapter.


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