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4.1b Notes – Calculations using Net force and Newton’s 2 nd Law.

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Presentation on theme: "4.1b Notes – Calculations using Net force and Newton’s 2 nd Law."— Presentation transcript:

1 4.1b Notes – Calculations using Net force and Newton’s 2 nd Law

2 Objectives Interpret motion diagrams Apply Newton’s Second Law of Motion to real life situations. Solve calculation problems using Newton’s Second Law of Motion.

3 Calculating Net Force Draw the picture in your notes How do we calculate net force?

4 Net Force = __________ Example

5 Net Force = _________ Examples

6 Net Force = __________ Examples

7 Newton’s 2 nd Law Calculations F = ma Determine the acceleration that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object. A 3-kg object experiences an acceleration of 4 m/s/s. A 6-kg object experiences an acceleration of 2 m/s/s.

8 Newton’s 2 nd Law Calculations F = ma A net force of 15 N is exerted on an encyclopedia to cause it to accelerate at a rate of 5 m/s 2. Determine the mass of the encyclopedia. F net = 15 N a = 5 m/s/s. m = F/a m = (15 N) / (5 m/s/s) m = 3.0 kg

9 Example Find the acceleration of a 10kg object undergoing the motion indicated in the diagram. Step 1 – find the net force Step 2 - use F=ma equation

10 Newton’s 2 nd Law Calculations F = ma Suppose that a sled is accelerating at a rate of 2 m/s 2. If the net force is tripled and the mass is doubled, then what is the new acceleration of the sled? Answer: 3 m/s/s The original value of 2 m/s/s must be multiplied by 3 (since a and F are directly proportional) and divided by 2 (since a and m are inversely proportional)

11 Newton’s 2 nd Law Calculations F = ma Suppose that a sled is accelerating at a rate of 2 m/s 2. If the net force is tripled and the mass is halved, then what is the new acceleration of the sled? Answer: 12 m/s/s The original value of 2 m/s/s must be multiplied by 3 (since a and F are directly proportional) and divided by 1/2 (since a and m are inversely proportional)

12 In-Class Assignment/Homework 4.1 b WKT


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